题目内容
已知平面向量
A.9
B.1
C.-1
D.-9
【答案】分析:利用两个向量共线时,它们的坐标间的关系,建立等式,解方程求得 x值.
解答:解:∵
,∴
=λ
,
∴(3,1)=(xλ,-3λ ),
∴xλ=3,-3λ=1,
∴x=-9,
故选 D.
点评:本题考查两个向量共线的性质,两个向量
、
共线时,
=λ
.
解答:解:∵
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
∴(3,1)=(xλ,-3λ ),
∴xλ=3,-3λ=1,
∴x=-9,
故选 D.
点评:本题考查两个向量共线的性质,两个向量
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


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