题目内容
若向量

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A.

B.2
C.4-2

D.6
【答案】分析:由已知中向量
的夹角为120°,
,根据平面向量的数量积的运算,我们易求出
及
的值,代入
即可得到答案.
解答:解:∵
,向量
的夹角为120°
∴
=4,
=
=-2
故
=
-
=4-(-2)=6
故选:D
点评:本题考查的知识点是平面向量的数量积的运算,根据已知条件结合平面向量的数量积,求出
及
的值是解答本题的关键.






解答:解:∵


∴



故




故选:D
点评:本题考查的知识点是平面向量的数量积的运算,根据已知条件结合平面向量的数量积,求出



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