ÌâÄ¿ÄÚÈÝ
ÎÒ¹úÖпÆÔºÉϺ£Éú»¯ËùÓÚ1982Äê5ÔºϳÉÁËÒ»ÖÖ¾ßÓÐÕòÍ´×÷ÓöøÓÖ²»»áÏñÂð·ÈÄÇÑùʹ²¡ÈËÉÏñ«µÄÒ©Îï--ÄÔ·ÈëÄ£¬ÉÏÃæÊÇËüµÄ½á¹¹¼òʽ£®Çë¸ù¾Ý´Ë»¯ºÏÎïµÄ½á¹¹·ÖÎö»Ø´ð£º

£¨1£©¸ÃÎïÖʵĻ¯Ñ§Ãû³ÆÊÇ £®
£¨2£©Èô½«¸ÃÎïÖÊÍêȫˮ½â£¬ÐèҪˮ·Ö×Ó ¸ö£¬Ë®½âºóµÄ²úÎïÓÐ ÖÖ£®
£¨3£©¸Ã»¯ºÏÎï¿ÉÓà ÊÔ¼Á¼ø¶¨£¬³ÊÏÖ É«£¬ÆäÔÒòÊǸû¯ºÏÎïÖк¬ÓÐµÄ Óë¸ÃÊÔ¼Á·¢ÉúÁËÑÕÉ«·´Ó¦£®Ê¹ÓÃÊÔ¼ÁʱµÄ·½·¨ÊÇ £®
£¨1£©¸ÃÎïÖʵĻ¯Ñ§Ãû³ÆÊÇ
£¨2£©Èô½«¸ÃÎïÖÊÍêȫˮ½â£¬ÐèҪˮ·Ö×Ó
£¨3£©¸Ã»¯ºÏÎï¿ÉÓÃ
¿¼µã£ºµ°°×Öʵĺϳɡª¡ª°±»ùËáÍÑË®ËõºÏ
רÌ⣺
·ÖÎö£º1¡¢·ÖÎöÌâͼ£ºÍ¼Ê¾ÎªÄÔ·ÈëĵĽṹʽ£¬¸Ã·Ö×ÓÊÇÓÉ5¸ö°±»ùËá·Ö×ÓÍÑË®ËõºÏÐγɵ쬳ÆÎªÎåëÄ£¬Ò²³ÆÎª¶àëÄ£®×é³ÉÂð·È·Ö×ÓµÄ5¸ö°±»ùËáµÄR»ùÍÅÒÀ´ÎÊÇ-CH2-C6H4OH¡¢-H¡¢-H¡¢-CH2-C6H5¡¢-CH2-CH£¨CH3£©£®
2¡¢¼ø¶¨µ°°×Öʵķ½·¨ÊÇ£ºË«ËõëåÊÔ¼ÁʹÓÃʱ£¬ÏȼÓÈëNaOHÈÜÒº£¨2mL£©£¬Õñµ´Ò¡ÔÈ£¬Ôì³É¼îÐԵķ´Ó¦»·¾³£¬È»ºóÔÙ¼ÓÈë3¡«4µÎCuSO4ÈÜÒº£¬Õñµ´Ò¡ÔȺó¹Û²ìÏÖÏ󣮣¨²»¼ÓÈÈ£©£®
2¡¢¼ø¶¨µ°°×Öʵķ½·¨ÊÇ£ºË«ËõëåÊÔ¼ÁʹÓÃʱ£¬ÏȼÓÈëNaOHÈÜÒº£¨2mL£©£¬Õñµ´Ò¡ÔÈ£¬Ôì³É¼îÐԵķ´Ó¦»·¾³£¬È»ºóÔÙ¼ÓÈë3¡«4µÎCuSO4ÈÜÒº£¬Õñµ´Ò¡ÔȺó¹Û²ìÏÖÏ󣮣¨²»¼ÓÈÈ£©£®
½â´ð£º
½â£º£¨1£©ÓÉÒÔÉÏ·ÖÎö¿ÉÖª£¬ÄÔ·ÈëÄÊÇÓÉ5¸ö°±»ùËá·Ö×ÓÍÑË®ËõºÏÐγɵ쬳ÆÎªÎåëÄ£®
£¨2£©ÄÔ·ÈëÄÊÇÓÉ5¸ö°±»ùËá¾¥ÍÑË®ËõºÏÐγɵģ¬ËùÒÔ¸ÃÎïÖÊÍêȫˮ½âʱ£¬ÐèÒª4¸öË®·Ö×Ó£®ÓÉÒÔÉÏ·ÖÎö¿ÉÖª£¬×é³ÉÄÔ·ÈëĵÄ5¸ö°±»ùËáµÄR»ùÒÀ´ÎÊÇ-CH2-C6H4OH¡¢-H¡¢-H¡¢-CH2-C6H5¡¢-CH2-CH£¨CH3£©£¬Óɴ˿ɼû£¬×é³ÉÄÔ·Èëĵݱ»ùËáµÄR»ùÓÐ4ÖÖ£®
£¨3£©¸Ã»¯ºÏÎï¿ÉÓÃË«ËõëåÊÔ¼Á¼ø¶¨£¬³ÊÏÖ×ÏÉ«£¬ÆäÔÒòÊǸû¯ºÏÎïÖк¬ÓеÄëļüÓë¸ÃÊÔ¼Á·¢ÉúÁËÑÕÉ«·´Ó¦£®Ê¹ÓÃÊÔ¼ÁʱµÄ·½·¨ÊÇÏȼÓË«ËõëåÊÔ¼ÁAÒº£¨»ò0.1g/mlNaOH£©£¬Ò¡ÔÈ£¬ÔÙ¼Ó¡¢Ë«ËõëåÊÔ¼ÁBÒº£¨»ò0.01g/mlCuSO4£©£®
¹Ê´ð°¸Îª£º
£¨1£©ÎåëÄ
£¨2£©4 4
£¨3£©Ë«Ëõëå ×Ï ëļü ÏȼÓË«ËõëåÊÔ¼ÁAÒº£¨»ò0.1g/mlNaOH£©£¬Ò¡ÔÈ£¬ÔÙ¼Ó¡¢Ë«ËõëåÊÔ¼ÁBÒº£¨»ò0.01g/mlCuSO4£©
£¨2£©ÄÔ·ÈëÄÊÇÓÉ5¸ö°±»ùËá¾¥ÍÑË®ËõºÏÐγɵģ¬ËùÒÔ¸ÃÎïÖÊÍêȫˮ½âʱ£¬ÐèÒª4¸öË®·Ö×Ó£®ÓÉÒÔÉÏ·ÖÎö¿ÉÖª£¬×é³ÉÄÔ·ÈëĵÄ5¸ö°±»ùËáµÄR»ùÒÀ´ÎÊÇ-CH2-C6H4OH¡¢-H¡¢-H¡¢-CH2-C6H5¡¢-CH2-CH£¨CH3£©£¬Óɴ˿ɼû£¬×é³ÉÄÔ·Èëĵݱ»ùËáµÄR»ùÓÐ4ÖÖ£®
£¨3£©¸Ã»¯ºÏÎï¿ÉÓÃË«ËõëåÊÔ¼Á¼ø¶¨£¬³ÊÏÖ×ÏÉ«£¬ÆäÔÒòÊǸû¯ºÏÎïÖк¬ÓеÄëļüÓë¸ÃÊÔ¼Á·¢ÉúÁËÑÕÉ«·´Ó¦£®Ê¹ÓÃÊÔ¼ÁʱµÄ·½·¨ÊÇÏȼÓË«ËõëåÊÔ¼ÁAÒº£¨»ò0.1g/mlNaOH£©£¬Ò¡ÔÈ£¬ÔÙ¼Ó¡¢Ë«ËõëåÊÔ¼ÁBÒº£¨»ò0.01g/mlCuSO4£©£®
¹Ê´ð°¸Îª£º
£¨1£©ÎåëÄ
£¨2£©4 4
£¨3£©Ë«Ëõëå ×Ï ëļü ÏȼÓË«ËõëåÊÔ¼ÁAÒº£¨»ò0.1g/mlNaOH£©£¬Ò¡ÔÈ£¬ÔÙ¼Ó¡¢Ë«ËõëåÊÔ¼ÁBÒº£¨»ò0.01g/mlCuSO4£©
µãÆÀ£º±¾ÌâÒÔÄÔ·ÈëÄÎªËØ²Ä£¬½áºÏÆä½á¹¹Ê¾Òâͼ£¬¿¼²éµ°°×ÖʵĺϳÉ--°±»ùËáÍÑË®ËõºÏ£¬ÒªÇó¿¼Éúʶ¼Ç°±»ùËáµÄ½á¹¹Í¨Ê½£¬ÕÆÎÕ°±»ùËáÍÑË®ËõºÏ¹ý³Ì£¬Äܸù¾Ý·Ö×Óʽ׼ȷÅÐ¶ÏÆäËùº¬°±»ùËáÊýÄ¿¼°ÖÖÀ࣬µ°°×Öʵļø¶¨¹ý³Ì£¬ÔÙ½áºÏËùѧµÄ֪ʶ´ðÌâ¼´¿É£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁйØÓÚÒȵºËØ×÷ÓõÄÐðÊö²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢´Ù½øÆÏÌÑÌǵÄÑõ»¯·Ö½â |
| B¡¢ÒÖÖÆÊ³ÎïÖÐÌÇÀàµÄÏû»¯ÎüÊÕ |
| C¡¢´Ù½ø¸ÎÌÇԺͼ¡ÌÇÔµÄºÏ³É |
| D¡¢ÒÖÖÆ¸ÎÌÇԵķֽâ |
ÔÚÉúÃü»î¶¯ÖУ¬Ã¸ÊDz»¿ÉȱÉÙµÄÉúÎï´ß»¯¼Á£¬ÒÔϸ÷øµÄ×÷ÓöÔÏóÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢½âÐýø-ëļü¡¢ëÄø-¼î»ù¼äÇâ¼ü¡¢ATPË®½âø-Á×Ëá»ùÍÅ |
| B¡¢ëÄø-ëļü¡¢½âÐýø-¼î»ù¼äÇâ¼ü¡¢ATPË®½âø-¸ßÄÜÁ×Ëá¼ü |
| C¡¢ATPË®½âø-NADPH¡¢ëÄø-¼î»ù¼äÇâ¼ü¡¢ÏËÎ¬ËØÃ¸-ÔÉúÖÊÌå |
| D¡¢ëÄø-R»ù¡¢½âÐýø-ÍÑÑõºËÜÕËá¡¢ATPË®½âø-ATP |
Óë¼¤ËØµ÷½ÚÏà±È£¬¸ßµÈ¶¯ÎïÉñ¾µ÷½Ú¾ßÓеÄÌØµãÊÇ£¨¡¡¡¡£©
¢Ùµ÷½ÚËÙ¶È¿ì ¢Úµ÷½ÚËÙ¶ÈÂý ¢Û×÷Ó÷¶Î§¹ã
¢Ü×÷ÓÃʱ¼ä¶Ì ¢Ý×÷Óò¿Î»×¼È· ¢Þ×÷ÓÃʱ¼ä±È½Ï³¤£®
¢Ùµ÷½ÚËÙ¶È¿ì ¢Úµ÷½ÚËÙ¶ÈÂý ¢Û×÷Ó÷¶Î§¹ã
¢Ü×÷ÓÃʱ¼ä¶Ì ¢Ý×÷Óò¿Î»×¼È· ¢Þ×÷ÓÃʱ¼ä±È½Ï³¤£®
| A¡¢¢Ù¢Ü¢Ý | B¡¢¢Ù¢Û¢Þ |
| C¡¢¢Ú¢Û¢Þ | D¡¢¢Ú¢Û¢Ý |