题目内容
若α是钝角,且

【答案】分析:首先利用同角正余弦关系式sin2α+cos2α=1求出cosα,然后根据余弦的和角公式把cos(
)展开,最后把特殊角三角函数值与已知数值代入即可.
解答:解:因为sinα=
,且α是钝角,
所以cosα=-
=-
,
所以cos(
)=
=
=
.
故答案为
.
点评:本题主要考查同角正余弦关系式与余弦的和角公式

解答:解:因为sinα=

所以cosα=-


所以cos(


=

=

故答案为

点评:本题主要考查同角正余弦关系式与余弦的和角公式

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