题目内容
已知函数![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_ST/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_ST/1.png)
A.9
B.
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_ST/2.png)
C.-9
D.-
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_ST/3.png)
【答案】分析:首先判断自变量是属于哪个区间,再代入相应的解析式,进而求出答案.
解答:解:∵
,∴
=
=-2,
而-2<0,∴f(-2)=3-2=
.
∴
=
.
故选B.
点评:正确理解分段函数在定义域的不同区间的解析式不同是解题的关键.
解答:解:∵
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_DA/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_DA/1.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_DA/2.png)
而-2<0,∴f(-2)=3-2=
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_DA/3.png)
∴
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_DA/4.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131103103734772935666/SYS201311031037347729356007_DA/5.png)
故选B.
点评:正确理解分段函数在定义域的不同区间的解析式不同是解题的关键.
![](http://thumb.zyjl.cn/images/loading.gif)
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