题目内容
已知定点A(0,1),点B在直线x+y=0上运动,当线段AB最短时,点B的坐标是___________________.
(-
,
)
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本题考查两点间的距离公式、求最值和点到直线的距离等,以及基本的运算技能,本题大致有两种做法:
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解法一:代数法,根据两点间的距离公式建立一个函数关系,即|AB|2=(x-0)2+(y-1)2,又y=x,则|AB|2=x2+(x+1)2=2x2+2x+1,转化为二次函数求最值,可见当x=-
时,|AB|2最小为
,∴|AB|?≥
,∴B(-
,
);
解法二:几何法,直线上的点B与A点的连线中当AB与x+
y=0垂直时,AB最短,∴AB:y=x+1,∴B点为
的交点为(-
,
).
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解法一:代数法,根据两点间的距离公式建立一个函数关系,即|AB|2=(x-0)2+(y-1)2,又y=x,则|AB|2=x2+(x+1)2=2x2+2x+1,转化为二次函数求最值,可见当x=-
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解法二:几何法,直线上的点B与A点的连线中当AB与x+
y=0垂直时,AB最短,∴AB:y=x+1,∴B点为
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