ÌâÄ¿ÄÚÈÝ

[2012¡¤Ì«Ô­¶þÄ£]ÔÚT¡æʱ£¬½«a g NH3ÍêÈ«ÈÜÓÚË®£¬µÃµ½V mLÈÜÒº£¬¼ÙÉè¸ÃÈÜÒºµÄÃܶÈΪ¦Ñ g¡¤cm£­3£¬ÈÜÖʵÄÖÊÁ¿·ÖÊýΪw£¬ÆäÖк¬NHµÄÎïÖʵÄÁ¿Îªb mol¡£ÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÈÜÖʵÄÖÊÁ¿·ÖÊýΪw£½¡Á100%
B£®ÈÜÖʵÄÎïÖʵÄÁ¿Å¨¶Èc£½ mol¡¤L£­1
C£®ÈÜÒºÖÐc(OH£­)£½ mol¡¤L£­1
D£®ÉÏÊöÈÜÒºÖÐÔÙ¼ÓÈëV mLË®ºó£¬ËùµÃÈÜÒºÈÜÖʵÄÖÊÁ¿·ÖÊý´óÓÚ0.5w
B
¸ù¾ÝÌâÖиø³öµÄÒÑÖªÁ¿¼°¸÷Ñ¡ÏîµÄÒªÇó£¬ÀûÓôýÇóÁ¿µÄ×î»ù±¾¼ÆËã¹Øϵ´úÈëÇó½â¼´¿É¡£A²»ÕýÈ·£¬wӦΪ¡Á100%£»¸ù¾Ý¹«Ê½c£½½øÐмÆËãÖªBÕýÈ·£»ÓÉÈÜÒºÖеĵçºÉÊغã¿ÉÖªc(OH£­)£½ mol¡¤L£­1£«c(H£«)£¬C´íÎó£»ÒòΪ°±Ë®µÄÃܶÈСÓÚË®µÄÃܶȣ¬¹ÊÉÏÊöÈÜÒºÔÙ¼ÓV mLË®ºó£¬ËùµÃÈÜÒºÈÜÖʵÄÖÊÁ¿·ÖÊýСÓÚ0.5w£¬¹ÊD²»ÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨16·Ö£©50mL 0.50mol/LÑÎËá¸ú50mL 0.55 mol/L NaOHÈÜÒºÔÚÓÒͼËùʾµÄ×°ÖÃÖнøÐÐÖкͷ´Ó¦£¬Í¨¹ý²â¶¨·´Ó¦¹ý³ÌÖÐËù·Å³öµÄÈÈÁ¿¿É¼ÆËã·´Ó¦ÈÈ¡£
(1)ÉÕ±­¼äÌîÂúÅÝÄ­ËÜÁϵÄ×÷ÓÃÊÇ                               £»
(2)´óÉÕ±­ÉÏÈô²»¸ÇÓ²Ö½°å£¬ÇóµÃµÄÖкÍÈÈÊýÖµ         £¨Ìî¡°Æ«´ó¡±¡¢ ¡°Æ«Ð¡¡±¡¢¡°ÎÞÓ°Ï족£©
(3)ÈçÏÂͼËùʾ£¬ÒÇÆ÷AµÄÃû³ÆÊÇ_______________£»ÔÚʵÑé¹ý³ÌÖУ¬Èç¹û²»°ÑζȼÆÉϵÄËáÓÃË®³åÏ´¸É¾»Ö±½Ó²âÁ¿NaOHÈÜÒºµÄζȣ¬Ôò²âµÃµÄ¡÷H     -57.3KJ/mol£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©£»

(4)ʵÑéÖиÄÓÃ80mL 0.50mol/LÑÎËá¸ú100mL 0.55 mol/L NaOHÈÜÒº½øÐз´Ó¦£¬ÓëÉÏÊöʵÑéÏà±È£¬Ëù·Å³öµÄÈÈÁ¿             £¨Ìî¡°ÏàµÈ¡¢¡°²»ÏàµÈ¡±)£¬
ËùÇóÖкÍÈÈ              £¨Ìî¡°ÏàµÈ¡¢¡°²»ÏàµÈ¡±) ¡£
(5)ÓÃÏàͬŨ¶ÈºÍÌå»ýµÄ°±Ë®´úÌæNaOHÈÜÒº½øÐÐÉÏÊöʵÑ飬²âµÃµÄÖкÍÈȵÄÊýÖµ»á          £»£¨¾ùÌî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°ÎÞÓ°Ï족£©
(6)ÀíÂÛÉÏÏ¡Ç¿Ëᡢϡǿ¼î·´Ó¦Éú³É1molˮʱ·Å³ö57.3kJµÄÈÈÁ¿£¬Ð´³öÏ¡ÁòËáºÍÏ¡ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÖкÍÈȵÄÈÈ»¯Ñ§·½³Ìʽ                                  £»

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø