ÌâÄ¿ÄÚÈÝ
£¨1£©¾Ý¡¶¿Æ¼¼ÏûÏ¢±¨¡·±¨µÀ£ºÓÉÓÚ·ÏÆøÅÅ·ÅÖÂʹµØÇòÄϼ«ÉÏ¿ÕµÄa²ã³öÏÖÁË400¶àÍòƽ·½¹«ÀïµÄ¿Õ¶´£¬Óк¦ÓîÖæÏß³¤ÇýÖ±È룬°Ñb·Ö½â£¬ÃܶȽÏСµÄÇâ¾Í»áÌÓÒݵ½ÓîÖæ¿Õ¼ä£¬Ê£ÏµÄÑõ×îÖÕ»áʹÍÁÈÀc£¬´Ó¶øʹµØÇòÈËÀàÕýÔÚÖص¸»ðÐǵĸ²ÕÞ¡£¸ù¾ÝÒÔÉÏÐðÊö£¬»Ø´ðÎÊÌâ¡£
¢ÙÌî³ä£ºa____b____c_____¡£
¢Úд³öaÓëb¶ÔÓ¦µÄ»¯Ñ§·½³Ìʽ£ºa_________b________¡£
£¨2£©¾Ý¡¶Öйú»·¾³±¨¡·±¨µÀ£º´ÓÒ»·Ý¿Æ¼¼¹¥¹Ø¿ÎÌâÑо¿½á¹ûÏÔʾ£¬ÎÒ¹úËáÓêÇøÒÑÕ¼¹úÍÁÃæ»ýµÄ40%¡£Ñо¿½á¹û»¹±íÃ÷£¬ËáÓê¶ÔÎÒ¹úÅ©×÷Îï¡¢ÉÁÖµÈÓ°ÏìÇøÓò´ó¡£
ÈçͼÊÇÑо¿ËáÓê³ÉÒòµÄѧÉúʵÑéÓõġ°´ß»¯°ô¡±¡£ÓÃÁ½¸ùÍâÃæÌ×Óв£Á§¹ÜµÄ´Öµ¼Ïß´©¹ýÏðƤÈû²¢¹Ì¶¨ÓÚ´Ö²£Á§¹ÜÖУ¬ÔÚÆäÖÐÒ»¶ËÓõçÈÈË¿Á¬½ÓÆðÀ´£¬¼´ÖƳɡ°´ß»¯°ô¡±¡£
ʵÑéʱ£¬ÏȽÓֱͨÁ÷µçÔ´£¬Ê¹µçÈÈË¿ºìÈÈ£¬È»ºó½«ºìÈȵĵçÈÈË¿ÉìÈë×°ÓÐSO2ºÍ¿ÕÆøµÄ¼¯ÆøÆ¿ÖУ¬Æ¿ÖÐÁ¢¼´³öÏÖ_____ ÏÖÏó£¬ÔÙÍùÆäÖмÓÈëÑÎËáËữµÄÂÈ»¯±µÈÜÒº£¬ÓÖ³öÏÖ______ÏÖÏó¡£
Çë»Ø´ð£º
¢ÙÒÔÉÏʵÑéÖпɵóöËáÓê³ÉÒòµÄ»¯Ñ§ÔÀíÊÇ_________¡£
¢ÚÄ¿Ç°Ò»×ùÖеȳÇÊÐÿÄêÓÃúԼ300Íò¶Ö£¬Æ京ÁòÁ¿Èç°´1%¼ÆË㣬ÔòÿÄêÅÅ·ÅSO2¶àÉÙ¶Ö£¿Èô´Ë¶þÑõ»¯ÁòÓÐ60%ת»¯ÎªÁòËᣬÏ൱ÓÚÉú³É¶àÉÙ¶Ö98%ÁòË᣿
¢ÛΪÁË·ÀÖÎËáÓ꣬½µµÍúȼÉÕʱÏò´óÆøÅŷŵÄSO2£¬¹¤ÒµÉϽ«Éúʯ»ÒºÍº¬Áòú»ìºÏºóʹÓá£Çëд³öȼÉÕʱ£¬Óйء°¹ÌÁò¡±£¨²»Ê¹ÁòµÄ»¯ºÏÎï½øÈë´óÆø£©·´Ó¦µÄ»¯Ñ§·½³Ìʽ______,²¢±È½Ï´Ë·¨Ó뽫¡°Ê¯»Òʯ·ÛδÓ뺬Áòú»ìºÏ¡±Ê¹Ó÷ÀÖÎËáÓêµÄ·½·¨£¬Äĸö¸üºÃЩ£¿´ð_________£¨Ìî¡°Éúʯ»Ò·¨¡±»ò¡°Ê¯»Òʯ·¨¡±£©
¢ÜÈçÿ¸ôÒ»¶Îʱ¼ä²â¶¨Ä³·ÝÓêË®£¨ËáÓ꣩ÑùÆ·µÄpH£¬Çë×÷³öÓйØʱ¼äÓëËáÓêpH±ä»¯µÄÇúÏßͼ¡£
¢Ý¹ú¼ÊÉÏ×îвÉÓá°±¥ºÍÑÇÁòËáÄÆÈÜÒºÎüÊÕ·¨¡±£¬Çëд³öÓйط´Ó¦µÄ»¯Ñ§·½³Ìʽ______¡£
£¨1£©¢Ù³ôÑõ²ã£»Ë®£»Ëữ¡£¢Ú2O33O2£»2H2O2H2¡ü+O2¡ü
£¨2£©¢Ù¿ÕÆøÖеÄSO2Óöµ½¿ó³¾»òúÑ̵ȶÔSO2µÄÑõ»¯Óд߻¯×÷ÓõĿÅÁ£¾Í»á±»Ñõ»¯ÐγÉËáÓê¡£
¢Ú6Íò¶Ö£»56250t¡£
¢ÛCaO+SO2=CaSO3, 2CaSO3+O2="2" CaSO4£»Éúʯ»Ò·¨¡£
¢Ü
¢ÝNa2SO3+SO2+H2O=2NaHSO3£¬2NaHSO3= Na2SO3+SO2+H2O¡£
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©¢Ù¸ù¾ÝÒÑÖªµÄÌâ¸ÉÐÅÏ¢¿ÉÅжϣ¬a¡¢b¡¢c·Ö±ðÊdzôÑõ²ã¡¢Ë®ºÍÑõÆø¡£
¢ÚaºÍb·Ö±ðÊÇÊdzôÑõºÍË®µÄ·Ö½â£¬ËùÒÔ·´Ó¦µÄ»¯Ñ§·½³Ìʽ·Ö±ðÊÇ2O33O2£»2H2O2H2¡ü+O2¡ü¡£
£¨2£©¢ÙÓÉÓÚ¿ÕÆøÖеÄSO2Óöµ½¿ó³¾»òúÑ̵ȶÔSO2µÄÑõ»¯Óд߻¯×÷Óã¬ËùÒÔ·´Ó¦ÖÐÓÍÁòËáÉú³É£¬´Ó¶øÐγÉËáÓê¡£
¢ÚÿÄêÅÅ·ÅSO2µÄÖÊÁ¿ÊÇ¡£
SO2 ¡« H2SO4
64t 98t
60000t¡Á60% m¡Á98%
½âµÃm£½56250t
¢ÛSO2ÊÇËáÐÔÑõ»¯ÎÄܺÍÉúʯ»Ò·´Ó¦Éú³ÉÑÇÁòËá¸Æ£¬ÑÇÁòËá¸Æ²»Îȶ¨£¬Ò×±»¿ÕÆøÑõ»¯Éú³ÉÁòËá¸Æ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇCaO+SO2=CaSO3, 2CaSO3+O2="2" CaSO4¡£ÓÉÓÚ´óÀíʯÔÚ·Ö½âʱ»¹Éú³ÉCO2£¬Ôì³ÉÎÂÊÒЧӦ£¬ËùÒÔÉúʯ»Ò·¨½ÏºÃ¡£
¢ÜËæ×Åʱ¼äµÄÍÆÒÆ£¬ËáÓêÖеÄÑÇÁòËáÖð½¥±»Ñõ»¯Éú³ÉÇ¿ËáÁòËᣬËùÒÔpH½µµÍ£¬×îÖÕ²»ÔÙ·¢Éú±ä»¯£¬ËùÒÔͼÏñÊÇ
¢ÝÑÇÁòËáÄÆÄÜÎüÊÕSO2Éú³ÉÑÇÁòËáÇâÄÆ£¬ÑÇÁòËáÇâÄÆ·Ö½âÓÖ²úÉúSO2£¬ËùÒÔ·´Ó¦µÄ»¯Ñ§·½³Ìʽ·Ö±ðÊÇNa2SO3+SO2+H2O£½2NaHSO3£¬2NaHSO3£½ Na2SO3+SO2+H2O¡£
¿¼µã£º¿¼²éËáÓêÐγɵÄÔÀí¡¢·ÀÖΡ¢ÒÔ¼°ÓйؼÆËã
µãÆÀ£º¸ÃÌâÊÇÖеÈÄѶȵÄÊÔÌ⣬ÊÔÌâ»ù´¡ÐÔÇ¿£¬ÄÑÒ×ÊÊÖУ¬²àÖØ¿¼²éѧÉú·ÖÎöÎÊÌâ¡¢½â¾öÎÊÌâµÄÄÜÁ¦¡£¸ÃÌâÓÐÀûÓÚÅàÑøѧÉúµÄ»·¾³±£»¤Òâʶ£¬ÔöǿѧÉúµÄÉç»áÔðÈθС£