题目内容

计算下列定积分的值
(1)
3-1
(4x-x2)dx

(2)
21
(x-1)5dx

(3)
π
2
0
(x+sinx)dx

(4)
π
2
-
π
2
cos2xdx
(1)
3-1
(4x-x2)dx
=(2x2-
x3
3
)
|3-1
=
20
3

(2)∵(
(x-1)6
6
)
=(x-1)5,∴
21
(x-1)5dx
=
(x-1)6
6
|21
=
1
6

(3)
π
2
0
(x+sinx)dx
=(
x2
2
-cosx)
|
π
2
0
=
π2
8
+1

(4)
π
2
-
π
2
cos2xdx
=
π
2
-
π
2
1+cos2x
2
dx
=(
x
2
+
sin2x
4
)
|
π
2
-
π
2
=
π
2
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