题目内容
已知

【答案】分析:先利用基本不等式求出当m•n取得最小值时m和n 的值,从而得到椭圆的标准方程,由方程求得椭圆的离心率.
解答:解:∵已知
,则 1≥2
,∴mn≥8,当且仅当 m=2,n=4时,等号成立.
此时,椭圆的方程为
+
=1,a=4,b=2,c=2
,∴e=
=
,
故答案为:
.
点评:本题考查基本不等式的应用,椭圆的简单性质的应用.
解答:解:∵已知


此时,椭圆的方程为





故答案为:

点评:本题考查基本不等式的应用,椭圆的简单性质的应用.

练习册系列答案
相关题目