ÌâÄ¿ÄÚÈÝ
£¨2011?¸§Ë³¶þÄ££©Ä³ÈÜÒºÖÐÖ»¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеļ¸ÖÖ£ºNa+¡¢NH4+¡¢Cl-¡¢SO42-¡¢CO32-£¨²»¿¼ÂÇÉÙÁ¿µÄH+ÓëOH-£©£¬·Ö±ðÈ¡100mL¸ÃÈÜÒº½øÐÐÒÔÏÂʵÑ飺¢ÙÈô¼ÓÈë×ãÁ¿µÄÉռ¼ÓÈÈ£¬²úÉú224mL£¨±ê×¼×´¿öÏ£©ÆøÌ壻¢ÚÈôÏȼÓÈë×ãÁ¿µÄHNO3ÎÞÏÖÏó£¬ÔÙ¼ÓÈë×ãÁ¿µÄBa£¨NO3£©2£¬µÃµ½2.33g¹ÌÌ壮Ôò¸ÃÈÜÒº£¨¡¡¡¡£©
·ÖÎö£ºÊµÑé¢Ù£ºµÚÒ»·Ý¼ÓÈë×ãÁ¿µÄÉռ¼ÓÈÈ»á²úÉúÆøÌåÖ¤Ã÷º¬ÓÐNH4+£¬ÊµÑé¢Ú£ºµÚ¶þ·ÝÏȼÓÈë×ãÁ¿µÄÑÎËᣬÎÞÏÖÏó£¬Ôò²»º¬ÓÐCO32-£¬ÔÙ¼Ó×ãÁ¿µÄBaCl2ÈÜÒº£¬µÃ¹ÌÌå2.33g£¬Ö¤Ã÷º¬ÓÐSO42-£¬¾Ý´Ë½øÐзÖÎö£®
½â´ð£º½â£º¸ù¾ÝʵÑé¢Ù£ºµÚÒ»·Ý¼ÓÈë×ãÁ¿µÄÉռ¼ÓÈÈ£¬»á²úÉúÆøÌå224mL£¬Ö¤Ã÷º¬ÓÐNH4+£¬ÇÒÎïÖʵÄÁ¿Îª0.01mol£»
ʵÑé¢Ú£ºµÚ¶þ·ÝÏȼÓÈë×ãÁ¿µÄÑÎËᣬÎÞÏÖÏó£¬ÔòÒ»¶¨²»º¬ÓÐCO32-£¬ÔÙ¼Ó×ãÁ¿µÄBaCl2ÈÜÒº£¬µÃ¹ÌÌå2.33g£¬Ö¤Ã÷Ò»¶¨º¬ÓÐSO42-£¬ÇÒÎïÖʵÄÁ¿Îª£º
=0.01mol£¬¸ù¾ÝÈÜÒºÖеĵçºÉÊغ㣬ÔòÒ»¶¨º¬ÓÐÄÆÀë×Ó£¬ÇÒÄÆÀë×ÓµÄŨ¶È¡Ý
=0.1mol/L£¬
A¡¢¸ù¾ÝÒÔÉÏ·ÖÎö£¬²»ÄÜÈ·¶¨º¬ÓÐÂÈÀë×Ó£¬¹ÊA´íÎó£»
B¡¢¸ÃÈÜÒºÖп϶¨º¬ÓÐNH4+¡¢S042-¡¢Na+£¬¿ÉÄܺ¬ÓÐÂÈÀë×Ó£¬¹ÊB´íÎó£»
C¡¢¸ù¾ÝÈÜÒºÖÐNH4+ÎïÖʵÄÁ¿Îª0.01mol£¬SO42-ÎïÖʵÄÁ¿Îª0.01mol£¬¸ù¾ÝµçºÉÊغãÔòc£¨Na+£©¡Ý0.1 mol/L£¬¹ÊCÕýÈ·£»
D¡¢Ò»¶¨²»»á̼Ëá¸ùÀë×Ó£¬¿ÉÄܺ¬ÓÐÂÈÀë×Ó£¬¹ÊD´íÎó£»
¹ÊÑ¡C£®
ʵÑé¢Ú£ºµÚ¶þ·ÝÏȼÓÈë×ãÁ¿µÄÑÎËᣬÎÞÏÖÏó£¬ÔòÒ»¶¨²»º¬ÓÐCO32-£¬ÔÙ¼Ó×ãÁ¿µÄBaCl2ÈÜÒº£¬µÃ¹ÌÌå2.33g£¬Ö¤Ã÷Ò»¶¨º¬ÓÐSO42-£¬ÇÒÎïÖʵÄÁ¿Îª£º
2.33g |
233g/mol |
0.01mol¡Á2-0.01mol |
0.1L |
A¡¢¸ù¾ÝÒÔÉÏ·ÖÎö£¬²»ÄÜÈ·¶¨º¬ÓÐÂÈÀë×Ó£¬¹ÊA´íÎó£»
B¡¢¸ÃÈÜÒºÖп϶¨º¬ÓÐNH4+¡¢S042-¡¢Na+£¬¿ÉÄܺ¬ÓÐÂÈÀë×Ó£¬¹ÊB´íÎó£»
C¡¢¸ù¾ÝÈÜÒºÖÐNH4+ÎïÖʵÄÁ¿Îª0.01mol£¬SO42-ÎïÖʵÄÁ¿Îª0.01mol£¬¸ù¾ÝµçºÉÊغãÔòc£¨Na+£©¡Ý0.1 mol/L£¬¹ÊCÕýÈ·£»
D¡¢Ò»¶¨²»»á̼Ëá¸ùÀë×Ó£¬¿ÉÄܺ¬ÓÐÂÈÀë×Ó£¬¹ÊD´íÎó£»
¹ÊÑ¡C£®
µãÆÀ£º±¾Ì⿼²éÁË»ìºÏÎï³É·ÖµÄ¼ø±ð£¬Íê³É´ËÌ⣬¿ÉÒÔÒÀ¾ÝÎïÖʵÄÐÔÖʽøÐУ¬×¢Òâ³£¼ûÀë×ÓÖ®¼äµÄ·´Ó¦ÒÔ¼°ÏÖÏ󣬱¾ÌâÄѶȲ»´ó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿