ÌâÄ¿ÄÚÈÝ
£¨¹²10·Ö£©ÒÑÖª°±¿ÉÒÔÓë×ÆÈȵÄÑõ»¯Í·´Ó¦µÃµ½µªÆøºÍ½ðÊôÍ£¬·´Ó¦·½³ÌʽΪ2NH3£«3CuO N2£«3H2O£«3Cu£¬ÓÃʾÒâͼÖеÄ×°ÖÿÉÒÔʵÏָ÷´Ó¦¡£»Ø´ðÏÂÁÐÎÊÌ⣺
(1£©AÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ ¡£¼ìÑé°±Æøͨ³£²ÉÓõķ½·¨¼°ÏÖÏóÊÇ_________ ______£¬ ¡£
(2£©BÖмÓÈëµÄÎïÖÊÊÇ £¬Æä×÷ÓÃÊÇ ¡£
(3£©ÊµÑéʱCÖй۲쵽µÄÏÖÏóÊÇ £¬¸Ã·´Ó¦Öа±µÄ×÷ÓÃÊÇ_______¼Á¡£
(4£©ÈôÒª¼ìÑé·´Ó¦Éú³ÉµÄË®£¬¿É½«ÊÔ¹ÜD¼°ÉÕ±²¿·Ö¸Ä³ÉÁ½¸öÏàÁ¬µÄ¸ÉÔï¹Ü£¬µÚÒ»¸ö¸ÉÔï¹ÜXÄÚ×°ÓÐ_____________£¬ÏÖÏóÊÇ___________________£»µÚ¶þ¸ö¸ÉÔï¹ÜYÄÚ×°Óмîʯ»Ò£¬×÷ÓÃÊÇ____________________________¡£
£¨1£©2NH4Cl+Ca(OH)22NH3¡ü+CaCl2+2H2O (1·Ö)
ÓÃʪÈóµÄºìɫʯÈïÊÔÖ½£¨1·Ö£©£¬ÊÔÖ½±äÀ¶£¨1·Ö£©
£¨2£©¼îʯ»Ò£¬£¨1·Ö£©³ýÈ¥°±Ë®ÖеÄË®ÕôÆû£¨1·Ö£©
£¨3£©ºÚÉ«¹ÌÌåÖð½¥±ä³ÉºìÉ«£¨1·Ö£©£¬»¹Ô£¨1·Ö£©
£¨4£©ÎÞË®ÁòËáÍ£¨1·Ö£©£¬±äÀ¶£¨1·Ö£©
·ÀÖ¹EÖеÄË®ÕôÆû½øÈë¸ÉÔï¹Üx£¬Ó°ÏìË®µÄ¼ìÑé¡££¨1·Ö£©
½âÎö