题目内容

8.4 g N2与9.6 g某单质RX,所含原子个数相同,且分子数之比为3:2,则R的相对原子质量是         ,x值为            
16 , 3 

试题分析:8.4 g N2含有的N原子为8.4/28×2=0.6mol,设该单质的摩尔质量为M,则
0.3/9.6/M=" 3:2" ,M=48g/mol,x=0.6/(9.6/48)=3,R的相对原子质量=48/3=16.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                              
点评:本题考查了化学的基本计算,给出的数字较多,要合理利用上述数字,该题难度适中。
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