题目内容
设函数

A.

B.

C.

D.18
【答案】分析:将变量x按分段函数的范围分成两种情形,在此条件下分别进行求解,先求f(2),最后将满足的条件再代入求解即可.
解答:解:当x=2时,
f(2)=22+2-2=4,
∴
=
故选A.
点评:本题考查了分段函数中已知自变量求函数的值问题,解答关键是对于分段函数的求值要分段考虑,属于常规题.
解答:解:当x=2时,
f(2)=22+2-2=4,
∴


故选A.
点评:本题考查了分段函数中已知自变量求函数的值问题,解答关键是对于分段函数的求值要分段考虑,属于常规题.

练习册系列答案
相关题目