ÌâÄ¿ÄÚÈÝ

(10·Ö)£¨1£©AgNO3µÄË®ÈÜÒº³Ê                £¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£º                ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡            £»

£¨2£©ÂÈ»¯ÂÁË®ÈÜÒº³Ê       ÐÔ £¬£¨Ìî¡°Ëᡱ¡¢¡°ÖС±¡¢¡°¼î¡±£©ÐÔ£¬Ô­ÒòÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±í

ʾ£©£º                                                            ;

°ÑAlCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóµÃµ½µÄÖ÷Òª¹ÌÌå²úÎïÊÇ                     ¡£

(3) ÒÑÖªMgCl2¡¤6H2O¾§ÌåÔÚ¿ÕÆøÖмÓÈÈʱ£¬ÊͷŲ¿·Ö½á¾§Ë®£¬Í¬Ê±Éú³ÉMg(OH)Cl£¨¼îʽÂÈ»¯Ã¾£©»òÉú³ÉMgO¡£ÏÂÁÐÊǹØÓÚMgCl2¡¤6H2OµÄ×ÛºÏÓ¦Óãº

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙÔÚÉÏͼµÄÀ¨ºÅÄÚÓ¦ÌîµÄÊÇÔÚ_______________»·¾³ÖмÓÈÈ¡£

¢ÚMg(OH)2¹ÌÌå´æÔÚÈçÏÂÈܽâƽºâ£ºMg(OH)2(¹Ì) Mg2£«£«2OH£­¡£ÏòÌåϵÖмÓÈ루ÇëÌî³öÁ½ÖÖ²»Í¬Àà±ðµÄÎïÖÊ£©_____________________________________________________ ÓÐÀûÓÚMg(OH)2Èܽ⡣

¢ÛÒÑÖªAnBmµÄÀë×Ó»ý£½c (Am£«) n ¡¤c (Bn£­) m£¬Ê½ÖÐc (Am£«) nºÍc (Bn£­) m±íʾÀë×ÓµÄÎïÖʵÄÁ¿Å¨¶È£¬ÔÚÊÒÎÂʱÈô²âµÃMg(OH)2±¥ºÍÈÜÒºµÄpHֵΪ11£¬ÆäÀë×Ó»ýΪ___________________¡£

 

£¨1£©Ëᣬ¡¡¡¡¡¡Ag£« £« H2O  AgOH£« H£«

£¨2£©Ëᣬ¡¡¡¡¡¡Al3£«£«3H2O  Al(OH)3£«3H£«£¬ ¡¡¡¡¡¡Al2O3   £»

(3) ¢ÙHClÆøÁ÷  ¢ÚËᡢˮ¡¢ËáÐÔÆøÌå¡¢±¥ºÍNH4ClµÈ£¨ÈÎÑ¡Á½ÖÖ£© £¨Ã¿¿Õ1·Ö£©

 ¢Û5¡Á10-10£¨2·Ö£©

½âÎö:£¨1£©AgNO3ÊÇÇ¿ËáÈõ¼îÑΣ¬Ë®½âÏÔËáÐÔ¡£

£¨2£©ÂÈ»¯ÂÁÒ²ÊÇÇ¿ËáÈõ¼îÑΣ¬Ë®½âÏÔËáÐÔ¡£ÂÁÀë×ÓË®½âÉú³ÉÇâÑõ»¯ÂÁºÍÂÈ»¯Ç⣬ˮ½âÎüÈÈ£¬¼ÓÈÈ´Ù½øË®½â¡£Í¬Ê±ÂÈ»¯ÇâµÄ»Ó·¢£¬½øÒ»²½´Ù½øË®½â£¬ËùÒÔ×îÖյõ½µÄÊÇÇâÑõ»¯ÂÁ£¬×ÆÉյõ½Ñõ»¯ÂÁ¡£

£¨3£©ÂÈ»¯Ã¾Ë®½âÏÔËáÐÔ£¬ËùÒÔÒªµÃµ½ÂÈ»¯Ã¾¾§Ì壬ÔÚ¼ÓÈÈʱÐèÒª·Àֹˮ½â£¬Òò´ËÔÚÁò»¯ÇâµÄÆøÁ÷ÖмÓÈȼ´¿É¡£¸ù¾ÝÇâÑõ»¯Ã¾µÄÈܽâƽºâ¿ÉÖª£¬Òª´Ù½øÈܽ⣬¾Í±ØÐëʹƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯¡£ËùÒÔ¿ÉÒÔͨ¹ýÏûºÄOH£­»òþÀë×ÓÀ´ÊµÏÖ¡£¸ù¾ÝÀë×Ó»ý³£ÊýµÄ¸ÅÄî¿ÉÖª£¬Àë×Ó»ý³£ÊýÊǵçÀë³öµÄÀë×ÓµÄŨ¶ÈµÄÃÝÖ®»ý£¬Mg(OH)2±¥ºÍÈÜÒºµÄpHֵΪ11£¬ÔòOH£­µÄŨ¶ÈΪ10£­3mol/L£¬ÔòþÀë×ÓŨ¶ÈΪ5¡Á10£­4mol/L£¬ËùÒÔÇâÑõ»¯Ã¾µÄÀë×Ó»ý³£ÊýΪ¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨08Äê½­ËÕ¾í£©(10·Ö)½ð¿ó¿ª²É¡¢Ò±Á¶ºÍµç¶Æ¹¤Òµ»á²úÉú´óÁ¿º¬Ç軯ºÏÎïµÄÎÛË®£¬ÆäÖк¬Ç軯ºÏÎïÒÔHCN¡¢CN -ºÍ½ðÊôÀë×ÓµÄÅäÀë×ÓM(CN)nm-µÄÐÎʽ´æÔÚÓÚË®ÖС£²â¶¨ÎÛË®Öк¬Ç軯ºÏÎﺬÁ¿µÄʵÑé²½ÖèÈçÏ£º

¢ÙË®ÑùÔ¤´¦Àí£ºË®ÑùÖмÓÈëÁ×ËáºÍEDTA£¬ÔÚpH£¼2µÄÌõ¼þϼÓÈÈÕôÁó£¬Õô³öËùÓеÄHCN£¬²¢ÓÃNaOHÈÜÒºÎüÊÕ¡£

¢ÚµÎ¶¨£º½«ÎüÊÕÒºµ÷½ÚÖÁpH£¾11£¬ÒÔÊÔÒøÁé×÷ָʾ¼Á£¬ÓÃAgNO3±ê×¼ÈÜÒºµÎ¶¨

Ag++2CN - == [Ag(CN)2] -

ÖÕµãʱ£¬ÈÜÒºÓÉ»ÆÉ«±ä³É³ÈºìÉ«¡£

¸ù¾ÝÒÔÉÏ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÅË®ÑùÔ¤´¦ÀíµÄÄ¿µÄÊÇ                                ¡£

¢ÆË®ÑùÔ¤´¦ÀíµÄ×°ÖÃÈçÓÒͼ£¬Ï¸µ¼¹Ü²åÈëÎüÊÕÒºÖÐÊÇΪÁË    ____

¢ÇÕôÁóÆ¿±ÈÎüÊÕÒºÃæÒª¸ß³öºÜ¶à£¬ÆäÄ¿µÄÊÇ                 ¡£

¢ÈÈç¹ûÓÃÑÎËá´úÌæÁ×Ëá½øÐÐÔ¤´¦Àí£¬ÊµÑé½á¹û½«           (Ìî¡°Æ«¸ß¡±¡¢¡°ÎÞÓ°Ï족»ò¡°Æ«µÍ¡±)¡£

¢É׼ȷÒÆȡij¹¤³§ÎÛË®100mL£¬¾­´¦ÀíºóÓÃŨ¶ÈΪ0.01000mol?L-1µÄÏõËáÒø±ê×¼ÈÜÒºµÎ¶¨£¬ÖÕµãʱÏûºÄÁË21.00mL¡£´ËË®ÑùÖк¬Ç軯ºÏÎïµÄº¬Á¿Îª              mg?L-1µÄ(ÒԼƣ¬¼ÆËã½á¹û±£ÁôһλСÊý)¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø