ÌâÄ¿ÄÚÈÝ
£¨22·Ö£©2SO2(g)+O2(g) 2SO3(g)·´Ó¦¹ý³ÌµÄÄÜÁ¿±ä»¯ÈçͼËùʾ¡£ÒÑÖª1mol SO2(g)Ñõ»¯Îª1mol SO3µÄ¦¤H=¡ª99kJ¡¤mol¡ª1£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Í¼ÖÐA¡¢C·Ö±ð±íʾ ¡¢ £¬EµÄ´óС¶Ô¸Ã·´Ó¦µÄ·´Ó¦ÈÈÓÐÎÞÓ°Ï죿 ¡£¸Ã·´Ó¦Í¨³£ÓÃV2O5×÷´ß»¯¼Á£¬¼ÓV2O5»áʹͼÖÐBµãÉý¸ß»¹ÊǽµµÍ£¿ £¬ÀíÓÉÊÇ £»
£¨2£©Í¼ÖС÷H= KJ¡¤mol¡ª1£»
£¨3£©V2O5µÄ´ß»¯Ñ»·»úÀí¿ÉÄÜΪ£ºV2O5Ñõ»¯SO2ʱ£¬×ÔÉí±»»¹ÔΪËļ۷°»¯ºÏÎËļ۷°»¯ºÏÎïÔÙ±»ÑõÆøÑõ»¯¡£Ð´³ö¸Ã´ß»¯Ñ»·»úÀíµÄ»¯Ñ§·½³Ìʽ £»
£¨4£©£¨2·Ö£©Èç¹û·´Ó¦ËÙÂʦԣ¨SO2£©Îª0£®05 mol¡¤L¡ª1¡¤min¡ª1,Ôò¦Ô£¨O2£©= mol¡¤L¡ª1¡¤min¡ª1¡¢
¦Ô(SO3)= mol¡¤L¡ª1¡¤min¡ª1£»
£¨5£©£¨2·Ö£©ÒÑÖªµ¥ÖÊÁòµÄȼÉÕÈÈΪ296 KJ¡¤mol¡ª1£¬¼ÆËãÓÉS(s)Éú³É3 molSO3(g)µÄ¡÷H £¨ÒªÇó¼ÆËã¹ý³Ì£©¡£
£¨6£©¼×ÍéȼÁÏµç³Ø £¨KOH×÷µç½âÖÊÈÜÒº£©
¸º¼«·´Ó¦·½³ÌʽÊÇ£º
Õý¼«·´Ó¦·½³ÌʽÊÇ£º
×Ü·´Ó¦·½³ÌʽÊÇ£º
£¨7£©£¨2·Ö£©³£ÎÂÏ£¬ÉèpH ¾ùΪ5µÄH2SO4ºÍA12(SO4)3ÈÜÒºÖÐÓÉË®µçÀë³öµÄc(H+)·Ö±ðΪc1 ¡¢c2£¬Ôòc1£ºc2= ¡£
£¨8£©£¨2·Ö£©Å¨¶ÈΪ0.5 mol/LµÄÑÎËáÓëµÈŨ¶ÈµÄ°±Ë®ÈÜÒº·´Ó¦£¬Ê¹ÈÜÒº³ÊÖÐÐÔ£¬Ôò»ìºÏǰÌå»ýVËá________V¼î(Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)
(9)£¨2·Ö£©È¡10 mLÈÜÒº0.5 mol/LµÄÑÎËᣬ¼ÓˮϡÊ͵½500 mL£¬Ôò´ËʱÈÜÒºÖÐÓÉË®µçÀë³öµÄc(H£«)£½________¡£
£¨22·Ö£©£¨1£©·´Ó¦ÎïÄÜÁ¿ Éú³ÉÎïÄÜÁ¿ ÎÞ ½µµÍ ÒòΪ´ß»¯¼Á¸Ä±äÁË·´Ó¦µÄÀú³Ìʹ»î»¯ÄÜE½µµÍ £¨2£©£¨2·Ö£©¡ª198
(3) £¨2·Ö£©SO2+V2O5=SO3+2VO2 4VO2+O2=2V2O5
(4)£¨2·Ö£©0£®025 0£®05
(5) £¨2·Ö£©S(s)+O2(g)=2SO2(g) ¡÷H1=¡ª296KJ¡¤mol¡ª1 ,
SO2(g)+1/2O2(g) SO3(g)¡÷H2=¡ª99 KJ¡¤mol¡ª1
3 S(s)+9/2O2(g)=3SO3(g) ¡÷H=3(¡÷H1+¡÷H2)=¡ª1185 KJ¡¤mol¡ª1
£¨6£©¸º¼«£ºCH4+10OH- £8e-=CO32-+7H2O Õý¼«£ºO2£«2H2O+4e-=4OH-
×Ü·´Ó¦£ºCH4£«2 O2+2OH-=CO32-+3H2O
£¨7£©£¨2·Ö£©1£º104 £¨8£©£¨2·Ö£©Ð¡ÓÚ£¨9£©£¨2·Ö£©10-12
½âÎö: