ÌâÄ¿ÄÚÈÝ
ÓÐһƿÎÞÉ«³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬Na+¡¢Mg2+¡¢H+¡¢Fe3+¡¢CO32-¡¢Cl-¡¢Br-ÖеÄÒ»ÖÖ»ò¼¸ÖÖ£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢ÙÓÃPHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊÇ¿ËáÐÔ
¢ÚÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÉÙÁ¿µÄCCl4¼°ÊýµÎÐÂÖƵÄÂÈË®£¬Õñµ´ºóCCl4²ãÏԳȺìÉ«
¢Û½«¢ÚµÃµ½µÄÈÜÒºµÎ¼ÓÏõËáÒøÈÜÒº£¬Óа×É«³ÁµíÉú³É£¬µÎ¼ÓÏ¡ÏõËá³Áµí²»Èܽ⡣
¢ÜÁíÈ¡²¿·ÖÈÜÒº£¬ÖðµÎ¼ÓÈëÏ¡NaOHÈÜÒº£¬Ê¹ÈÜÒº´ÓËáÐÔÖð½¥×ª±äΪ¼îÐÔ£¬Ôڵμӹý³ÌÖм°µÎ¼ÓÍê±Ïºó£¬ÈÜÒºÖоùÎÞ³ÁµíÉú³É
¸ù¾ÝÉÏÊöʵÑéÊÂʵȷ¶¨²¢»Ø´ð£º
£¨1£©ÔÚÈÜÒºÖУ¬¿Ï¶¨´æÔÚµÄÀë×ÓÓÐ ¡£
£¨2£©¿Ï¶¨²»´æÔÚµÄÀë×ÓÓÐ ¡£
£¨3£©¿ÉÄÜ´æÔÚµÄÀë×ÓÓÐ ¡£
£¨1£©H+ Br-
£¨2£©Mg2+ Fe3+¡¢CO32-
£¨3£©Na+ Cl-
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©¢ÙÈÜÒºÎÞÉ«£¬ËµÃ÷²»º¬Fe3+£»ÈÜÒº³ÊÇ¿ËáÐÔ£¬ËµÃ÷ÈÜÒºÖдæÔÚH+£¬ËùÒÔÓëÆä·´Ó¦µÄCO32-²»´æÔÚ£»¢ÚµÎÐÂÖƵÄÂÈË®£¬Õñµ´ºóCCl4²ãÏԳȺìÉ«£¬ËµÃ÷ÈÜÒºÖдæÔÚBr-£»¢Û²»ÄÜÖ¤Ã÷ÔÈÜÒºÖÐÓÐCl-£¬ÒòΪÉϲ½ÖеÄÈÜÒºÂÈË®Öк¬ÂÈÀë×Ó¢ÜÈÜÒºÖоùÎÞ³ÁµíÉú³É˵Ã÷ÈÜÒºÖв»º¬Mg2+£¬×ÛÉÏ·ÖÎöÔÚÈÜÒºÖУ¬¿Ï¶¨´æÔÚµÄÀë×ÓÓÐH+ Br-
£¨2£©¿Ï¶¨²»´æÔÚµÄÀë×ÓÓÐMg2+ Fe3+¡¢CO32-
£¨3£©¿ÉÄÜ´æÔÚµÄÀë×ÓÓÐNa+ Cl-
¿¼µã£º¿¼²éÈÜÒºÖÐÀë×Ó¼äµÄ·´Ó¦¼°Àë×ÓÑÕÉ«µÄÅжÏ