题目内容
已知
,如果
,求
的取值
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345004630.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345035458.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345051192.gif)
解1°若a=0 则A={-} 满足A∩R+=![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345082213.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/2014082319134509881.gif)
2°若a≠0时
(1)△=4+4 a<0时即a<-1 A=
满足A∩R+=![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345082213.gif)
(2)△≥0即a≥-1要
A∩R+=
只须![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345378170.gif)
△≥0 a≥-1
<0
a<0
-1≤a<0
-
>0 a<0
综上所述a的取值范围为 {a a≤0}
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345082213.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/2014082319134509881.gif)
2°若a≠0时
(1)△=4+4 a<0时即a<-1 A=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345082213.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345082213.gif)
(2)△≥0即a≥-1要
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/2014082319134534772.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345082213.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345378170.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345394171.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345410227.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345425164.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345425164.gif)
-
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823191345456230.gif)
综上所述a的取值范围为 {a a≤0}
略
![](http://thumb.zyjl.cn/images/loading.gif)
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