ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©

£¨1£©ÏòNa2CO3µÄŨÈÜÒºÖÐÖðµÎ¼ÓÈëÏ¡ÑÎËᣬֱµ½²»ÔÙÉú³ÉCO2ÆøÌåΪֹ£¬ÔòÔڴ˹ý³ÌÖУ¬ÈÜÒºµÄc(HCO3£­)±ä»¯Ç÷ÊÆ¿ÉÄÜÊÇ£º¢ÙÖð½¥¼õС£»¢ÚÖð½¥Ôö´ó£»¢ÛÏÈÖð½¥Ôö´ó£¬¶øºó¼õС£»¢ÜÏÈÖð½¥¼õС£¬¶øºóÔö´ó¡£4ÖÖÇ÷ÊÆÖпÉÄܵÄÊÇ________¡£

£¨2£©pHÏàͬµÄHClÈÜÒº¡¢H2SO4ÈÜÒº¡¢CH3COOHÈÜÒº¸÷100 mL¡£

¢Ù·Ö±ðÓÃ0.1 mol/LµÄNaOHÈÜÒºÖкͣ¬ÆäÖÐÏûºÄNaOHÈÜÒº×î¶àµÄÊÇ________£¨Ìѧʽ£©¡£

¢ÚÓëµÈÁ¿µÄп·Û·´Ó¦£¬·´Ó¦¿ªÊ¼Ê±£¬·´Ó¦ËÙÂÊ________¡£

A£®HCl×î¿ì       B£®H2SO4×î¿ì    C£®CH3COOH×î¿ì     D£®Ò»Ñù¿ì

£¨3£©Ä³Î¶ÈÏ£¬´¿Ë®ÖÐc(H£«)£½2¡Á10£­7 mol/L£¬Ôò´Ëʱ0.02mol/LBa(OH)2ÈÜÒºµÄpH =        

£¨4£©ÓÐËÄÖÖÒ»ÔªËáHA¡¢HB¡¢HC¡¢HD£¬ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄNaDºÍNaBÈÜÒºµÄpH£¬Ç°Õ߱ȺóÕß´ó£¬NaAÈÜÒº³ÊÖÐÐÔ£¬1mol/LµÄKCÈÜÒºÓö·Ó̪ÊÔÒº³ÊºìÉ«£»Í¬Ìå»ý¡¢Í¬ÎïÖʵÄÁ¿Å¨¶ÈµÄHB¡¢HCÓÃÑùµÄ×°Ö÷ֱð×÷µ¼µçÐÔÊÔÑ飬·¢ÏÖºóÕߵĵÆÅݱÈǰÕßÁÁ£¬ÔòÕâËÄÖÖËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòΪ________________________¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø