题目内容
(文)与双曲线

A.

B.

C.

D.

【答案】分析:设所求双曲线为
(λ≠0),把点(-3,4
)代入,求出λ,从而得到双曲线的方程.
解答:解:设所求双曲线为
(λ≠0),
把点(-3,
)代入,得
,
解得λ=-1,
∴所示的双曲线方程为
.
故选A.
点评:本题考查双曲线的性质和应用,解题时要注意待定系数法的合理运用.


解答:解:设所求双曲线为

把点(-3,


解得λ=-1,
∴所示的双曲线方程为

故选A.
点评:本题考查双曲线的性质和应用,解题时要注意待定系数法的合理运用.

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