题目内容
长度都为2的向量
,
的夹角为
,点C在以O为圆心的圆弧AB(劣弧)上,
=m
+n
,则m+n的最大值是________.
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建立平面直角坐标系,设向量
=(2,0),向量
=(1,
).设向量
=(2cos α,2sin α),0≤α≤
.由
=m
+n
,得(2cos α,2sin α)=(2m+n,
n),
即2cos α=2m+n,2sin α=
n,
解得m=cos α-
sin α,n=
sin α.
故m+n=cos α+
sin α=
sin
≤
.
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即2cos α=2m+n,2sin α=
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解得m=cos α-
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故m+n=cos α+
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