题目内容
执行如图所示的程序框图,若输入
,则输出
的值是____________。




0
解:将x=0.1代入得:m=lg(0.1)=-1,
∵m=-1<0不满足m>0,
∴从“否”这一出口走,
∵m=-1,
∴m+1=0,
∴将m+1=0重新赋与m,则m的值变为0,
∴输出m的值为0.
∵m=-1<0不满足m>0,
∴从“否”这一出口走,
∵m=-1,
∴m+1=0,
∴将m+1=0重新赋与m,则m的值变为0,
∴输出m的值为0.

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