ÌâÄ¿ÄÚÈÝ

¸ÖÌúÉúÐâµÄ¹ý³ÌÊ®·Ö¸´ÔÓ£¬ÒÑ֪ijÌúÐ⺬ÓÐFe2O3•nH2O(n¡Ü1)£¬»¹¿ÉÄÜÓÐFe(OH)3ºÍFeCO3¡£Ä³Ñ§Ï°Ð¡×é×öÁËÒÔÏÂʵÑ飺

¢ÙÈ¡12.574gÌúÐâ¸ô¾ø¿ÕÆø¼ÓÈÈÖÁºãÖØ£¬µÃµ½¹ÌÌå10.528g¡£

¢ÚÁíÈ¡6.287gÌúÐ⣬ÔÚ205.00 mL 1.000mol/LµÄÏ¡ÏõËáÖÐÇ¡ºÃÍêÈ«Èܽ⣬²úÉúNOÆøÌå89.60 mL(±ê×¼×´¿ö)¡£

£¨1£©¸ù¾ÝʵÑé¢Ù£¬ÌúÐâÖÐÊÇ·ñÖ»º¬Fe2O3•nH2O£¿ÊÔͨ¹ý¼ÆËã»Ø´ð¡£

£¨2£©¸ù¾ÝʵÑé¢Ú£¬ÄÜ·ñÈ·¶¨ÌúÐâÖк¬ÓÐFeCO3£¿ÀíÓÉÊÇʲô£¿

£¨3£©Èôn=0.8£¬ÊÔͨ¹ý¼ÆËãÈ·¶¨6.287gÌúÐâµÄ³É·ÖÒÔ¼°ËüÃǵÄÎïÖʵÄÁ¿¡£

£¨1£©·ñ;ÈôÖ»º¬Fe2O3•nH2O£¬ÔòFe2O3ÓëH2OµÄÎïÖʵÄÁ¿Ö®±ÈΪ

10.528¡Â160/£¨12.574-10.528£©¡Â18=0.0658£º0.114=1£º1.72      n£¾1£¬²»ºÏÌâÒ⣨2·Ö£¬ºÏÀí¼´¿É£©                    £¨2£©ÓУ¬ÒòΪֻÓÐFeCO3ÏÔ»¹Ô­ÐÔ£¨1·Ö£¬ºÏÀí¼´¿É£©

£¨3£©Fe2O3•0.8H2O£º0.025 mol£»Fe(OH)3£º0.005 mol£»FeCO3 £º0.012mol£¨¸÷1·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø