ÌâÄ¿ÄÚÈÝ

£¨08ïÃûÊжþÄ££©£¨±¾Ìâ12·Ö£©Ä³Ñ§Ï°Ð¡×éΪ̽¾¿SºÍCl2ÄÜ·ñ·´Ó¦£¬¾­²é×ÊÁÏ»ñµÃÐÅÏ¢£¬¸ÉÔïµÄCl2ÔÚ110¡æ¡«140¡æÓëS·´Ó¦£¬¿ÉµÃS2Cl2´ÖÆ·£¬ÓÉ´ËÉè¼ÆÈçÏÂÊÔÑé×°Ö㨼гÖ×°ÖÃδ»­³ö£©£¬Çë»Ø´ðºóÃæÎÊÌâ¡£

(1)ʵÑé¹ý³ÌÖУ¬Ê¹Ó÷ÖҺ©¶·µÎ¼ÓŨÑÎËáµÄ²Ù×÷ÊÇ                             £¨2·Ö£©£¨2£©Ó÷´Ó¦·½³Ìʽ±íʾH×°ÖõÄ×÷Óà                                       £¨2·Ö£©£¨3£©Ð´³öBÖз´Ó¦µÄÀë×Ó·½³Ìʽ                                                 £¨2·Ö£©£¨4£©C¡¢DÖеÄÊÔ¼Á·Ö±ðÊÇ                          £¬                   £¨2·Ö£©£¨5£©¾­¼ì²â´ÖÆ·Öк¬ÓÐSCl2£¬Îª¼õÉÙSCl2µÄÉú³É£¬¹Ø¼üµÄ²Ù×÷ÊÇ                 £¨2·Ö£©£¨6£©Fµ¼¹Ü¿ÉÄܻᷢÉú¶ÂÈû£¬ÇëÔÚC¡¢DÖ®¼äÉè¼ÆÒ»¸ö·À¶ÂÈû×°ÖÃÒÔÃâ·¢ÉúΣÏÕ¡££¨ÒªÇó»­³ö×°ÖÃͼ£¬±ê³öÊÔ¼ÁÃû³Æ£¬¼Ð³Ö×°Öò»Ðè»­³ö£©                              £¨2·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨08ïÃûÊжþÄ££©£¨±¾Ìâ10·Ö£©Ð¡Ã÷Ϊ̽¾¿ÑªÒºÖиÆÀë×ÓÔÚѪҺÄý¹Ì¹ý³ÌÖÐÆðÖØÒª×÷Ó㬲é×ÊÁÏÖªµÀ¸ÆÀë×Óȱ·¦Ôò²»ÄÜÄý¹Ì£¬²ÝËá¼ØÈÜÒºÄÜÓëѪҺÖеĸÆÀë×Ó·¢Éú·´Ó¦£¬ÐγɲÝËá¸Æ³Áµí£¬Æð¿¹Äý×÷Óá£Ð¡Ã÷ʵÑéºó֤ʵ¸Ã×ÊÁϵĽáÂÛÊÇÕýÈ·µÄ¡£Çë¸ù¾ÝСÃ÷µÄʵÑé²ÄÁϺÍÓþߣ¬¼òҪд³öµÚ¶þ²½¼°ÒÔºóµÄʵÑé²½ÖèºÍʵÑé½á¹û£¬²¢»Ø´ðÎÊÌâ¡£

£¨1£©ÊµÑé²ÄÁϺÍÓþߣº¢Ù¼ÒÍà ¢ÚÉúÀíÑÎË®  ¢Û¾Æ¾«ÃÞ    ¢Ü0.1mol/LµÄ²ÝËá¼ØÈÜÒº ¢Ý0.1mol/LµÄÂÈ»¯¸ÆÈÜÒº   ¢ÞÊԹܠ  ¢ß×¢ÉäÆ÷£¨Õë¹Ü¡¢ÕëÍ·£©¡£

£¨2£©ÊµÑé²½ÖèºÍʵÑéÏÖÏó

µÚÒ»²½£ºÔÚA¡¢BÊÔ¹ÜÖзֱð¼ÓÈëµÈÁ¿µÄ²ÝËá¼ØÈÜÒººÍÉúÀíÑÎË®

µÚ¶þ²½£º                                                                  £¨2·Ö£©

µÚÈý²½£ºÁ¢¼´½«        £¨1·Ö£©¼ÓÈëµ½A¡¢BÁ½ÊÔ¹ÜÖУ¬¿ÉÒԹ۲쵽             £¨2·Ö£©

µÚËIJ½£º½«        £¨1·Ö£©ÈÜÒº·Ö±ð¼ÓÈëµ½A¡¢BÁ½ÊÔ¹ÜÖУ¬¿ÉÒԹ۲쵽         £¨2·Ö£©

£¨3£©ÉèÖÃB¹ÜµÄÄ¿µÄÊÇ                                                    £¨2·Ö£©

(08ïÃûÊжþÄ£)£¨15·Ö£©¹¤ÒµÖÆÁòËáÉú²úÁ÷³ÌÈçÏÂͼ£º

£¨1£©ÔçÆÚÉú²úÓûÆÌú¿óΪԭÁÏ£¬µ«ÏÖÔÚ¹¤³§Éú²úÁòËáÓÃÁò»ÇΪԭÁÏ£¬ÀíÓÉÊÇ       £¨2·Ö

£¨2£©ÔÚ´ß»¯·´Ó¦ÊÒ£¬ÏÂÁдëÊ©ÖÐÓÐÀûÓÚÌá¸ßSO2ƽºâת»¯ÂʵÄÓР             £¨2·Ö£©

A£®Éý¸ßζȠ                      B£®¼õÉÙѹǿ      

C£®²»¶Ï²¹³äSO2ºÍ¿ÕÆø             D£®¼°Ê±·ÖÀë³öSO3

£¨3£©ÔÚÉú²úÖУ¬ÎªÌá¸ß´ß»¯¼ÁЧÂʲÉÈ¡ÁËÄÄЩ´ëÊ©£¿                                   

                                                                        £¨3·Ö£©

£¨4£©ÒÑÖª2SO2£¨g£©+O2£¨g£©2SO3£¨g£©£¬¦¤H£½£­196 kJ?mol£­1¡£ÔÚ450¡æ¡¢³£Ñ¹ºÍ·°´ß»¯Ìõ¼þÏÂÏòÒ»ÃܱÕÈÝÆ÷ÖгäÈë2molSO2ºÍ1molO2,³ä·Ö·´Ó¦ºó,·Å³öµÄÈÈÁ¿______(Ìî¡°<¡±¡°>¡±¡°=¡±)196kJ£¬ÀíÓÉÊÇ______________________________________________¡£  £¨3·Ö£©

£¨5£©¾­¼ì²âÉú²úÁòËáµÄÔ­ÁÏÆø³É·Ö£¨Ìå»ý·ÖÊý£©ÎªSO27£¥¡¢O211£¥¡¢N282£¥¡£ÔÚ500¡æ£¬0.1MPaÌõ¼þÏ´ﵽƽºâʱ£¬¸÷ÖÖÆøÌåµÄÌå»ý±ÈΪV£¨SO2£©£ºV£¨SO3£©£ºV£¨O2£©£ºV£¨N2£©£½0.46£º6.5£º7.7£º82£¬ÔòSO2µÄÀûÓÃÂÊΪ                    £¨3·Ö£©

(6)ÔÚ450¡æ¡¢³£Ñ¹ºÍ·°´ß»¯Ìõ¼þÏ£¬ÔÚÈÝ»ýΪVLµÄÈÝÆ÷ÖмÓÈë2n molSO2ºÍn molO2£¬·´Ó¦´ïƽºâºó²âµÃƽºâ³£ÊýΪK£¬´ËʱO2µÄת»¯ÂÊΪx¡£ÔòKºÍxµÄ¹ØϵÂú×ãK£½      ¡££¨2·Ö£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø