题目内容
已知集合U = {(x,y)| xÎR, y ÎR}, M = {(x,y) | |x | + | y | < a },P = {(x,y)| y = f (x ) },现给出下列函数: ①y = ax , ② y = logax , ③y = sin(x + a), ④y = cos a x,若0 < a < 1时,恒有P∩CUM = P,则f (x)可以取的函数有
A.①②③ B. ①②④ C. ①③④ D . ②③④
B
【解析】∵∁uM={(x,y)||x|+|y|≥a},0<a<1时,P∩∁uM=P,∴P={(x,y)y=f(x)}⊆∁uM,如图所示:结合图形可得满足条件的函数图象应位于曲线|x|+|y|=a(-a≤x≤a )的上方.
①中,x∈R,y>0,满足|x|+|y|≥a,故①可取.
②中,x>0,y=logax∈R,满足||x|+|y|≥a,故②可取.
③中的函数不满足条件,如 x=0,时,
,不满足|x|+|y|≥a.
④中x∈R,-1≤y≤1,满足|x|+|y|≥a,故④可取.