题目内容

(本小题满分16分,每小题8分)
求下列函数的值域:(1) ;(2)

(1)
(2)


即值域为……………………………………………………………8分
(2) 解:
,则y=t2-3t+2,·························································· 2分
x∈[-2,2],∴,················································ 4分
,····································································· 5分
时,,当t=4时,ymax=6,
········································································· 8分
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