题目内容

已知的展开式中没有常数项,,且2≤n≤8,则n=______.

:  5


解析:

: 当n=2时,(x+的展开式中有,结论不成立;当n=3时,(x+的展开式中有1,结论不成立;当n=4时,(x+的展开式中有常数项,结论不成立;当n=5时,(x+的展开式中x的次数依次是5,1,-3,-7,-11,-15,结论成立.                                                                                                                                                                                                                      

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