题目内容

AM |
c |
AN |
b |
AB |
c |
b |
-
+
2 |
3 |
c |
4 |
3 |
b |
-
+
.2 |
3 |
c |
4 |
3 |
b |
分析:由向量的运算法则,可得
=
+
-
,由方程的思想可得
AB |
AN |
1 |
4 |
AB |
1 |
2 |
AM |
AB |
解答:解:由题意可得
=
+
=
+
=
+
=
+
(
+
)
=
+
-
故可得
=
-
=
-
解得
=-
+
故答案为:-
+
AB |
AN |
NB |
=
AN |
1 |
2 |
CB |
AN |
1 |
2 |
DA |
=
AN |
1 |
2 |
DM |
MA |
=
AN |
1 |
4 |
AB |
1 |
2 |
AM |
故可得
3 |
4 |
AB |
AN |
1 |
2 |
AM |
b |
1 |
2 |
c |
解得
AB |
2 |
3 |
c |
4 |
3 |
b |
故答案为:-
2 |
3 |
c |
4 |
3 |
b |
点评:本题考查向量的加减法和几何意义,涉及方程的思想,属基础题.

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