ÌâÄ¿ÄÚÈÝ

д³öÏÂÁи÷ÓлúÎïµÄ½á¹¹¼òʽ£º
£¨1£©Ä³Ìþ1molÓë2mol HClÍêÈ«¼Ó³É£¬Éú³ÉµÄÂÈ´úÍéÌþ×î¶à»¹¿ÉÒÔÓë4molÂÈÆø·´Ó¦£¬Ôò¸ÃÌþµÄ½á¹¹¼òʽΪ______________¡£
£¨2£©Ä³ÍéÌþAÕôÆøµÄÃܶÈÊÇÏàͬ״¿öÏÂÇâÆøÃܶȵÄ64±¶£¬¾­²â¶¨µÃÖªA·Ö×ÓÖй²º¬6¸ö¼×»ù¡£ÈôA²»¿ÉÄÜÊÇÏ©ÌþÓëÇâÆø¼Ó³ÉµÄ²úÎAµÄ½á¹¹¼òʽΪ___________ ;
£¨3£© 0.2 molijÌþAÔÚÑõÆøÖÐÍêȫȼÉÕºó£¬Éú³ÉCO2ºÍH2O¸÷1.2 mol¡£  
 ¢ÙÈôÌþA²»ÄÜʹäåË®ÍÊÉ«£¬µ«ÔÚÒ»¶¨Ìõ¼þÏÂÄÜÓëÂÈÆø·¢ÉúÈ¡´ú·´Ó¦£¬ÆäÒ»ÂÈÈ¡´úÎïÖ»ÓÐÒ»ÖÖ£¬ÔòÌþAµÄ½á¹¹¼òʽΪ_________________________¡£
¢Ú ÈôÌþAÄÜʹäåË®ÍÊÉ«£¬ÌþAÔÚ´ß»¯¼Á×÷ÓÃÏ¿ÉÒÔÓëH·¢Éú¼Ó³É·´Ó¦£¬Æä¼Ó³É²úÎï·Ö×ÓÖк¬ÓÐ4¸ö¼×»ù¡£Èç¹ûÌþAµÄ·Ö×ÓÖÐËùÓеÄ̼ԭ×Ó²»¿ÉÄÜ´¦ÓÚͬһƽÃæÉÏ£¬ÔòÌþA¿ÉÄܵĽṹ¼òʽΪ___________»ò______________¡£
£¨1£©
£¨2£©(CH3)3CCH2C(CH3)3¡£
£¨3£©¢Ù £» ¢ÚCH2£½CHC(CH3)3»òCH2£½C(CH3)CH(CH3)2
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨1£©Ð´³öÏÂÃæÓлúÎïµÄ½á¹¹¼òʽ£ºË³-2-¶¡Ï©£º
£»
£¨2£©ÏµÍ³ÃüÃû·¨ÃüÃûÏÂÁÐÎïÖÊ
¢Ù
2£¬3-¶þ¼×»ùÎìÍé
2£¬3-¶þ¼×»ùÎìÍé

¢Úº¬Ñõ¹ÙÄÜÍŵÄÃû³ÆÊÇ
È©»ù
È©»ù
£®
¢Û
2-±û´¼
2-±û´¼

£¨3£©°´ÒªÇóд³öÏÂÁл¯Ñ§·½³Ìʽ£®
¢Ù¼×±½¡úTNT
+3HNO3
 Å¨H2SO4 
.
¼ÓÈÈ
+3H2O£®
+3HNO3
 Å¨H2SO4 
.
¼ÓÈÈ
+3H2O£®

¢ÚÒÒÈ©ÓëÒø°±ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ
CH3CHO+2Ag£¨NH3£©2OH
¼ÓÈÈ
CH3COONH4+2Ag+3NH3+H2O
CH3CHO+2Ag£¨NH3£©2OH
¼ÓÈÈ
CH3COONH4+2Ag+3NH3+H2O

¢Û2-äå±ûÍé¡ú±ûÏ©
CH3CHBrCH+NaOH
´¼
¼ÓÈÈ
CH2=CH-CH3¡ü+NaBr+H2O£»
CH3CHBrCH+NaOH
´¼
¼ÓÈÈ
CH2=CH-CH3¡ü+NaBr+H2O£»

¢ÜÒÒÏ©¡úÒÒ¶þ´¼
CH2=CH2+Br2¡úCH2Br-CH2Br
CH2=CH2+Br2¡úCH2Br-CH2Br
£¬
CH2Br-CH2Br+2NaOH
¼ÓÈÈ
CH2OH-CH2OH+NaBr
CH2Br-CH2Br+2NaOH
¼ÓÈÈ
CH2OH-CH2OH+NaBr
£®
¢Ý±½·ÓÄÆÈÜÒºÖÐͨÈë¶þÑõ»¯Ì¼ÆøÌåµÄÀë×Ó·½³Ìʽ
C6H5O-+CO2+H2O¡úC6H5OH+HCO3-
C6H5O-+CO2+H2O¡úC6H5OH+HCO3-
£®
£¨4£©°´ÒªÇóд³öÏÂÁи÷ÓлúÎïµÄ½á¹¹¼òʽ£®
¢Ùµ±0.2molÌþAÔÚ×ãÁ¿ÑõÆøÖÐÍêȫȼÉÕʱÉú³ÉCO2ºÍH2O¸÷1.2mol£¬´ß»¯¼ÓÇâºóÉú³É2£¬2-¶þ¼×»ù¶¡Í飬ÔòAµÄ½á¹¹¼òʽΪ
£¨CH3£©3C-CH=CH2
£¨CH3£©3C-CH=CH2
£®
¢ÚijÌþ1molÓë2molHClÍêÈ«¼Ó³É£¬Éú³ÉµÄÂÈ´úÍé×î¶à»¹¿ÉÒÔÓë4molCl2·´Ó¦£¬Ôò¸ÃÌþµÄ½á¹¹¼òʽΪ
CH¡ÔCH
CH¡ÔCH
£®
¢ÛÓÐÁ½ÖÖѧ¹ýµÄÌþÍêȫȼÉÕºó£¬Éú³ÉCO2ºÍH2O£¨g£©Ìå»ý±ÈΪ2£º1£¬ÊÔд³öËüÃǵĽṹ¼òʽ
CH¡ÔCH
CH¡ÔCH
¡¢
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø