ÌâÄ¿ÄÚÈÝ

14£®ÓÐa¡¢bÁ½¸öµÈÌå»ýÇÒ¼«Ò×µ¼ÈȵÄÃܱÕÈÝÆ÷£¬a±£³ÖÈÝ»ý²»±ä£¬bÖеĻîÈû¿ÉÉÏÏÂÒƶ¯£¬ÒÔ±£³ÖÄÚÍâѹǿÏàµÈ£®ÔÚÏàͬÌõ¼þϽ«3mol A£¬1mol B·Ö±ðͬʱ»ìºÏÓÚa¡¢bÁ½ÈÝÆ÷ÖУ¬·¢Éú·´Ó¦£º3A£¨g£©+B£¨g£©?2C£¨g£©+D£¨g£©
£¨1£©´ïµ½Æ½ºâʱ£¬aÖÐAµÄŨ¶ÈΪM mol/L£®AµÄת»¯ÂÊΪN£¬bÖÐAµÄŨ¶ÈΪm mol/L£¬AµÄת»¯ÂÊΪn£¬ÔòM£¼m£»N£¼n£¨Ì¡¢£¼¡¢=¡¢ÎÞ·¨±È½Ï£©
£¨2£©±£³ÖζȲ»±ä£¬°´ÏÂÁÐÅä±È·Ö±ð³äÈëa¡¢bÁ½ÈÝÆ÷£¬´ïƽºâºó£¬aÖÐAµÄŨ¶ÈΪM mol•L-1µÄÊÇD¡¢E
A  6mol A+2mol B    B  3mol A+2mol C    C  2mol C+1mol B+1mol D
D  2mol C+1mol D    E  1.5mol C+0.5mol B+1mol C+0.5mol D£®

·ÖÎö £¨1£©a±£³ÖÈÝ»ý²»±ä£¬ÎªµÈÈݱ仯£¬b±£³ÖÄÚÍâѹǿÏàµÈ£¬ÎªµÈѹ±ä»¯£¬·¢Éú·´Ó¦3A£¨g£©+B£¨g£©?2C£¨g£©+D£¨g£©ÊÇÆøÌåÎïÖʵÄÁ¿¼õÉٵķ´Ó¦£¬¹ÊbÏ൱ÓÚÔÚaƽºâµÄ»ù´¡ÉϼÓѹ£¬Æ½ºâÓÒÒÆ£¬Æ½ºâÒƶ¯²»ÄÜÏû³ýAµÄŨ¶ÈÔö´ó£¬µ½´ïÐÂƽºâʱµÄŨ¶È¸ßÓÚԭƽºâ£¬¾Ý´Ë½â´ð£»
£¨2£©ÒªÏë´ïµ½Æ½ºâºóaÖÐAµÄŨ¶ÈΪM mol•L-1£¬ÓëÔ­ÌåϵÊǵÈЧƽºâ£¬µÈεÈÈݵÄÌõ¼þÏ£¬ÏàͬÎïÖʵÄͶÁÏÁ¿ÏàµÈ£®

½â´ð ½â£º£¨1£©a±£³ÖÈÝ»ý²»±ä£¬ÎªµÈÈݱ仯£¬b±£³ÖÄÚÍâѹǿÏàµÈ£¬ÎªµÈѹ±ä»¯£¬·¢Éú·´Ó¦3A£¨g£©+B£¨g£©?2C£¨g£©+D£¨g£©ÊÇÆøÌåÎïÖʵÄÁ¿¼õÉٵķ´Ó¦£¬¹ÊbÏ൱ÓÚÔÚaƽºâµÄ»ù´¡ÉϼÓѹ£¬Æ½ºâÓÒÒÆ£¬ËùÒÔbÖÐAµÄת»¯Âʴ󣬼´N£¼n£¬Æ½ºâÒƶ¯²»ÄÜÏû³ýAµÄŨ¶ÈÔö´ó£¬µ½´ïÐÂƽºâʱµÄŨ¶È¸ßÓÚԭƽºâ£¬¹ÊbÖÐƽºâʱAµÄŨ¶È´óÓÚaÖÐAµÄƽºâŨ¶È£¬¼´M£¼m£¬¹Ê´ð°¸Îª£º£¼£»£¼£»
£¨2£©±£³ÖζȲ»±ä£¬°´ÏÂÁбÈÀý·Ö±ð³äÈëa¡¢bÁ½ÈÝÆ÷ÖУ¬´ïµ½Æ½ºâºóaÖÐCµÄŨ¶ÈÈÔΪN mol•L-1£¬Ò»±ßµ¹×ª»¯ÎªÍ¬Ò»ÎïÖÊ£¬ÎïÖʵÄÁ¿ÏàͬD¡¢2molC+1molD E¡¢1.5molA+0.5molB+1molC+0.5molDÏ൱ÓÚ3mol A¡¢1mol B£¬¹ÊÑ¡D¡¢E£®

µãÆÀ ±¾Ì⿼²é»¯Ñ§Æ½ºâÒƶ¯Óë¼ÆË㣬ÄѶÈÖеȣ¬×¢ÒâÀûÓõÈЧ˼ÏëÉè¼Æƽºâ½¨Á¢µÄ;¾¶£¬£¨1£©ÖÐAµÄŨ¶È±È½ÏΪÒ×´íµã£¬Ñ§ÉúÈÝÒ׸ù¾ÝƽºâÒƶ¯·ÖÎöÅжÏaÖÐŨ¶È´ó£¬ºöÂÔÌå»ýµÄ¼õС£¬×¢Òâ¸ù¾ÝƽºâÒƶ¯Ô­Àí»òƽºâ³£ÊýÀí½â£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø