ÌâÄ¿ÄÚÈÝ
ÏÂͼÊÇ¿ÉÓÃÓÚ²âÁ¿°¢·ü¼ÓµÂÂÞ³£ÊýµÄ×°ÖÃʾÒâͼ£¬ÆäÖÐA£¬BÊÇÁ½¿é´¿ÍƬ£¬²åÔÚCuSO4Ï¡ÈÜÒºÖУ¬ÍƬÓëÒý³öµ¼ÏßÏàÁ¬£¬Òý³ö¶Ë·Ö±ðΪx£¬y¡£
£¨1£©µ±ÒÔI=0.21AµÄµçÁ÷µç½â60minºó£¬²âµÃÍƬAµÄÖÊÁ¿Ôö¼ÓÁË0.25g£¬ÔòͼÖÐ×°ÖõÄx¶ËÓ¦ÓëÖ±Á÷µçµÄ__________¼«ÏàÁ¬£¬ËüÊǵç½â³ØµÄ__________¼«¡£
£¨2£©µç½âºóÍƬBµÄÖÊÁ¿__________¡££¨Ôö¼Ó¡¢¼õÉÙ»ò²»±ä£©
£¨3£©ÁÐʽ¼ÆËãʵÑé²âµÃµÄ°¢·ü¼ÓµÂÂÞ³£ÊýNA¡££¨ÒÑÖªµç×ÓµçÁ¿e=1.60´10-19C£©
´ð°¸£º
½âÎö£º
½âÎö£º
£¨1£©¸º Òõ £¨2£©¼õÉÙ £¨3£©6.05´1023
|
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿