ÌâÄ¿ÄÚÈÝ

ÈçͼÖÐA¡¢B¡¢C·Ö±ðÊÇij¿ÎÍâ»î¶¯Ð¡×éÉè¼ÆµÄÖÆÈ¡°±Æø²¢½øÐÐÅçȪʵÑéµÄÈý×é×°ÖÃʾÒâͼ£¬ÖÆÈ¡NH3Ñ¡ÓÃÊÔ¼ÁÈçͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

¾«Ó¢¼Ò½ÌÍø

£¨1£©ÓÃAͼËùʾµÄ×°ÖÿÉÖÆ±¸¸ÉÔïµÄNH3
¢Ù·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®×°ÖÃÖÐÊÕ¼¯NH3µÄÊԹܿڷÅÖÃÃÞ»¨ÍŵÄ×÷ÓÃÊÇ______£®
¢Ú¸ÉÔï¹ÜÖиÉÔï¼ÁÄÜ·ñ¸ÄÓÃÎÞË®CaCl2______£¬ÀíÓÉÊÇ______£®
£¨2£©ÓÃBͼËùʾµÄ×°ÖÿɿìËÙÖÆÈ¡½Ï´óÁ¿NH3Äâ×÷ÅçȪʵÑ飮¸ù¾ÝBͼËùʾµÄ×°Öü°ÊÔ¼Á»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÓû¯Ñ§·½³Ìʽ±íʾŨ°±Ë®µÎÈëCaOÖÐÓдóÁ¿NH3ÒݳöµÄ¹ý³Ì£º______
¢Ú¼ìÑéNH3ÊÇ·ñÊÕ¼¯ÂúµÄʵÑé·½·¨ÊÇ£º______£®
£¨3£©ÓÃCͼËùʾµÄ×°ÖýøÐÐÅçȪʵÑ飬Éϲ¿ÉÕÆ¿ÒѳäÂú¸ÉÔï°±Æø£¬Òý·¢Ë®ÉÏÅçµÄ²Ù×÷ÊÇ______£¬¸ÃʵÑéµÄÔ­ÀíÊÇ£º______£®
Èô²âµÃC×°ÖÃÉÕÆ¿ÖÐNH3µÄÖÊÁ¿ÊÇÏàͬ״¿öÏÂÏàͬÌå»ýH2ÖÊÁ¿µÄ10±¶£¬ÔòÅçȪʵÑéÍê±Ïºó£¬ÉÕÆ¿ÖÐË®¿ÉÉÏÉýÖÁÉÕÆ¿ÈÝ»ýµÄ______£¨Ìî¡°¼¸·ÖÖ®¼¸¡±£©£®
£¨1£©¢ÙÔÚ¼ÓÈÈÌõ¼þÏ£¬ÂÈ»¯ï§ºÍÇâÑõ»¯¸Æ·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ°±Æø£»°±ÆøÊÇÆøÌ壬ÈÝÒ×ºÍ¿ÕÆø²úÉú¶ÔÁ÷£¬ËùÒÔÃÞ»¨µÄ×÷ÓÃÊÇ·ÀÖ¹¿ÕÆø¶ÔÁ÷£¬Ê¹NH3³äÂúÊԹܣ¬
¹Ê´ð°¸Îª£º2NH4Cl+Ca£¨OH£©2
  ¡÷  
.
 
CaCl2+2NH3¡ü+2H2O£»·ÀÖ¹¿ÕÆø¶ÔÁ÷£¬Ê¹NH3³äÂúÊԹܣ»
¢ÚÂÈ»¯ï§ºÍ°±ÆøÄÜ·¢Éú·´Ó¦CaCl2+8NH3=CaCl2?8NH3£¬ËùÒÔ¸ÉÔï¹ÜÖиÉÔï¼Á²»ÄܸÄÓÃÎÞË®CaCl2£¬
¹Ê´ð°¸Îª£º²»ÄÜ£»CaCl2+8NH3=CaCl2?8NH3£»
£¨2£©¢ÙÑõ»¯¸ÆºÍË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬Çҷųö´óÁ¿ÈÈÁ¿£¬Ñõ»¯¸ÆºÍË®·Å³öµÄÈÈÁ¿ÄÜ´Ù½ø°±Ë®µÄ·Ö½â£¬
¹Ê´ð°¸Îª£ºCaO+H2O=Ca£¨OH£©2£¬·´Ó¦·ÅÈÈ£¬NH3?H2O
  ¡÷  
.
 
NH3¡ü+H2O£»
¢Ú°±ÆøÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬°±ÆøºÍÂÈ»¯Çâ·´Ó¦Éú³É°×ÑÌ£¬ËùÒÔ¿ÉÓÃÂÈ»¯Çâ»òʪÈóµÄºìɫʯÈïÊÔÖ½¼ìÑ飬
¹Ê´ð°¸Îª£ºÓò£Á§°ôպȡÉÙÐíŨÑÎËá¿¿½üÊÕ¼¯NH3µÄÊԹܿڣ¬Èô²úÉú°×ÑÌ£¬ËµÃ÷ÊÔ¹ÜÒÑÊÕ¼¯ÂúNH3£¬·´Ö®£¬ÔòûÓÐÊÕ¼¯Âú£»»òÓÃʪÈóµÄºìɫʯÈïÊÔÖ½¿¿½üÊÕ¼¯NH3µÄÊԹܿڣ¬ÈôʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬Ôò˵Ã÷NH3ÒÑÊÕ¼¯Âú£¬·´Ö®£¬ÔòûÓÐÊÕ¼¯Âú£»
£¨3£©NH3¼«Ò×ÈܽâÓÚË®£¬´ò¿ªÖ¹Ë®¼Ð¼·³ö½ºÍ·µÎ¹ÜÖеÄË®£¬ÓÉÓÚ°±ÆøÑ¸ËÙÈܽ⵼ÖÂÉÕÆ¿ÄÚÆøÌåѹǿѸËÙ¼õС£¬µ¼ÖÂÈÜÒº½øÈëÉÕÆ¿²úÉúÅçȪÏÖÏó£»ÉÕÆ¿ÖÐNH3µÄÖÊÁ¿ÊÇÏàͬ״¿öÏÂÏàͬÌå»ýH2ÖÊÁ¿µÄ10±¶£¬ËùÒÔÉÕÆ¿ÖÐÆøÌåµÄƽ¾ù·Ö×ÓÁ¿ÊÇÇâÆøµÄ10±¶£¬¼´ÉÕÆ¿ÖÐÆøÌåµÄƽ¾ù·Ö×ÓÁ¿ÊÇ20£¬

¾«Ó¢¼Ò½ÌÍø
£¬ËùÒÔ¿ÕÆøºÍ°±ÆøµÄÌå»ýÖ®±ÈΪ1£º3£¬¹ÊÅçȪʵÑéÍê±Ïºó£¬ÉÕÆ¿ÖÐË®¿ÉÉÏÉýÖÁÉÕÆ¿ÈÝ»ýµÄ
3
4
£¬
¹Ê´ð°¸Îª£º´ò¿ªÖ¹Ë®¼Ð¼·³ö½ºÍ·µÎ¹ÜÖеÄË®£»NH3¼«Ò×ÈܽâÓÚË®£¬ÖÂʹÉÕÆ¿ÄÚѹǿѸËÙ¼õС£»
3
4
£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2012?Íò°²ÏØÄ£Ä⣩ÈçͼÖРA¡¢B¡¢C¡¢D¡¢E¾ùΪÓлú»¯ºÏÎÒÑÖª£ºCÄܸúNaHCO3·¢Éú·´Ó¦£¬CºÍDµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÏàµÈ£¬ÇÒEΪÎÞÖ§Á´µÄ»¯ºÏÎ

¸ù¾ÝÉÏͼ»Ø´ðÎÊÌ⣺
£¨1£©ÒÑÖªEµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª102£¬ÆäÖÐ̼¡¢ÇâÁ½ÖÖÔªËØµÄÖÊÁ¿·ÖÊý·Ö±ðΪ58.8%¡¢9.8%£¬ÆäÓàΪÑõ£¬ÔòEµÄ·Ö×ÓʽΪ
C5H10O2
C5H10O2
£»C·Ö×ÓÖеĹÙÄÜÍÅÃû³ÆÊÇ
ôÈ»ù
ôÈ»ù
£»»¯ºÏÎïB²»ÄÜ·¢ÉúµÄ·´Ó¦ÊÇ
e
e
£¨Ìî×ÖĸÐòºÅ£©£º
a£®¼Ó³É·´Ó¦  b£®È¡´ú·´Ó¦  c£®ÏûÈ¥·´Ó¦ d£®õ¥»¯·´Ó¦  e£®Ë®½â·´Ó¦  f£® Öû»·´Ó¦
£¨2£©·´Ó¦¢ÚµÄ»¯Ñ§·½³ÌʽÊÇ
CH3COOH+CH3CH2CH2OH
ŨÁòËá
¡÷
CH3COOCH2CH2CH3+H2O
CH3COOH+CH3CH2CH2OH
ŨÁòËá
¡÷
CH3COOCH2CH2CH3+H2O
£®
£¨3£©·´Ó¦¢ÚʵÑéÖмÓÈȵÄÄ¿µÄÊÇ£º
¢ñ
¼Ó¿ì·´Ó¦ËÙÂÊ
¼Ó¿ì·´Ó¦ËÙÂÊ
£»¢ò
¼°Ê±½«²úÎïÒÒËá±ûõ¥Õô³ö£¬ÒÔÀûÓÚÆ½ºâÏòÉú³ÉÒÒËá±ûõ¥µÄ·½ÏòÒÆ¶¯
¼°Ê±½«²úÎïÒÒËá±ûõ¥Õô³ö£¬ÒÔÀûÓÚÆ½ºâÏòÉú³ÉÒÒËá±ûõ¥µÄ·½ÏòÒÆ¶¯
£®
£¨4£©AµÄ½á¹¹¼òʽÊÇ
£®
£¨5£©Í¬Ê±·ûºÏÏÂÁÐÈý¸öÌõ¼þµÄBµÄͬ·ÖÒì¹¹ÌåµÄÊýÄ¿ÓÐËĸö£®
¢ñ£®º¬Óмä¶þÈ¡´ú±½»·½á¹¹¢ò£®ÊôÓÚ·Ç·¼ÏãËáõ¥¢ó£®Óë FeCl3 ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£®Ð´³öÆäÖÐÈÎÒâÒ»¸öͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø