题目内容
为提高信息在传输中的抗干扰能力,通常在原信息中按一定规则加入相关数据组成传输信息.设定原信息为









A.11010 B.01100 C.10111 D.00011
C解析:假设传输信息为“10111”,那么h0,a0,a1,a2,h1的取值分别为这5个数“1,0,1,1,1”,据题目条件必有h0=a0a1=0
1=1;h1=h0
a2=|
|=0,此时与“h1=1”相矛盾.故此信息是错误的.

练习册系列答案
相关题目
题目内容
为提高信息在传输中的抗干扰能力,通常在原信息中按一定规则加入相关数据组成传输信息.设定原信息为A.11010 B.01100 C.10111 D.00011
C解析:假设传输信息为“10111”,那么h0,a0,a1,a2,h1的取值分别为这5个数“1,0,1,1,1”,据题目条件必有h0=a0a1=0
1=1;h1=h0
a2=|
|=0,此时与“h1=1”相矛盾.故此信息是错误的.