ÌâÄ¿ÄÚÈÝ
£¨10·Ö£©FeºÍAlÊÇÁ½ÖÖ³£ÓõĽðÊô£¬ÏÖ½«ËüÃÇ°´Ò»¶¨µÄÖÊÁ¿±È×é³É¾ùÔȵĻìºÏÎï¡£
£¨1£©È¡Ò»¶¨ÖÊÁ¿µÄ¸Ã»ìºÏÎÏòÆäÖмÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬Éú³ÉÆøÌåµÄÌå»ýÔÚ±ê×¼×´¿öÏÂΪn L£¬Ôò·´Ó¦µÄÀë×Ó·½³ÌʽΪ ¡£
»ìºÏÎïÖÐAlµÄÎïÖʵÄÁ¿Îª £¨Óú¬×ÖĸµÄÊýѧʽ±íʾ£©¡£
£¨2£©ÁíÈ¡ÏàͬÖÊÁ¿µÄ¸Ã»ìºÏÎÏòÆäÖмÓÈë×ãÁ¿µÄÏ¡ÁòËᣬ¹ÌÌåÈ«²¿Èܽ⣬Éú³ÉÆøÌåµÄÌå»ýÔÚ±ê×¼×´¿öÏÂΪmL£¬Ôò·´Ó¦ÖÐתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª £¬»ìºÏÎïÖÐFeµÄÖÊÁ¿Îª £¨Óú¬×ÖĸµÄÊýѧʽ±íʾ£©¡£
£¨1£©2Al+2OH-+2H2O===2AlO2-+3H2¡ü£»n/33.6 mol£¨¸÷2·Ö£©
£¨2£©m/11.2 mol £» 2.5£¨m¡ªn£©g£¨¸÷3·Ö£©
¡¾½âÎö¡¿(1)Á½½ðÊôÖÐÖ»ÓÐÂÁ²ÅºÍ¼îÈÜÒº·´Ó¦²úÉúÇâÆø£¬¹ÊÓÉÇâÆøµÄÌå»ýÇóµÃÂÁµÄÖÊÁ¿
£¨2£©·¢ÉúµÄ·´Ó¦Îª£º2Al+2OH-+2H2O===2AlO2-+3H2¡ü Fe£«2H£«=Fe2£«£«H2¡ü
ÓÉ·´Ó¦·½³Ìʽ¿É¿´³öÿ²úÉú1molÇâÆøÔòÓÐ2molµç×ÓµÄתÒÆ£¬¹Ê·´Ó¦ÖÐתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª= m/11.2 mol£»
Óɵç×ӵĵÃʧÊغã¿ÉÖª£¨ÉèÌúµÄÖÊÁ¿Îªx g£©£¬½âµÃx=2.5£¨m¡ªn£©g