题目内容
已知向量
,
,若
与
垂直,则
的值为 ( )
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165819964574.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165819979655.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165819995300.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820089504.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820120346.png)
A.![]() | B.![]() | C.![]() | D.1 |
C
根据向量坐标运算的公式,结合
=(1,3),
=(-2,m),可得向量
+2
的坐标.再根据向量
与
+2
互相垂直,得到它们的数量积等于0,利用两个向量数量积的坐标表达式列方程,解之可得m的值.
解∵
=(1,3),
=(-2,m)
∴向量
+2
=(1-4,3+2m)=(-3,3+2m)
又∵向量
与
+2
互相垂直,
∴
(
+2
)=1×(-3)+3(3+2m)=0
∴-3+9+6m=0?m=-1
故选C
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
解∵
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
∴向量
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
又∵向量
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820276280.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823165820416287.png)
∴-3+9+6m=0?m=-1
故选C
![](http://thumb.zyjl.cn/images/loading.gif)
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