ÌâÄ¿ÄÚÈÝ
(12·Ö) Ë®ÊÇÉúÃüÖ®Ô´£¬ËüÓëÎÒÃǵÄÉú»îÃÜÇÐÏà¹Ø¡£ÔÚ»¯Ñ§ÊµÑéºÍ¿ÆѧÑо¿ÖУ¬Ë®Ò²ÊÇÒ»ÖÖ³£ÓõÄÊÔ¼Á¡£¸ù¾ÝÏÂÁÐÐÅÏ¢»Ø´ðÎÊÌ⣺
£¨1£©»ù̬ÑõÔ×Ó¼Û²ãµç×ӵĵç×ÓÅŲ¼Í¼Îª____________
£¨2£©Ð´³öÁ½ÖÖÓëH2O·Ö×Ó»¥ÎªµÈµç×ÓÌåµÄ΢Á£ ¡¢
£¨3£©ÏÂÁйØÓÚË®µÄ˵·¨ÕýÈ·µÄÊÇ__________£¨Ñ¡ÌîÐòºÅ£©¡£
A¡¢´¿Ë®³ÊÖÐÐÔ£¬ËùÒÔÔÚÈκÎÌõ¼þÏ´¿Ë®µÄpH¾ùΪ7£»
B¡¢Ë®·Ö×ÓÊÇÓɼ«ÐÔ¼ü¹¹³ÉµÄ¼«ÐÔ·Ö×Ó£»
C¡¢Ë®ÔÚ»¯Ñ§·´Ó¦ÖпÉÒÔ×÷Ñõ»¯¼Á£¬Ò²¿ÉÒÔ×÷»¹Ô¼Á£»
D¡¢Ë®·Ö×ÓÖмȺ¬¦Ò¼ü£¬ÓÖº¬ÓЦмü£»
£¨4£©Ë®·Ö×ÓÔÚÌض¨Ìõ¼þÏÂÈÝÒ׵õ½Ò»¸öH£«£¬ÐγÉË®ºÏÇâÀë×Ó£¨H3O£«£©¡£ÏÂÁжÔÉÏÊö¹ý³ÌµÄÃèÊö²»ºÏÀíµÄÊÇ
A£®ÑõÔ×ÓµÄÔÓ»¯ÀàÐÍ·¢ÉúÁ˸ıä B£®Î¢Á£µÄ¿Õ¼ä¹¹ÐÍ·¢ÉúÁ˸ıä
C£®Î¢Á£µÄ»¯Ñ§ÐÔÖÊ·¢ÉúÁ˸ıä
£¨5£©ÏÂÁÐÊÇÄÆ¡¢µâ¡¢½ð¸Õʯ¡¢¸É±ù¡¢ÂÈ»¯Äƾ§ÌåµÄ¾§°ûͼ(δ°´Ë³ÐòÅÅÐò)¡£Óë±ùµÄ¾§ÌåÀàÐÍÏàͬµÄÊÇ (ÇëÓÃÏàÓ¦µÄ±àºÅÌîд)
£¨6£©ÔÚ±ù¾§ÌåÖУ¬Ã¿¸öË®·Ö×ÓÓëÏàÁÚµÄ4¸öË®·Ö×ÓÐγÉÇâ¼ü(ÈçͼËùʾ)£¬ÒÑÖª±ùµÄÉý»ªÈÈÊÇ51kJ/mol£¬³ýÇâ¼üÍ⣬ˮ·Ö×Ӽ仹´æÔÚ·¶µÂ»ªÁ¦(11 kJ/mol)£¬Ôò±ù¾§ÌåÖÐÇâ¼üµÄ¡°¼üÄÜ¡±ÊÇ_________kJ/mol£»
£¨7£©½«°×É«µÄÎÞË®CuSO4ÈܽâÓÚË®ÖУ¬ÈÜÒº³ÊÀ¶É«£¬ÊÇÒòΪÉú³ÉÁËÒ»ÖÖ³ÊÀ¶É«µÄÅäºÏÀë×Ó¡£Çëд³öÉú³É´ËÅäºÏÀë×ÓµÄÀë×Ó·½³Ìʽ£º ¡£
(12·Ö)£¨1£©£¨2£©H2S NH2¡¥ £¨3£©BC £¨4£©A
(5)BC (6)20 (7) Cu2+ + 4H2O = Cu(H2O)42+
¡¾½âÎö¡¿
£¨12·Ö £©Ë®ÊÇÉúÃüÖ®Ô´£¬ËüÓëÎÒÃǵÄÉú»îÃÜÇÐÏà¹Ø¡£ÔÚ»¯Ñ§ÊµÑéºÍ¿ÆѧÑо¿ÖУ¬Ë®Ò²ÊÇÒ»ÖÖ³£ÓõÄÊÔ¼Á¡£
£¨1£©Ë®·Ö×ÓÖÐÑõÔ×ÓÔÚ»ù̬ʱºËÍâµç×ÓÅŲ¼Ê½Îª_ __£»
£¨2£©Ð´³öÓëH2O·Ö×Ó»¥ÎªµÈµç×ÓÌåµÄ΢Á£____£¨Ìî1ÖÖ£©¡£
£¨3£©Ë®·Ö×ÓÔÚÌض¨Ìõ¼þÏÂÈÝÒ׵õ½Ò»¸öH£«£¬ÐγÉË®ºÏÇâÀë×Ó£¨H3O£«£©¡£ÏÂÁжÔÉÏÊö¹ý³ÌµÄÃèÊö²»ºÏÀíµÄÊÇ_____
A£®ÑõÔ×ÓµÄÔÓ»¯ÀàÐÍ·¢ÉúÁ˸ıä |
B£®Î¢Á£µÄÐÎ×´·¢ÉúÁË¸Ä±ä µÚ 6Ò³ ¹² 8Ò³ |
C£®Î¢Á£µÄ»¯Ñ§ÐÔÖÊ·¢ÉúÁ˸ıä |
D£®Î¢Á£Öеļü½Ç·¢ÉúÁ˸ıä |
£¨5£©ÔÚ±ù¾§ÌåÖУ¬Ã¿¸öË®·Ö×ÓÓëÏàÁÚµÄ4¸öË®·Ö×ÓÐγÉÇâ¼ü(ÈçͼËùʾ)£¬ÒÑÖª±ùµÄÉý»ªÈÈÊÇ51 kJ/mol£¬³ýÇâ¼üÍ⣬ˮ·Ö×Ӽ仹´æÔÚ·¶µÂ»ªÁ¦(11 kJ/mol)£¬Ôò±ù¾§ÌåÖÐÇâ¼üµÄ¡°¼üÄÜ¡±ÊÇ_________kJ/mol£»
£¨6£©½«°×É«µÄÎÞË®CuSO4ÈܽâÓÚË®ÖУ¬ÈÜÒº³ÊÀ¶É«£¬ÊÇÒòΪÉú³ÉÁËÒ»ÖÖ³ÊÀ¶É«µÄÅäºÏÀë×Ó¡£
Çëд³öÉú³É´ËÅäºÏÀë×ÓµÄÀë×Ó·½³Ìʽ£º___ ¡£
(12·Ö)Ë®ÊÇÉúÃüÖ®Ô´£¬ËüÓëÎÒÃǵÄÉú»îÃÜÇÐÏà¹Ø¡£ÔÚ»¯Ñ§ÊµÑéºÍ¿ÆѧÑо¿ÖУ¬Ë®Ò²ÊÇÒ»ÖÖ³£ÓõÄÊÔ¼Á¡£
£¨1£©Ë®·Ö×ÓÖÐÑõÔ×ÓÔÚ»ù̬ʱºËÍâµç×ÓÅŲ¼Ê½Îª_____ _____£»
£¨2£©Ð´³öÓëH2O·Ö×Ó»¥ÎªµÈµç×ÓÌåµÄ΢Á£__ ________£¨Ìî2ÖÖ£©¡£
£¨3£©Ë®·Ö×ÓÔÚÌض¨Ìõ¼þÏÂÈÝÒ׵õ½Ò»¸öH£«£¬ÐγÉË®ºÏÇâÀë×Ó£¨H3O£«£©¡£ÏÂÁжÔÉÏÊö¹ý³ÌµÄÃèÊö²»ºÏÀíµÄÊÇ_ ____
A£®ÑõÔ×ÓµÄÔÓ»¯ÀàÐÍ·¢ÉúÁ˸ıä | B£®Î¢Á£µÄÐÎ×´·¢ÉúÁ˸ıä |
C£®Î¢Á£µÄ»¯Ñ§ÐÔÖÊ·¢ÉúÁ˸ıä | D£®Î¢Á£Öеļü½Ç·¢ÉúÁ˸ıä |
£¨5£©ÔÚ±ù¾§ÌåÖУ¬Ã¿¸öË®·Ö×ÓÓëÏàÁÚµÄ4¸öË®·Ö×ÓÐγÉÇâ¼ü(ÈçͼËùʾ)£¬ÒÑÖª±ùµÄÉý»ªÈÈÊÇ51 kJ/mol£¬³ýÇâ¼üÍ⣬ˮ·Ö×Ӽ仹´æÔÚ·¶µÂ»ªÁ¦(11 kJ/mol)£¬Ôò±ù¾§ÌåÖÐÇâ¼üµÄ¡°¼üÄÜ¡±ÊÇ_________kJ/mol£»
£¨6£©½«°×É«µÄÎÞË®CuSO4ÈܽâÓÚË®ÖУ¬ÈÜÒº³ÊÀ¶É«£¬ÊÇÒòΪÉú³ÉÁËÒ»ÖÖ³ÊÀ¶É«µÄÅäºÏÀë×Ó¡£Çëд³öÉú³É´ËÅäºÏÀë×ÓµÄÀë×Ó·½³Ìʽ£º ¡£