ÌâÄ¿ÄÚÈÝ

£¨15·Ö£©Ä³Ê³Óð״×ÊÇÓÉ´×ËáÓë´¿Ë®ÅäÖƶø³É£¬ÓÃÖк͵ζ¨µÄ·½·¨×¼È·²â¶¨ÆäÖд×ËáµÄÎïÖʵÄÁ¿Å¨¶È¡£ÊµÑé²½Ö裺¢ÙÅäÖÆ500mLŨ¶ÈԼΪ0.1 mol¡¤L£­1µÄNaOHÈÜÒº£»¢ÚÓÃÎïÖÊXµÄ±ê×¼ÈÜҺ׼ȷ²â¶¨¸ÃNaOHÈÜÒºµÄŨ¶È£¨XÓëÇâÑõ»¯ÄÆ°´ÎïÖʵÄÁ¿±È1£º1ÍêÈ«·´Ó¦£©£»¢ÛÓÃÒÑ֪׼ȷŨ¶ÈµÄNaOHÈÜÒº²â¶¨´×ËáµÄŨ¶È¡£

£¨1£©³ÆÁ¿ËùÐèµÄNaOH¹ÌÌåÖÃÓÚ´óÉÕ±­ÖУ¬¼ÓÈë500mLÕôÁóË®£¬½Á°èÈܽ⡣¸ÃÅäÖƲ½Öè__________£¨Ìî¡°¿ÉÐС±»ò¡°²»¿ÉÐС±£©¡£

£¨2£©³ÆÁ¿Ê±NaOHÔÚ¿ÕÆøÖм«Ò×ÎüË®£¬ÅäÖÆËùµÃµÄNaOHÈÜҺŨ¶Èͨ³£±ÈÔ¤ÆÚ_____£¨ÌС¡±»ò¡°´ó¡±£©£¬ÕâÊDz»ÄÜÖ±½ÓÅäÖÆÆä±ê×¼ÈÜÒºµÄÔ­Òò¡£

£¨3£©²éÔÄ°×´×°üװ˵Ã÷£¬´×ËẬÁ¿Ô¼Îª6g/100mL£¬»»Ëã³ÉÎïÖʵÄÁ¿Å¨¶ÈԼΪ_____ mol¡¤L£­1£¬µÎ¶¨Ç°½«°×´×Ï¡ÊÍ_________£¨Ìî¡°10¡±»ò¡°100¡±£©±¶¡££¨ÒÑÖª´×ËáµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª60£©

£¨4£©Ï¡ÊÍ°×´×ʱÐèÒªµÄÒÇÆ÷ÓÐÉÕ±­¡¢²£Á§°ô¡¢µÎ¹Ü¡¢ËáʽµÎ¶¨¹Ü¡¢___________¡£

£¨5£©×¼È·Á¿È¡Ï¡ÊͺóµÄ°×´×20.00mL£¬ÖÃÓÚ250mL׶ÐÎÆ¿ÖУ¬¼ÓË®30mL£¬ÔٵμӷÓָ̪ʾ¼Á£¬ÓÃÉÏÊöNaOH±ê×¼ÈÜÒºµÎ¶¨ÖÁ____________¼´ÎªÖյ㡣Öظ´µÎ¶¨Á½´Î£¬Æ½¾ùÏûºÄNaOH±ê×¼ÈÜÒºV mL£¨NaOHÈÜҺŨ¶ÈΪc mol¡¤L£­1£©¡£

£¨6£©Ô­°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶È£½____________ mol¡¤L£­1¡£

 

¡¾´ð°¸¡¿

£¨1£©¿ÉÐУ¨2·Ö£©   £¨2£©Ð¡£¨2·Ö£©     £¨3£©1 £¨2·Ö£©   10£¨2·Ö£©

£¨4£©ÈÝÁ¿Æ¿£¨1·Ö£©  £¨5£©ÈÜÒº±ä³ÉdzºìÉ«ÇÒ30ÃëÄÚ²»ÍÊÉ«£¨3·Ö£©  £¨6£©cV/2£¨3·Ö£©

¡¾½âÎö¡¿£¨1£©¸ù¾ÝÌâÒâ¿ÉÖª£¬ÇâÑõ»¯ÄƵÄŨ¶È²»ÐèҪ׼ȷÅäÖÆ£¬ËùÒÔ²»ÐèÒªÈÝÁ¿Æ¿£¬Òò´ËÊÇ¿ÉÐеġ£

£¨2£©ÇâÑõ»¯ÄÆÒ×ÎüË®£¬µ¼Ö³ÆÁ¿µÄÇâÑõ»¯ÄƹÌÌåÖÊÁ¿Æ«Ð¡£¬Å¨¶ÈÆ«µÍ¡£

£¨3£©6gÒÒËáÊÇ0.1mol£¬ËùÒÔŨ¶ÈÊÇ0.1mol¡Â0.1L£½1.0mol/L¡£Å¨¶ÈÌ«¸ß·´Ó¦Ì«¿ì£¬²»ÀûÓÚÅжÏÖյ㣬̫µÍ£¬·´Ó¦Ì«Âý£¬ËùÒÔÏ¡ÊÍ10±¶¼´¿É¡£

£¨4£©Ó¦Óô×ËáµÄŨ¶ÈÐèÒªÊÇ׼ȷµÄ£¬Òò´ËÓ¦¸ÃÓÃÈÝÁ¿Æ¿ÅäÖÆ¡£

£¨5£©Ëá²»ÄÜʹ·Ó̪ÊÔÒºÏÔÉ«£¬¼îÄÜʹ·Ó̪ÊÔÒºÏÔºìÉ«£¬ËùÒÔÖÕµãʱµÄÏÖÏóÊÇÈÜÒº±ä³ÉdzºìÉ«ÇÒ30ÃëÄÚ²»ÍÊÉ«¡£

£¨6£©¸ù¾ÝÇâÀë×ÓµÄÎïÖʵÄÁ¿ºÍOH£­µÄÎïÖʵÄÁ¿ÏàµÈ¿ÉÖª£¬´×ËáµÄŨ¶ÈÊÇcV/20mol/L¡£ËùÒÔÔ­´×ËáµÄŨ¶ÈÊÇcV/20mol/L¡Á10£½cV/2mol/L¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ijʳÓð״×ÊÇÓÉ´×ËáÓë´¿Ë®ÅäÖƶø³É£¬ÓÃ0.1000mol/L NaOHÈÜҺ׼ȷ²â¶¨ÆäÖд×ËáµÄÎïÖʵÄÁ¿Å¨¶È£®ÒÔÏÂΪijͬѧÁгöµÄʵÑé²½Ö裨δÅÅÐò£©£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣮
A£®·Ö±ðÏò¼îʽµÎ¶¨¹Ü¡¢ËáʽµÎ¶¨¹Ü×¢ÈëNaOH±ê×¼ÈÜÒººÍ´ý²â´×ËáÖÁ0¿Ì¶ÈÒÔÉÏ2¡«3cm
B£®µ÷½ÚµÎ¶¨¹ÜÒºÃæÖÁ0»ò0¿Ì¶ÈÒÔÏ£¬¼Ç϶ÁÊý
C£®ÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬¼ÇÏµζ¨¹ÜÒºÃæµÄ¿Ì¶È
D£®Óñê×¼ÈÜÒºÇåÏ´¼îʽµÎ¶¨¹Ü2¡«3´Î£»´ý²â´×ËáÇåÏ´ËáʽµÎ¶¨¹Ü2¡«3´Î
E£®Óôý²â´×ËáÇåϴ׶ÐÎÆ¿2¡«3´Î
F£®ÅÅÆøÅÝʹµÎ¶¨¹Ü¼â×ì³äÂúÈÜÒº£¬°ÑµÎ¶¨¹Ü¹Ì¶¨ºÃ
G£®µÎ¶¨¹Ü¼ì©£¬ÓÃË®ÇåÏ´ËùÓÐÒÇÆ÷£¬±¸ÓÃ
H£®Í¨¹ýËáʽµÎ¶¨¹ÜÏò׶ÐÎƿעÈë20.00mL´ý²â´×Ëᣬ²¢¼ÓÈë2-3µÎָʾ¼Á
£¨1£©ÓÃÀë×Ó·½³Ìʽ±íʾ¸ÃʵÑéµÄÔ­Àí
CH3COOH+OH-=CH3COO-+H2O
CH3COOH+OH-=CH3COO-+H2O
£®
£¨2£©´ÓÉÏÊöʵÑé²½ÖèÖÐÑ¡³öÕýÈ·µÄ²¢°´²Ù×÷ÏȺóÅÅÐò£®ÄãµÄʵÑé˳ÐòΪ£º£¨ÓÃ×Öĸ±íʾ£©
G¡úD¡úA¡úF¡úB¡úH¡úC
G¡úD¡úA¡úF¡úB¡úH¡úC
£®
£¨3£©ÊµÑéÊÒ³£ÓõÄËá¼îָʾ¼ÁÓм׻ù³È¡¢Ê¯ÈïºÍ·Ó̪£¬ÄãÑ¡ÔñµÄָʾ¼ÁÊÇ
·Ó̪
·Ó̪
£¬ÀíÓÉÊÇ
Á½ÕßÇ¡ºÃÍêÈ«ÖкÍÉú³É´×ËáÄÆ£¬ÆäË®ÈÜÒº³Ê¼îÐÔ£¬±ØÐèÑ¡ÔñÔÚ¼îÐÔ·¶Î§±äÉ«ÇÒÑÕÉ«ÈÝÒ×ÅжϵķÓ̪×÷ָʾ¼ÁÅжϵζ¨ÖÕµã
Á½ÕßÇ¡ºÃÍêÈ«ÖкÍÉú³É´×ËáÄÆ£¬ÆäË®ÈÜÒº³Ê¼îÐÔ£¬±ØÐèÑ¡ÔñÔÚ¼îÐÔ·¶Î§±äÉ«ÇÒÑÕÉ«ÈÝÒ×ÅжϵķÓ̪×÷ָʾ¼ÁÅжϵζ¨ÖÕµã
£»µÎ¶¨ÖÕµãµÄÏÖÏóÊÇ
µ±µÎ¼Ó×îºóÒ»µÎÇâÑõ»¯ÄÆÈÜҺʱ£¬ÈÜÒº±äΪdzºìÉ«ÇÒ30s²»ÍÊÉ«
µ±µÎ¼Ó×îºóÒ»µÎÇâÑõ»¯ÄÆÈÜҺʱ£¬ÈÜÒº±äΪdzºìÉ«ÇÒ30s²»ÍÊÉ«
£®
£¨4£©Ä³Í¬Ñ§ÊµÑéºóµÃµ½µÄÊý¾ÝÈçÏ£º
            µÎ¶¨´ÎÊý
ʵÑéÊý¾Ý
1 2 3 4 5
V£¨NaOH£©/mL£¨³õ¶ÁÊý£© 0.00 0.20 0.00 0.10 0.05
V£¨NaOH£©/mL£¨ÖÕ¶ÁÊý£© 15.75 15.20 14.98 15.12 15.05
Ô­°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ
0.07500
0.07500
mol/L£¨½á¹û±£Áô4λÓÐЧÊý×Ö£©£®
£¨5£©·ÖÎöÏÂÁвÙ×÷¶Ô²â¶¨½á¹ûµÄÓ°Ï죬Óá°Æ«µÍ¡±¡¢¡°Æ«¸ß¡±»ò¡°²»Ó°Ï족Ìî¿Õ£®
¢ÙµÎ¶¨Ç°¼îʽµÎ¶¨¹Ü³äÂúÈÜÒº£¬µÎ¶¨ºó¼â×ì´¦ÓÐÆøÅÝ
Æ«µÍ
Æ«µÍ
£»
¢Ú¶ÁÈ¡±ê×¼ÈÜÒºÌå»ýʱ£¬µÎ¶¨Ç°Æ½ÊÓ£¬µÎ¶¨ºóÑöÊÓ
Æ«¸ß
Æ«¸ß
£®

£¨15·Ö£©Ä³Ê³Óð״×ÊÇÓÉ´×ËáÓë´¿Ë®ÅäÖƶø³É£¬ÓÃÖк͵ζ¨µÄ·½·¨×¼È·²â¶¨ÆäÖд×ËáµÄÎïÖʵÄÁ¿Å¨¶È¡£ÊµÑé²½Ö裺¢ÙÅäÖÆ500mLŨ¶ÈԼΪ0.1 mol¡¤L£­1µÄNaOHÈÜÒº£»¢ÚÓÃÎïÖÊXµÄ±ê×¼ÈÜҺ׼ȷ²â¶¨¸ÃNaOHÈÜÒºµÄŨ¶È£¨XÓëÇâÑõ»¯ÄÆ°´ÎïÖʵÄÁ¿±È1£º1ÍêÈ«·´Ó¦£©£»¢ÛÓÃÒÑ֪׼ȷŨ¶ÈµÄNaOHÈÜÒº²â¶¨´×ËáµÄŨ¶È¡£
£¨1£©³ÆÁ¿ËùÐèµÄNaOH¹ÌÌåÖÃÓÚ´óÉÕ±­ÖУ¬¼ÓÈë500mLÕôÁóË®£¬½Á°èÈܽ⡣¸ÃÅäÖƲ½Öè__________£¨Ìî¡°¿ÉÐС±»ò¡°²»¿ÉÐС±£©¡£
£¨2£©³ÆÁ¿Ê±NaOHÔÚ¿ÕÆøÖм«Ò×ÎüË®£¬ÅäÖÆËùµÃµÄNaOHÈÜҺŨ¶Èͨ³£±ÈÔ¤ÆÚ_____£¨ÌС¡±»ò¡°´ó¡±£©£¬ÕâÊDz»ÄÜÖ±½ÓÅäÖÆÆä±ê×¼ÈÜÒºµÄÔ­Òò¡£
£¨3£©²éÔÄ°×´×°üװ˵Ã÷£¬´×ËẬÁ¿Ô¼Îª6g/100mL£¬»»Ëã³ÉÎïÖʵÄÁ¿Å¨¶ÈԼΪ_____ mol¡¤L£­1£¬µÎ¶¨Ç°½«°×´×Ï¡ÊÍ_________£¨Ìî¡°10¡±»ò¡°100¡±£©±¶¡££¨ÒÑÖª´×ËáµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª60£©
£¨4£©Ï¡ÊÍ°×´×ʱÐèÒªµÄÒÇÆ÷ÓÐÉÕ±­¡¢²£Á§°ô¡¢µÎ¹Ü¡¢ËáʽµÎ¶¨¹Ü¡¢___________¡£
£¨5£©×¼È·Á¿È¡Ï¡ÊͺóµÄ°×´×20.00mL£¬ÖÃÓÚ250mL׶ÐÎÆ¿ÖУ¬¼ÓË®30mL£¬ÔٵμӷÓָ̪ʾ¼Á£¬ÓÃÉÏÊöNaOH±ê×¼ÈÜÒºµÎ¶¨ÖÁ____________¼´ÎªÖյ㡣Öظ´µÎ¶¨Á½´Î£¬Æ½¾ùÏûºÄNaOH±ê×¼ÈÜÒºV mL£¨NaOHÈÜҺŨ¶ÈΪc mol¡¤L£­1£©¡£
£¨6£©Ô­°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶È£½____________ mol¡¤L£­1¡£

ijʳÓð״×ÊÇÓÉ´×ËáÓë´¿Ë®ÅäÖƶø³É£¬ÓÃ0.1000 mol/L NaOHÈÜҺ׼ȷ²â¶¨ÆäÖд×ËáµÄÎïÖʵÄÁ¿Å¨¶È¡£ÒÔÏÂΪijͬѧÁгöµÄʵÑé²½Ö裨δÅÅÐò£©£¬Çë»Ø´ðÏÂÁÐÎÊÌâ¡£

A£®·Ö±ðÏò¼îʽµÎ¶¨¹Ü¡¢ËáʽµÎ¶¨¹Ü×¢ÈëNaOH±ê×¼ÈÜÒººÍ´ý²â´×ËáÖÁ0¿Ì¶ÈÒÔÉÏ2¡«3cm
B£®µ÷½ÚµÎ¶¨¹ÜÒºÃæÖÁ0»ò0¿Ì¶ÈÒÔÏ£¬¼Ç϶ÁÊý
C£®ÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬¼ÇÏµζ¨¹ÜÒºÃæµÄ¿Ì¶È
D£®Óñê×¼ÈÜÒºÇåÏ´¼îʽµÎ¶¨¹Ü2¡«3´Î£»´ý²â´×ËáÇåÏ´ËáʽµÎ¶¨¹Ü2¡«3´Î
E£®Óôý²â´×ËáÇåϴ׶ÐÎÆ¿2¡«3´Î
F£®ÅÅÆøÅÝʹµÎ¶¨¹Ü¼â×ì³äÂúÈÜÒº£¬°ÑµÎ¶¨¹Ü¹Ì¶¨ºÃ
G£®µÎ¶¨¹Ü¼ì©£¬ÓÃË®ÇåÏ´ËùÓÐÒÇÆ÷£¬±¸ÓÃ
H£®Í¨¹ýËáʽµÎ¶¨¹ÜÏò׶ÐÎƿעÈë20.00 mL´ý²â´×Ëᣬ²¢¼ÓÈë2-3µÎָʾ¼Á
£¨1£©ÓÃÀë×Ó·½³Ìʽ±íʾ¸ÃʵÑéµÄÔ­Àí                                     ¡£
£¨2£©´ÓÉÏÊöʵÑé²½ÖèÖÐÑ¡³öÕýÈ·µÄ²¢°´²Ù×÷ÏȺóÅÅÐò¡£ÄãµÄʵÑé˳ÐòΪ£º£¨ÓÃ×Öĸ
±íʾ£©                                                               ¡£
£¨3£©ÊµÑéÊÒ³£ÓõÄËá¼îָʾ¼ÁÓм׻ù³È¡¢Ê¯ÈïºÍ·Ó̪£¬ÄãÑ¡ÔñµÄָʾ¼ÁÊÇ________£¬
ÀíÓÉÊÇ_______________________________________________________________ £»
µÎ¶¨ÖÕµãµÄÏÖÏóÊÇ______________________________________________________¡£
£¨4£©Ä³Í¬Ñ§ÊµÑéºóµÃµ½µÄÊý¾ÝÈçÏ£º
           µÎ¶¨´ÎÊý
ʵÑéÊý¾Ý
1
2
3
4
5
V(NaOH) /mL£¨³õ¶ÁÊý£©
0.00
0.20
0.00
0.10
0.05
V(NaOH) /mL£¨ÖÕ¶ÁÊý£©
15.75
15.20
14.98
15.12
15.05
Ô­°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ____________mol/L£¨½á¹û±£Áô4λÓÐЧÊý×Ö£©¡£
£¨5£©·ÖÎöÏÂÁвÙ×÷¶Ô²â¶¨½á¹ûµÄÓ°Ï죬Óá°Æ«µÍ¡±¡¢¡°Æ«¸ß¡±»ò¡°²»Ó°Ï족Ìî¿Õ¡£
¢ÙµÎ¶¨Ç°¼îʽµÎ¶¨¹Ü³äÂúÈÜÒº£¬µÎ¶¨ºó¼â×ì´¦ÓÐÆøÅÝ_______£»
¢Ú¶ÁÈ¡±ê×¼ÈÜÒºÌå»ýʱ£¬µÎ¶¨Ç°Æ½ÊÓ£¬µÎ¶¨ºóÑöÊÓ________¡£

ijʳÓð״×ÊÇÓÉ´×ËáÓë´¿Ë®ÅäÖƶø³É£¬ÓÃ0.1000 mol/L NaOHÈÜҺ׼ȷ²â¶¨ÆäÖд×ËáµÄÎïÖʵÄÁ¿Å¨¶È¡£ÒÔÏÂΪijͬѧÁгöµÄʵÑé²½Ö裨δÅÅÐò£©£¬Çë»Ø´ðÏÂÁÐÎÊÌâ¡£

A£®·Ö±ðÏò¼îʽµÎ¶¨¹Ü¡¢ËáʽµÎ¶¨¹Ü×¢ÈëNaOH±ê×¼ÈÜÒººÍ´ý²â´×ËáÖÁ0¿Ì¶ÈÒÔÉÏ2¡«3cm

B£®µ÷½ÚµÎ¶¨¹ÜÒºÃæÖÁ0»ò0¿Ì¶ÈÒÔÏ£¬¼Ç϶ÁÊý

C£®ÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬¼ÇÏµζ¨¹ÜÒºÃæµÄ¿Ì¶È

D£®Óñê×¼ÈÜÒºÇåÏ´¼îʽµÎ¶¨¹Ü2¡«3´Î£»´ý²â´×ËáÇåÏ´ËáʽµÎ¶¨¹Ü2¡«3´Î

E£®Óôý²â´×ËáÇåϴ׶ÐÎÆ¿2¡«3´Î

F£®ÅÅÆøÅÝʹµÎ¶¨¹Ü¼â×ì³äÂúÈÜÒº£¬°ÑµÎ¶¨¹Ü¹Ì¶¨ºÃ

G£®µÎ¶¨¹Ü¼ì©£¬ÓÃË®ÇåÏ´ËùÓÐÒÇÆ÷£¬±¸ÓÃ

H£®Í¨¹ýËáʽµÎ¶¨¹ÜÏò׶ÐÎƿעÈë20.00 mL´ý²â´×Ëᣬ²¢¼ÓÈë2-3µÎָʾ¼Á

£¨1£©ÓÃÀë×Ó·½³Ìʽ±íʾ¸ÃʵÑéµÄÔ­Àí                                     ¡£

£¨2£©´ÓÉÏÊöʵÑé²½ÖèÖÐÑ¡³öÕýÈ·µÄ²¢°´²Ù×÷ÏȺóÅÅÐò¡£ÄãµÄʵÑé˳ÐòΪ£º£¨ÓÃ×Öĸ

±íʾ£©                                                               ¡£

£¨3£©ÊµÑéÊÒ³£ÓõÄËá¼îָʾ¼ÁÓм׻ù³È¡¢Ê¯ÈïºÍ·Ó̪£¬ÄãÑ¡ÔñµÄָʾ¼ÁÊÇ________£¬

ÀíÓÉÊÇ_______________________________________________________________ £»

µÎ¶¨ÖÕµãµÄÏÖÏóÊÇ______________________________________________________¡£

£¨4£©Ä³Í¬Ñ§ÊµÑéºóµÃµ½µÄÊý¾ÝÈçÏ£º

           µÎ¶¨´ÎÊý

ʵÑéÊý¾Ý

1

2

3

4

5

V(NaOH) /mL£¨³õ¶ÁÊý£©

0.00

0.20

0.00

0.10

0.05

V(NaOH) /mL£¨ÖÕ¶ÁÊý£©

15.75

15.20

14.98

15.12

15.05

Ô­°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ____________mol/L£¨½á¹û±£Áô4λÓÐЧÊý×Ö£©¡£

£¨5£©·ÖÎöÏÂÁвÙ×÷¶Ô²â¶¨½á¹ûµÄÓ°Ï죬Óá°Æ«µÍ¡±¡¢¡°Æ«¸ß¡±»ò¡°²»Ó°Ï족Ìî¿Õ¡£

¢ÙµÎ¶¨Ç°¼îʽµÎ¶¨¹Ü³äÂúÈÜÒº£¬µÎ¶¨ºó¼â×ì´¦ÓÐÆøÅÝ_______£»

¢Ú¶ÁÈ¡±ê×¼ÈÜÒºÌå»ýʱ£¬µÎ¶¨Ç°Æ½ÊÓ£¬µÎ¶¨ºóÑöÊÓ________¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø