ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÏÂͼÊÇÈËÀà´Óº£Ë®×ÊÔ´»ñȡijЩÖØÒª»¯¹¤ÔÁϵÄÁ÷³ÌʾÒâͼ£º
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©²Ù×÷AÊÇ___________ºÍ¹ýÂË£¨ÌîʵÑé»ù±¾²Ù×÷Ãû³Æ£©¡£
£¨2£©²Ù×÷BÐè¼ÓÈëÏÂÁÐÊÔ¼ÁÖеÄÒ»ÖÖ£¬×îºÏÊʵÄÊÇ______£¨Ñ¡Ìî±àºÅ£©¡£
a£®ÇâÑõ»¯ÄÆÈÜÒº
b£®³ÎÇåʯ»ÒË®
c£®Ê¯»ÒÈé
d£®Ì¼ËáÄÆÈÜÒº
£¨3£©Ïò¿à±ÖÐͨÈëCl2£¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ________________________________£¬
ÓÃSO2Ë®ÈÜÒºÎüÊÕBr2£¬ÎüÊÕÂÊ¿É´ï95%£¬Óйط´Ó¦µÄÀë×Ó·½³ÌʽΪ_______________¡£
£¨4£©¹¤ÒµÉÏÓÉÎÞË®MgCl2ÖÆȡþµÄ»¯Ñ§·½³ÌʽΪ__________________________________¡£
¡¾´ð°¸¡¿£¨1£©Õô·¢½á¾§£»£¨2£©c£»£¨3£©Cl2 + 2Br£ =Br2 + 2Cl££¬Br2£«SO2£«2H2O===4H£«£«SO£«2Br£ £»£¨4£©MgCl2£¨ÈÛÈÚ£© Mg£«Cl2¡ü¡£
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©º£Ë®Öеõ½´ÖÑΣ¬²ÉÈ¡Õô·¢½á¾§µÄ·½·¨£»£¨2£©´Óº£Ë®Öеõ½Mg£¨OH£©2£¬ÐèÒª¿¼Âǵ½¾¼ÃЧÒ棬Òò´ËʹÓÃCa£¨OH£©2£¬³ÎÇåʯ»ÒË®Öк¬ÓÐCa£¨OH£©2Á¿±È½ÏÉÙ£¬Òò´ËʹÓÃʯ»ÒÈ飬¹ÊÑ¡c£»£¨3£©ÀûÓñËصÄÖû»·´Ó¦£¬Ñõ»¯ÐÔÇ¿µÄÖÆÈ¡Ñõ»¯ÐÔÈõµÄ£¬Cl2£«2Br£=2Cl££«Br2£¬SO2¾ßÓл¹ÔÐÔ£¬SO2£«£«Br2£«H2O=4H£«£«SO42££«2Br££»£¨4£©ÖÆȡþ£¬µç½âÈÛÈÚ״̬µÄÂÈ»¯Ã¾£¬Æä·´Ó¦·½³ÌʽΪ£ºMgCl2£¨ÈÛÈÚ£© Mg£«Cl2¡ü¡£