ÌâÄ¿ÄÚÈÝ
(15·Ö)ijУ¸ßÒ»»¯Ñ§Ñо¿ÐÔѧϰС×é¶ÔÈÕ³£Éú»îÖеÄÂÈÆøÓÃ;½øÐÐÁ˵÷²é£¬Á˽⵽ÂÈÆø¿É¹ã·ºµØÓ¦ÓÃÓÚÒÂÎïµÄƯ°×¡¢Ë®ÌåµÄɱ¾úºÍÏû¶¾µÈ¡£
(1)ÂÈÆø¿ÉÒÔÓÃÓÚƯ°×¡¢Ïû¶¾µÄÔÒòÊÇÒòΪÄÜÓëË®×÷ÓÃÐγɾßÓÐ______ÐԵĴÎÂÈËᣬÏà¹Ø·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________________¡£
(2)ÔÚµ÷²éijÊÒÍâÓÎÓ¾³ØÏļ¾³ØË®Ïû¶¾Çé¿öʱ£¬Ð¡×é³ÉÔ±Á˽⵽£¬¸ÃÓÎÓ¾³ØÿÖÜÒ»ÉÏÎç8£º00»»Ë®£¬È»ºóͨÈëÂÈÆøÏû¶¾£¬Í¨³£ÓÎÓ¾³ØÖÐË®µÄº¬ÂÈÁ¿¿ØÖÆÔÚ0.5 mg¡¤L£1ÖÁ1.0 mg¡¤L£1Ö®¼äʱ£¬Ð§¹û×îºÃ¡£ÓÒͼÊǸÃС×é²â¶¨µÄÿÌì19£º00ʱÓÎÓ¾³ØÖÐË®µÄº¬ÂÈÁ¿£¬Äļ¸ÌìʹÓÃÓÎÓ¾³Ø²»°²È«£¿______¡£
(3)ÄãÈÏΪÄļ¸ÌìµÄÌìÆøÑ×ÈÈ¡¢Ñô¹âÇ¿ÁÒ______£¬Ëµ³öÒ»ÖÖÀíÓÉÊÇ
__________________________(±ØÒªµÄ·½³ÌʽºÍÎÄ×Ö)¡£
(4)ÔÚ¶ÔÓÎÓ¾³ØË®ÖÐͨÈëÂÈÆøÏû¶¾Ê±£¬µ±·¢ÉúÂÈÆøй©ʱ£¬Ó¦Á¢¼´¹Ø±ÕÂÈÆø¹Þ£¬»¹Ó¦²ÉÈ¡ÏÂÁÐ×Ծȷ½·¨______¡£
A£®ÓÃʪÈóµÄë½íÎæס¿Ú±ÇÅÜÏòµÍ´¦
B£®ÓýþʪСËÕ´ò»ò·ÊÔíË®µÄë½íÎæס¿Ú±ÇÅÜÏò¸ß´¦
C£®ÓýþʪŨ°±Ë®µÄë½íÎæס¿Ú±ÇÙéÙëÅÜÖÁ°²È«´¦
D£®ÓýþʪʳÑÎË®µÄë½íÎæס¿Ú±Ç˳·çÅÜÖÁ°²È«´¦
(5)СÐÍÓÎÓ¾³Øͨ³£Ê¹ÓÃƯ°×Òº(NaClOÈÜÒº)¶ø·ÇÂÈÆøÀ´Ïû¶¾³ØË®£¬ÊÔ¾Ù³öʹÓÃƯ°×ÒºÏû¶¾¶ø·ÇÂÈÆøµÄÒ»ÏîÀíÓÉ__________________£»Óû¯Ñ§·½³Ìʽ˵Ã÷¹¤ÒµÉÏÈçºÎÉú²úƯ°×Òº£¿________________________________________________________________________¡£
(1)Ç¿Ñõ»¯¡¡Cl2£«H2O===HCl£«HClO
(2)ÐÇÆÚÁù¡¢ÐÇÆÚÈÕ
(3)ÐÇÆÚËÄ¡¢ÐÇÆÚÁù¡¡Ñô¹âÇ¿ÁÒHClO¸üÒ׷ֽ⣬2HClO2HCl£«O2¡ü£¬µ¼Öº¬ÂÈÁ¿Ï½µÃ÷ÏÔ
(4)B
(5)NaClO¸üÎȶ¨£¬±ãÓÚ´¢´æºÍÔËÊä¡¡2NaOH£«Cl2===NaCl£«NaClO£«H2O?
½âÎö:±¾ÌâÒÔÂÈË®ÖÐHClOµÄÐÔÖÊΪ¿¼²é¶ÔÏóÉèÖÃÌâÄ¿¡£
(1)ÀûÓÃHClOµÄÇ¿Ñõ»¯ÐÔɱ¾úÏû¶¾¡£(3)ÒòΪHClOÓÖÓйâÕÕÒ×·Ö½âµÄÐÔÖÊ£º2HClO2HCl£«O2¡ü£¬Ê¹ClO£Å¨¶È½µµÍ£¬ÓÐЧÂȽµµÍ£¬É±¾úÏû¶¾Ð§¹û²»ÀíÏë¡£¿´×Ý×ø±êÿÌìµÄ±ä»¯Á¿£¬¿É¼ûÖÜËÄ¡¢ÖÜÁùϽµ·ù¶ÈÃ÷ÏÔ£¬Òò´ËÑô¹âÇ¿ÁÒ¡£(4)ÒòCl2ÃܶȱȿÕÆø´ó£¬¹ÊÈËÓ¦Ïò¸ß´¦ÅÜ£¬ÓÖÒòΪÂÈÆøÈÜÓÚˮʱÉú³ÉµÄHCl¡¢HClOÏÔËáÐÔ£¬¹ÊÓ¦ÓÃÏÔ¼îÐÔµÄÎïÖÊÎüÊÕ£¬¿¼Âǵ½°²È«ÐÔ£¬¹Ê¿ÉÓýþÓÐСËÕ´ò»ò·ÊÔíË®µÄë½íÎæס¿Ú±Ç¡£(5)ÒòΪHClOµÄ¼û¹â²»Îȶ¨ÐÔ£¬Òò´ËÑ¡ÓÃÆäÑÎÈÜҺɱ¾úÏû¶¾£¬Ð§¹û³¤¾ÃÇÒ±ãÓÚ´¢´æºÍÔËÊä¡£
(15·Ö) ijУ»¯Ñ§ÐËȤС×éΪÁË̽¾¿´ÖÌúÁ££¨º¬ÓÐÉÙÁ¿½ðÊôÍÔÓÖÊ£©ÓëijŨ¶ÈÏõËá·´Ó¦£¬Éè¼ÆÁËÈçÏÂ̽¾¿»î¶¯£º
̽¾¿Ò»
£¨1£©½«´ÖÌúÁ£Í¶ÈëijŨ¶ÈÏõËáÖУ¬Ä³Í¬Ñ§¹Û²ì¸ÃʵÑéÏÖÏóʱ·¢ÏÖ£¬·´Ó¦½øÐÐÒ»¶Îʱ¼äºó£¬·´Ó¦¿ªÊ¼Öð½¥¼Ó¿ì¡£Çë·ÖÎö·´Ó¦Öð½¥¼Ó¿ìµÄ¿ÉÄÜÔÒò
_______________________________________________________________________¡£
£¨2£©Áí³ÆÈ¡´ÖÌúÁ£10 g·ÅÈëijŨ¶ÈÏõËáÖУ¬³ä·Ö·´Ó¦ºóµÃµ½ÈÜÒºX²¢ÊÕ¼¯µ½ÆøÌåY¡£ÎªÁË̽¾¿ÈÜÒºXÖÐÌúÔªËصļÛ̬,ͬѧ¼×Éè¼ÆÈçÏÂʵÑ飺ÓÐÒ©Æ·ºÍÒÇÆ÷£º0.1 mol¡¤L-1 KSCNÈÜÒº£»0.1 mol¡¤L-1 KIÈÜÒº£»0.2 mol¡¤L-1ËáÐÔ¸ßÃÌËá¼ØÈÜÒº£»ÂÈË®µÈ£»ÊԹܺ͵ιÜ
ÇëÄãÉè¼Æ¼òµ¥ÊµÑ飬̽¾¿ÉÏÊö²ÂÏëÊÇ·ñÕýÈ·£¬ÌîдÏÂÁÐʵÑ鱨¸æ£º
ʵÑé²½Öè |
ÏÖÏó |
½áÂÛ |
Àë×Ó·½³Ìʽ |
µÚÒ»²½ |
È¡2-3 mLÈÜҺװÓÚÊԹܣ¬ÏòÊÔ¹ÜÖмÓÈ뼸µÎKSCNÈÜÒº¡£ |
|
|
µÚ¶þ²½ |
|
ÈôÈÜÒº×ÏÉ«ÍÊÈ¥£¬ÔòÈÜÒºº¬ÓÐFe2+£» ÈôÎÞÃ÷ÏԱ仯£¬Ôò²»º¬Fe3+¡£ |
|
̽¾¿¶þ ΪÁË̽¾¿ÆøÌåYµÄ³É·Ö£¬Í¬Ñ§ÒÒÉè¼ÆÁËÈçÏÂ×°Ö㨲»¿¼ÂÇNO2ת»¯ÎªN2O4£©
(3)×°ÖÃÒÒµÄ×÷Ó㺠¡£
£¨4£©×°ÖñûÊÕ¼¯µ½ÂúÆøÌåºó£¬Í¨¹ýÆøÅݹÄÈë¿ÕÆøºó£¬Óкì×ØÉ«ÆøÌåÉú³É£¬ÄÜ·ñÈ·¶¨
ÆøÌåYÖк¬NO£¿ ˵Ã÷ÀíÓÉ¡£
________________________________________________________________________¡£
(5) ͬѧ¶¡ÎªÁË̽¾¿ÆøÌåYµÄ×é³É£¬½«224mLÆøÌåYͨÈë×ãÁ¿µÄNaOHÈÜÒºÖУ¬ÆøÌå±»ÍêÈ«ÎüÊÕ£¬ËùµÃÈÜÒºÔÙÓÃ0.15 mol¡¤L-1ËáÐÔKMnO4ÈÜÒºµÎ¶¨£¬ÏûºÄ20 mLKMnO4ÈÜÒº¡£
ÔòÆøÌåYÖÐNO¡¢NO2µÄÌå»ý±ÈΪ ¡£
£¨ÒÑÖª2NO2+2NaOH£½NaNO3+NaNO2+H2OºÍNO2+NO+2NaOH£½2NaNO2+H2O£©