题目内容
设函数![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_ST/0.png)
【答案】分析:根据连续的定义得到x→0时函数的极限等于f(0)即a,求出极限即可得到a的值.
解答:解:因为f(x)在x=0处连续,所以
f(x)=![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/1.png)
=f(0)=a
而
=
=
=
,所以a=
.
故答案为:![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/8.png)
点评:考查学生掌握函数连续的定义,会求函数的极限.
解答:解:因为f(x)在x=0处连续,所以
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/1.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/2.png)
而
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/3.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/4.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/5.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/6.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/7.png)
故答案为:
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131023213339069038020/SYS201310232133390690380013_DA/8.png)
点评:考查学生掌握函数连续的定义,会求函数的极限.
![](http://thumb.zyjl.cn/images/loading.gif)
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