ÌâÄ¿ÄÚÈÝ

ʳƷ°²È«¹ØÏµµ½¹ú¼ÆÃñÉú£¬±¸ÊܹØ×¢¡£

¢ñ¡¢É½ÀæËᣨCH3CH=CHCH=CHCOOH£©ÊǸßЧ°²È«µÄʳƷ·À¸¯¼Á¡£

£¨1£©ÏÂÁйØÓÚɽÀæËáÐÔÖÊÐðÊö²»ÕýÈ·µÄÊÇ__________

A.ÄÜÓëäåË®·¢Éú¼Ó³É·´Ó¦     B.ÄÜʹËáÐÔ¸ßÃÌËá¼ØÍÊÉ«

C.¼îÐÔÌõ¼þϵÄÜË®½â         D.ÄÜ·¢Éú¼Ó¾Û·´Ó¦

£¨2£©É½ÀæËỹ¿ÉÒԺϳÉÀàËÆÓÚÌìÈ»Ï𽺵ĸ߷Ö×Ó²ÄÁÏ£¬ºÏ³É·ÏßÈçÏ£º

д³ö¢ÙµÄ·´Ó¦·½³Ìʽ£º________________________;¢ÚµÄ·´Ó¦ÀàÐÍ£º_________

¢ò¡¢Èý¹ÄÌ·ÛÌí¼ÓÈý¾ÛÇè°·ÖÂËÀÓ¤¶ùÖØ´óʹÊÁîÈËÕ𾪡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÄÌ·ÛÖе°°×ÖÊÆ½¾ùº¬µªÁ¿Îª16%£¬Èý¾ÛÇè°·ÖеªµÄÖÊÁ¿·ÖÊýΪ______

£¨2£©Èý¾ÛÇè°·ÔÚÈËÌåÄÚ·¢ÉúÈ¡´ú·´Ó¦£¨Ë®½â£©£¬Éú³ÉÈý¾ÛÇèËᣨÏÂͼ£©£¬

д³öÈý¾ÛÇè°·Ë®½â·½³Ìʽ______________________

£¨3£©²»·¨ÆóÒµÔÚÔ­ÄÌÖÐÌí¼ÓÄòËØCO(NH2)2£¬¸ßÎÂÏ¿ÉÒÔÉú³ÉÈý¾ÛÇè°·ºÍNH3¡¢CO2£¬ÄÌ·ÛÖв»º¬ÄòËØÁË£¬µ«ÊǺ¬µªÁ¿ÈÔÈ»½Ï¸ß¡£Ð´³öÄòËØ¸ßβúÉúÈý¾ÛÇè°·µÄ»¯Ñ§·½³Ìʽ________

¢ñ£®£¨1£©C(2·Ö)

£¨2£©CH3CH=CHCH=CHCOOH £« CH3OH   CH3CH=CHCH=CHCOOCH3+ H2O£¨2·Ö£©

        ¼Ó¾Û·´Ó¦(1·Ö)

¢ò£®£¨1£© 66.7%(1·Ö) 

£¨2£©   £«3H2O ¡ú£«3NH3 (2·Ö)

£¨3£©6 CO£¨NH2)2 ¡ú C3N6H6 + 6 NH3 + 3 CO2(2·Ö)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2009?ÉîÛÚ¶þÄ££©Ê³Æ·°²È«¹ØÏµµ½¹ú¼ÆÃñÉú£¬±¸ÊܹØ×¢£®
¢ñ¡¢É½ÀæËᣨCH3CH=CHCH=CHCOOH£©ÊǸßЧ°²È«µÄʳƷ·À¸¯¼Á£®
£¨1£©ÏÂÁйØÓÚɽÀæËáÐÔÖÊÐðÊö²»ÕýÈ·µÄÊÇ
C
C

A£®ÄÜÓëäåË®·¢Éú¼Ó³É·´Ó¦     B£®ÄÜʹËáÐÔ¸ßÃÌËá¼ØÍÊÉ«
C£®¼îÐÔÌõ¼þÏÂÄÜË®½â         D£®ÄÜ·¢Éú¼Ó¾Û·´Ó¦
£¨2£©É½ÀæËỹ¿ÉÒԺϳÉÀàËÆÓÚÌìÈ»Ï𽺵ĸ߷Ö×Ó²ÄÁÏ£¬ºÏ³É·ÏßÈçÏ£º

д³ö¢ÙµÄ·´Ó¦·½³Ìʽ£º
CH3CH=CHCH=CHCOOH+CH3OH
ŨÁòËá
¡÷
CH3CH=CHCH=CHCOOCH3+H2O
CH3CH=CHCH=CHCOOH+CH3OH
ŨÁòËá
¡÷
CH3CH=CHCH=CHCOOCH3+H2O
£»¢ÚµÄ·´Ó¦ÀàÐÍ£º
¼Ó¾Û·´Ó¦
¼Ó¾Û·´Ó¦
£®
¢òÈý¹ÄÌ·ÛÌí¼ÓÈý¾ÛÇè°·ÖÂËÀÓ¤¶ùÖØ´óʹÊÁîÈËÕ𾪣®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÄÌ·ÛÖе°°×ÖÊÆ½¾ùº¬µªÁ¿Îª16%£¬Èý¾ÛÇè°·ÖеªµÄÖÊÁ¿·ÖÊýΪ
66.7%
66.7%
£®
£¨2£©Èý¾ÛÇè°·ÔÚÈËÌåÄÚ·¢ÉúÈ¡´ú·´Ó¦£¨Ë®½â£©£¬Éú³ÉÈý¾ÛÇèËᣨÈçͼ£©£¬Ð´³öÈý¾ÛÇè°·Ë®½â·½³Ìʽ
£®
£¨3£©²»·¨ÆóÒµÔÚÔ­ÄÌÖÐÌí¼ÓÄòËØCO£¨NH2£©2£¬¸ßÎÂÏ¿ÉÒÔÉú³ÉÈý¾ÛÇè°·ºÍNH3¡¢CO2£¬ÄÌ·ÛÖв»º¬ÄòËØÁË£¬µ«ÊǺ¬µªÁ¿ÈÔÈ»½Ï¸ß£®Ð´³öÄòËØ¸ßβúÉúÈý¾ÛÇè°·µÄ»¯Ñ§·½³Ìʽ
6CO£¨NH2£©2
 ¸ßΠ
.
 
C3H6N6+6NH3+3CO2
6CO£¨NH2£©2
 ¸ßΠ
.
 
C3H6N6+6NH3+3CO2
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø