ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿½«N2¡¢H2µÄ»ìºÏÆøÌå·Ö±ð³äÈë¼×¡¢ÒÒ¡¢±ûÈý¸öÈÝÆ÷ÖУ¬½øÐкϳɰ±·´Ó¦£¬¾­¹ýÏàͬµÄÒ»¶Îʱ¼äºó£¬²âµÃ·´Ó¦ËÙÂÊ·Ö±ðΪ£º¼×£º¦Ô£¨H2£©£½1 mol¡¤L£­1¡¤min£­1£»ÒÒ£º¦Ô£¨N2£©£½2 mol¡¤L£­1¡¤min£­1£»±û£º¦Ô£¨NH3£©£½ 3 mol¡¤L£­1¡¤min£­1¡£ÔòÈý¸öÈÝÆ÷Öкϳɰ±µÄ·´Ó¦ËÙÂÊ

A. ¦Ô(¼×)£¾¦Ô(ÒÒ)£¾¦Ô(±û£© B. ¦Ô(ÒÒ)£¾¦Ô(±û)£¾¦Ô(¼×£©

C. ¦Ô(±û)£¾¦Ô(¼×)£¾¦Ô(ÒÒ) D. ¦Ô(ÒÒ)£¾¦Ô(¼×)£¾¦Ô(±û£©

¡¾´ð°¸¡¿B

¡¾½âÎö¡¿

ͬһ»¯Ñ§·´Ó¦ÖУ¬Í¬Ò»Ê±¼ä¶ÎÄÚ£¬¸÷ÎïÖʵķ´Ó¦ËÙÂÊÖ®±ÈµÈÓÚÆ仯ѧ¼ÆÁ¿ÊýÖ®±È£»ÏȰѲ»Í¬ÎïÖʵķ´Ó¦ËÙÂÊ»»Ëã³ÉͬһÎïÖʵķ´Ó¦ËÙÂʽøÐбȽϣ¬¾Ý´Ë·ÖÎö×÷´ð¡£

ºÏ³É°±µÄ·´Ó¦Îª£ºN2(g)+3H2(g) 2NH3(g)£¬ÒÔÇâÆøµÄ»¯Ñ§·´Ó¦ËÙÂÊΪ±ê×¼½øÐÐÅжϣ¬

¼×£º¦Ô£¨H2£©£½1 mol¡¤L£­1¡¤min£­1£»

ÒÒ£º¦Ô£¨N2£©£½2 mol¡¤L£­1¡¤min£­1£¬¸ù¾Ý»¯Ñ§·´Ó¦ËÙÂÊÖ®±ÈµÈÓÚ»¯Ñ§·½³ÌʽÖл¯Ñ§¼ÆÁ¿ÊýÖ®±È£¬¦Ô£¨H2£©£½3¦Ô£¨N2£© = 3¡Á2 mol¡¤L£­1¡¤min£­1 = 6 mol¡¤L£­1¡¤min£­1£»

±û£º¦Ô£¨NH3£©£½ 3 mol¡¤L£­1¡¤min£­1£¬Í¬Àí¿ÉÖª¦Ô£¨H2£©£½1.5¦Ô£¨NH3£©£½ 1.5¡Á3 mol¡¤L£­1¡¤min£­1 = 4.5 mol¡¤L£­1¡¤min£­1£¬¿ÉÒÔ¿´³ö·´Ó¦ËÙÂÊ£º¦Ô(ÒÒ)£¾¦Ô(±û)£¾¦Ô(¼×£©£¬BÏîÕýÈ·£»

¹Ê´ð°¸Ñ¡B¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ä³Ð¡×éÓû̽¾¿·´Ó¦2Fe2+ + I22Fe3+ + 2I£¬Íê³ÉÈçÏÂʵÑ飺

×ÊÁÏ£ºAgIÊÇ»ÆÉ«¹ÌÌ壬²»ÈÜÓÚÏ¡ÏõËá¡£ÐÂÖƵÄAgI¼û¹â»áÉÙÁ¿·Ö½â¡£

(1)¢ñ¡¢¢ò¾ùδ¼ì³öFe3+£¬¼ìÑé¢òÖÐÓÐÎÞFe3+µÄʵÑé²Ù×÷¼°ÏÖÏóÊÇ£ºÈ¡ÉÙÁ¿¢òÖÐÈÜÒº£¬______¡£

(2)¢óÖеĻÆÉ«»ë×ÇÊÇ______¡£

(3)¾­¼ìÑ飬¢ò¡ú¢óµÄ¹ý³ÌÖвúÉúÁËFe3+¡£

¢Ù¶ÔFe3+²úÉúµÄÔ­Òò×ö³öÈçϼÙÉ裺

¼ÙÉèa£º¿ÕÆøÖдæÔÚO2£¬ÓÉÓÚ______(ÓÃÀë×Ó·½³Ìʽ±íʾ)£¬¿É²úÉúFe3+£»

¼ÙÉèb£ºÈÜÒºÖÐAg+¾ßÓÐÑõ»¯ÐÔ£¬¿É²úÉúFe3+£»

¼ÙÉèc£º ______£»

¼ÙÉèd£º¸ÃÌõ¼þÏ£¬I2ÈÜÒº¿É½«Fe2+Ñõ»¯ÎªFe3+¡£

¢Úͨ¹ýʵÑé½øÒ»²½Ö¤Êµa¡¢b¡¢c²»ÊDzúÉúFe3+µÄÖ÷ÒªÔ­Òò£¬¼ÙÉèd³ÉÁ¢¡£¢ò¡ú¢óµÄ¹ý³ÌÖÐI2ÈÜÒºÑõ»¯Fe2+µÄÔ­ÒòÊÇ______¡£

(4)¾­¼ìÑ飬¢ôÖлҺÚÉ«»ë×ÇÖк¬ÓÐAgIºÍAg¡£

¢ÙÑéÖ¤»ÒºÚÉ«»ë×Ǻ¬ÓÐAgµÄʵÑé²Ù×÷¼°ÏÖÏóÊÇ£ºÈ¡Ï´¾»ºóµÄ»ÒºÚÉ«¹ÌÌ壬______¡£

¢Ú Ϊ̽¾¿¢ó¡ú¢ô³öÏÖ»ÒºÚÉ«»ë×ǵÄÔ­Òò£¬Íê³ÉÁËʵÑé1ºÍʵÑé2¡£

ʵÑé1£ºÏò1 mL 0.1 mol¡¤L1 FeSO4ÈÜÒºÖмÓÈë1 mL0.1 mol¡¤L1 AgNO3ÈÜÒº£¬¿ªÊ¼Ê±£¬ÈÜÒºÎÞÃ÷ÏԱ仯¡£¼¸·ÖÖӺ󣬳öÏÖ´óÁ¿»ÒºÚÉ«»ë×Ç¡£·´Ó¦¹ý³ÌÖÐζȼ¸ºõÎޱ仯¡£²â¶¨ÈÜÒºÖÐAg+Ũ¶ÈË淴Ӧʱ¼äµÄ±ä»¯ÈçÏÂͼ¡£

ʵÑé2£ºÊµÑ鿪ʼʱ£¬ÏÈÏòÊÔ¹ÜÖмÓÈ뼸µÎFe2(SO4)3ÈÜÒº£¬Öظ´ÊµÑé1£¬ÊµÑé½á¹ûÓëʵÑé1Ïàͬ¡£

¢¡£®ÊµÑé1Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______¡£

¢¢£®¢ôÖÐѸËÙ³öÏÖ»ÒºÚÉ«»ë×ǵĿÉÄܵÄÔ­ÒòÊÇ______¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø