ÌâÄ¿ÄÚÈÝ

»¯¹¤Éú²úÖÐÓÃÍéÌþºÍË®ÕôÆø·´Ó¦µÃµ½ÒÔCOºÍH2ΪÖ÷µÄ»ìºÏÆøÌ壬ÕâÖÖ»ìºÏÆøÌå¿ÉÓÃÓÚÉú²ú¼×´¼»òºÏ³É°±£¬¶Ô¼×Íé¶øÑÔ£¬ÓÐÈçÏÂÁ½¸öÖ÷Òª·´Ó¦£º
¢ÙCH4(g)+1/2O2(g) CO(g)+2H2(g)  ¦¤H1=£­36 kJ¡¤mol-1
¢ÚCH4(g)+H2O(g) CO(g)+3H2(g)  ¦¤H2="+216" kJ¡¤mol-1
ÓÉ·´Ó¦¢Ù¢ÚÍƳö×Ü·´Ó¦ÈÈΪÁãµÄ×Ü·´Ó¦·½³Ìʽ¢Û£¬²¢Çó½øÁÏÆøÖпÕÆø(O2µÄÌå»ý·ÖÊýΪ21%)ÓëË®ÕôÆøµÄÌå»ý±È¡£
100¡Ã7
´ÓËù¸øµÄÈÈ»¯Ñ§·½³Ìʽ¿É¿´³ö£º216/36=6,½«¢Ù¡Á6µÃ³öʽ×ÓÓë¢ÚÏà¼Ó£º
6CH4+3O26CO+12H2
+)CH4+H2OCO+3H2
7CH4+3O2+H2O7CO+15H2¡£
ËùÒÔ×Ü·´Ó¦Ê½¢ÛΪ
7CH4(g)+3O2(g)+H2O(g)7CO(g)+15H2(g)  ¦¤H=0
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø