题目内容
非零向量
=(sinθ,2),
=(cosθ,1),若
与
共线,则tan(θ-
)=
- A.3
- B.-3
- C.
- D.-
C
分析:根据题意,有
∥
,根据向量平行的充要条件,构造方程,解方程即可得到答案.
解答:∵
与
共线,
∴sinθ-2cosθ=0
即tanα=2,
则tan(θ-
)=
=
故选C.
点评:本题考查的知识点是向量平行的坐标运算:
,则
?x1•y2-x2y1=0
分析:根据题意,有


解答:∵


∴sinθ-2cosθ=0
即tanα=2,
则tan(θ-



故选C.
点评:本题考查的知识点是向量平行的坐标运算:



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