ÌâÄ¿ÄÚÈÝ

£¨16·Ö£©îÙ(Pd)µÄÐÔÖÊÓ벬ÏàËÆ¡£¹¤ÒµÉÏ´Ó·Ï´ß»¯¼Á£¨Ö÷Òª³É·ÖÊÇîٺͻîÐÔÌ¿£¬»¹º¬ÓÐÉÙÁ¿Ìú¡¢Ð¿£©ÖлØÊÕîÙ£¬²ÉÓÃÈçÏÂÁ÷³Ì£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ËáÈÜIµÄÄ¿µÄÊÇ__________________________________¡£

£¨2£©¢ÙËáÈÜ¢òʱ²ÐÔüÓëÍõË®ÔÚ¼ÓÈÈÌõ¼þ·¢ÉúµÄÖ÷Òª·´Ó¦ÊÇ£º

3Pd +12HCl + 2HNO3 3H2PdCl4 + 2NO¡ü+ 4H2O

д³ö´ß»¯¼ÁÖÐÁíÒ»Ö÷Òª³É·ÖÓëŨÏõËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________________¡£

¢ÚËáÈÜ¢òÐè¿ØÖÆÎ¶Ȳ»Ò˹ý¸ß£¬³ýÁË¿ØÖÆÒ»¶¨·´Ó¦ËÙÂÊÍ⣬ÆäÔ­Òò¿ÉÄÜ»¹ÓÐ

_____________________________¡£

¢ÛÈôÓÃ×ãÁ¿µÄÉÕ¼îÎüÊÕÆøÌ壬Çëд³öÎüÊÕºóÈÜÒºÖк¬ÓеÄÈÜÖʵĻ¯Ñ§Ê½£ºNaOH¡¢NaNO2¡¢___________¡¢___________¡£

£¨3£©Ê¹Óü×È©»¹Ô­îٵϝºÏÎïʱ£¬ÈÜÒºÐë±£³Ö¼îÐÔ£¬·ñÔò»áÔì³É¼×È©µÄ¶îÍâËðºÄ£¬Ô­ÒòÊÇ_______________________________________¡£

£¨4£©²Ù×÷IµÄÃû³ÆÊÇ_______________£¬ÈÜÒºI¿ÉÄܺ¬ÓеÄÓлúÀë×ÓΪ________________¡£

£¨5£©ÓÐÈËÌá³ö£¬ÔÚ½øÐÐËáÈÜǰ×îºÃÏȽ«·Ï´ß»¯¼ÁÔÚ700¡æÏ½øÐÐׯÉÕ£¬Í¬Ê±²»¶ÏͨÈë¿ÕÆø£¬

ÆäÄ¿µÄÊÇ______________________________________________________¡£

 

¡¾´ð°¸¡¿

£¨1£©³ýÈ¥Ìú¡¢Ð¿µÈÔÓÖÊ  £¨2·Ö£©

£¨2£©¢ÙC+4HNO3£¨Å¨£© CO2¡ü+4NO2¡ü+2H2O £¨2·Ö£©

¢Ú·ÀÖ¹ÏõËá·Ö½â£¬·ÀÖ¹ÑÎËá¡¢ÏõËá»Ó·¢£¨2·Ö£©

¢ÛNaNO3¡¢Na2CO3£¨2·Ö£©

£¨3£©ËáÐÔÌõ¼þÏ£¬¼×È©»á±»ÏõËáÑõ»¯£¨2·Ö£©  £¨4£©¹ýÂË£¨2·Ö£©   HCOO£¨2·Ö£©

£¨5£©³ýÈ¥·Ï´ß»¯¼ÁÖеĻîÐÔÌ¿£¬¼õÉÙÍõË®µÄÏûºÄ£¨2·Ö£©

¡¾½âÎö¡¿£¨1£©ÓÉÓÚº¬ÓÐпºÍÌú£¬ËùÒÔËữµÄÄ¿µÄÊdzýȥпºÍÌú¡£

£¨2£©¢ÙŨÏõËá¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Ò²ÄÜÑõ»¯µ¥ÖÊ̼£¬·´Ó¦Ê½ÎªC+4HNO3£¨Å¨£© CO2¡ü+4NO2¡ü+2H2O¡£

¢ÚÓÉÓÚÏõËáÒ׷ֽ⣬ÇÒÏõËáºÍÑÎËá¶¼Ò×»Ó·¢£¬ËùÒÔζȲ»ÄÜÌ«¸ß¡£

¢ÛÒòÎªÆøÌåÖк¬ÓÐCO2ºÍNO2£¬ËùÒÔ»¹»á²úÉú̼ËáÄÆºÍÏõËáÄÆ¡£

£¨3£©ÓÉÓÚÔÚËáÐÔÌõ¼þÏ£¬ÏõËáÄÜÑõ»¯¼×È©£¬ËùÒÔÈÜÒº±ØÐë±£³Ö¼îÐÔ¡£

£¨4£©½ðÊôPd²»ÈÜÓÚË®£¬¹ýÂ˼´¿É¡£¼×È©µÄÑõ»¯²úÎïÊǼ×ËᣬËùÒÔ¿ÉÄܺ¬ÓеÄÓлúÀë×ÓÊÇ HCOO¡£

£¨5£©ÒòΪÔÚ¼ÓÈÈʱ̼Äܱ»ÑõÆøÑõ»¯Éú³ÉCO2£¬ÕâÑù¿ÉÒÔ¼õÉÙÍõË®µÄÏûºÄ¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2012?ºç¿ÚÇø¶þÄ££©îÙ£¨Pd£©ÊÇÒ»ÖÖ²»»îÆÃ½ðÊô£¬ÐÔÖÊÓ벬ÏàËÆ£®ÔÚ¿ÆÑк͹¤ÒµÉú²úÖУ¬º¬îÙ´ß»¯¼Á²»½öÓÃ;¹ã·º£¬ÇÒÓÃÁ¿´ó£¬Òò´Ë´Ó·Ï´ß»¯¼ÁÖлØÊÕîÙ¾ßÓо޴óµÄ¾­¼ÃÐ§Òæ£®ÒÑÖª·Ï´ß»¯¼ÁµÄÖ÷Òª³É·ÖÊÇîٺͻîÐÔÌ¿£¬»¹º¬ÓÐÉÙÁ¿Ìú¡¢Ð¿£®¹¤ÒµÉϲÉÓÃÈçÏÂÁ÷³Ì´Ó·Ï´ß»¯¼ÁÖÐÌáÈ¡îÙ£®

£¨1£©ÆøÌåIµÄ»¯Ñ§Ê½Îª
H2
H2
£¬ËáÈÜIµÄÄ¿µÄÊÇ
³ýÈ¥Ìú¡¢Ð¿µÈÔÓÖÊ
³ýÈ¥Ìú¡¢Ð¿µÈÔÓÖÊ
£®
£¨2£©ÍõˮָÊÇŨÏõËáºÍŨÑÎËá×é³ÉµÄ»ìºÏÎÆäÌå»ý±ÈΪ
1£º3
1£º3
£®²ÐÔüÓëÍõË®·¢ÉúµÄ·´Ó¦ÓУº
a£®Pd+HCl+HNO3¡ú¡­
b£®
C+4HNO3¨TCO2¡ü+4NO2¡ü+2H2O
C+4HNO3¨TCO2¡ü+4NO2¡ü+2H2O
£¨Ð´³ö»¯Ñ§·½³Ìʽ²¢Å䯽£©£®
£¨3£©ÈôÓÃ×ãÁ¿µÄÉÕ¼îÎüÊÕÆøÌåII£¬Çëд³öÎüÊÕºóÈÜÒºÖк¬ÓеÄÈÜÖʵĻ¯Ñ§Ê½£ºNaOH¡¢
NaNO3
NaNO3
¡¢
NaNO2
NaNO2
¡¢
Na2CO3
Na2CO3
£®
£¨4£©Ð´³öÓÃNaHCO3µ÷½ÚpHֵʱ·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º
HCO3-+H+¨TH2O+CO2¡ü
HCO3-+H+¨TH2O+CO2¡ü
£®Ê¹Óü×È©»¹Ô­îٵϝºÏÎïʱ£¬ÈÜÒºÐë±£³Ö¼îÐÔ£¬·ñÔò»áÔì³É¼×È©µÄ¶îÍâËðºÄ£¬Ô­ÒòÊÇ
ËáÐÔÌõ¼þÏ£¬¼×È©»á±»ÏõËáÑõ»¯
ËáÐÔÌõ¼þÏ£¬¼×È©»á±»ÏõËáÑõ»¯
£®
£¨5£©²Ù×÷IµÄÃû³ÆÊÇ
¹ýÂË
¹ýÂË
£¬ÈÜÒºI¿ÉÄܺ¬ÓеÄÓлúÀë×ÓΪ
HCOO-
HCOO-
£®
£¨6£©ÓÐÈËÌá³ö£¬ÔÚ½øÐÐËáÈÜǰ×îºÃÏȽ«·Ï´ß»¯¼ÁÔÚ700¡æÏ½øÐÐׯÉÕ£¬Í¬Ê±²»¶ÏͨÈë¿ÕÆø£¬ÆäÄ¿µÄÊÇ
³ýÈ¥·Ï´ß»¯¼ÁÖеĻîÐÔÌ¿£¬¼õÉÙÍõË®µÄÏûºÄ
³ýÈ¥·Ï´ß»¯¼ÁÖеĻîÐÔÌ¿£¬¼õÉÙÍõË®µÄÏûºÄ
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø