ÌâÄ¿ÄÚÈÝ

£¨15·Ö£©Ä³Ð£ÐËȤС×éͬѧÓûÑо¿SO2µÄÐÔÖÊ¡£
£¨1£©½«Ïà¹ØµÄº¬ÁòÎïÖÊ·ÖΪÈçϱíËùʾ3×飬µÚ2×éÖÐÎïÖÊXµÄ»¯Ñ§Ê½ÊÇ     ¡£

µÚ1×é
µÚ2×é
µÚ3×é
S£¨µ¥ÖÊ£©
SO2¡¢X¡¢Na2SO3¡¢NaHSO3
SO3¡¢H2SO4¡¢Na2SO4¡¢NaHSO4
 
£¨2£©ÀûÓÃÏÂͼËùʾµÄ×°ÖÃÑо¿SO2µÄÐÔÖÊ£º
£¨È۵㣺SO£­76£®1¡æ£¬SO3  16£®8¡æ£»·Ðµã£ºSO£­10¡æ£¬SO44£®8¡æ£©

¢Ù×°ÖÃIÄ£Ä⹤ҵÉú²úÖÐSO2´ß»¯Ñõ»¯µÄ·´Ó¦£¬Æ仯ѧ·½³ÌʽÊÇ                   ¡£
¢Ú¼×ͬѧ°´I¡¢II¡¢III¡¢IVµÄ˳ÐòÁ¬½Ó×°Öã¬×°ÖÃIIµÄ×÷ÓÃÊÇ                     £»×°ÖÃIIIÖÐÈÜÒºÖð½¥ÍÊÉ«£¬Éú³ÉMn2+£¬Í¬Ê±pH½µµÍ£¬Ôò¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ          ¡£
¢ÛÒÒͬѧ°´I¡¢II¡¢IVµÄ˳ÐòÁ¬½Ó×°Öã¬Èô×°ÖÃIVÖÐÓÐ40 mL 2£®5 mol?L£­1 NaOHÈÜÒº£¬·´Ó¦ºóÔöÖØ4£®8 g£¬Ôò×°ÖÃIVÖз¢Éú·´Ó¦µÄ×Ü»¯Ñ§·½³ÌʽÊÇ                          ¡£

£¨1£©£¨3·Ö£©H2SO3
£¨2£©¢Ù£¨3·Ö£©2SO2 + O2  2SO3
¢Ú£¨3·Ö£©Ê¹SO3Äý½á³É¹ÌÌåÓëSO2·ÖÀë
£¨3·Ö£©5SO2 + 2H2O + 2MnO4£­="=" 5SO42£­ + 2Mn2+ + 4H+
¢Û£¨3·Ö£©3SO2 + 4NaOH ="=" Na2SO3 + 2NaHSO3 + H2O

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø