ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿¼¸ÖÖÖ÷×åÔªËØ(¹ý¶ÉÔªËØÂÔÈ¥)ÔÚÖÜÆÚ±íÖеÄλÖÃÈçÏÂ:

(1) AµÄÔªËØ·ûºÅÊÇ________¡£

(2) DÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ_________________________________¡£

(3) E¡¢G¡¢TµÄÔ­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ_________(ÌîÔªËØ·ûºÅ)¡£

(4)ÎøÔªËØ(34Se)ÓëDͬÖ÷×壬Æä·Ç½ðÊôÐÔ±ÈD_________(Ìî¡°Ç¿¡±»ò¡°Èõ¡±)£¬´ÓÔ­×ӽṹ½Ç¶È½âÊÍÆäÔ­Òò:___________________________________________________________________¡£

(5) RÔªËصÄÔ­×ӽṹʾÒâͼΪ_________________¡£

(6) E¡¢G¡¢JÈýÖÖÔªËØ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÁ½Á½Ö®¼äÄÜ·´Ó¦£¬Àë×Ó·½³Ìʽ·Ö±ðΪ:H+ +OH-£½H2O¡¢_________________________________¡¢______________________¡£

(7) E¡¢DÁ½ÔªËØÄÜÐγÉÔ­×Ó¸öÊý±È2:1ºÍ1:1µÄÁ½ÖÖ»¯ºÏÎï¡£2:1 ÐÍ»¯ºÏÎïµÄµç×ÓʽΪ______________________________¡£1:1ÐÍ»¯ºÏÎïµÄ»¯Ñ§Ê½ÒÔ¼°Ëùº¬»¯Ñ§¼üÀàÐÍÊÇ_____________________________¡£

(8)AÓëMÐγɵķÖ×Ó¿ÉÄÜÊÇ______________(Ìî×ÖĸÐòºÅ)¡£

¡¾´ð°¸¡¿H µÚ2ÖÜÆÚµÚ¢öA×å K£¾Na£¾Al Èõ SeÓëOͬÖ÷×壬µç×Ó²ãÊýSe£¾O£¬Ô­×Ӱ뾶Se£¾O£¬µÃµç×ÓÄÜÁ¦Se£¼O£¬·Ç½ðÊôÐÔSe£¼O Al(OH)3+3H+£½A13++3H2O Al(OH)3+OH£­£½AlO2-+2H2O Na2O2 Àë×Ó¼ü¡¢·Ç¼«ÐÔ¼ü ¢Û

¡¾½âÎö¡¿

Ê×ÏÈÒÀ¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄÏà¶ÔλÖÃÅжϳöÔªËØÃû³Æ£¬È»ºó½áºÏÔªËØÖÜÆÚÂÉ¡¢ÎïÖʵÄÐÔÖÊ·ÖÎö½â´ð¡£

¸ù¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄÏà¶ÔλÖÿÉÖªAÊÇH£¬BÊÇN£¬DÊÇO£¬EÊÇNa£¬GÊÇAl£¬JÊÇCl£¬MÊÇC£¬RÊÇS£¬TÊÇK¡£Ôò

(1)AµÄÔªËØ·ûºÅÊÇH¡£

(2)DÊÇO£¬ÔÚÖÜÆÚ±íÖеÄλÖÃÊǵÚ2ÖÜÆÚµÚ¢öA×å¡£

(3)ͬÖÜÆÚ×Ô×óÏòÓÒÔ­×Ӱ뾶Öð½¥¼õС£¬Í¬Ö÷×å´ÓÉϵ½ÏÂÔ­×Ӱ뾶Öð½¥Ôö´ó£¬ÔòE¡¢G¡¢TµÄÔ­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇK£¾Na£¾Al¡£

(4)ͬÖ÷×å´ÓÉϵ½Ï·ǽðÊôÐÔÖð½¥¼õÈõ£¬ÎøÔªËØ(34Se)ÓëDͬÖ÷×壬ÔòÆä·Ç½ðÊôÐÔ±ÈDÈõ£¬ÕâÊÇÓÉÓÚSeÓëOͬÖ÷×壬µç×Ó²ãÊýSe£¾O£¬Ô­×Ӱ뾶Se£¾O£¬µÃµç×ÓÄÜÁ¦Se£¼O£¬·Ç½ðÊôÐÔSe£¼O¡£

(5)RÔªËØÊÇS£¬ÆäÔ­×ӽṹʾÒâͼΪ¡£

(6)E¡¢G¡¢JÈýÖÖÔªËØ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯Îï·Ö±ðÊÇÇâÑõ»¯ÄÆ¡¢ÇâÑõ»¯ÂÁºÍ¸ßÂÈËᣬÁ½Á½Ö®¼äÄÜ·´Ó¦£¬Àë×Ó·½³Ìʽ·Ö±ðΪH++OH-£½H2O¡¢Al(OH)3+3H+£½A13++3H2O¡¢Al(OH)3+OH£­£½AlO2-+2H2O¡£

(7)E¡¢DÁ½ÔªËØÄÜÐγÉÔ­×Ó¸öÊý±È2:1ºÍ1:1µÄÁ½ÖÖ»¯ºÏÎï·Ö±ðÊÇÑõ»¯Äƺ͹ýÑõ»¯ÄÆ¡£2:1ÐÍ»¯ºÏÎïÊÇÑõ»¯ÄÆ£¬µç×ÓʽΪ¡£1:1ÐÍ»¯ºÏÎïµÄ»¯Ñ§Ê½ÎªNa2O2£¬Ëùº¬»¯Ñ§¼üÀàÐÍÊÇÀë×Ó¼ü¡¢·Ç¼«ÐÔ¼ü¡£

(8)AÓëMÐγɵķÖ×Ó¿ÉÄÜÊǼ×Í飬·Ö×ÓʽΪCH4£¬´ð°¸Ñ¡¢Û¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¾ùΪ¶ÌÖÜÆÚÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎµÝÔö¡£AÔªËØÔ­×ÓºËÄÚÎÞÖÐ×Ó£¬BÔªËØÔ­×Ó×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ2±¶£¬DÊǵؿÇÖк¬Á¿×î¶àµÄÔªËØ£¬EµÄ»¯ºÏÎïÑæÉ«·´Ó¦ÊÇ»ÆÉ«£¬FÓëGλÖÃÏàÁÚ£¬GÊÇͬÖÜÆÚÔªËØÖÐÔ­×Ӱ뾶×îСµÄÔªËØ¡£

ÇëÓû¯Ñ§ÓÃÓï»Ø´ð£º

£¨1£©DµÄ¼òµ¥ÒõÀë×ӵĽṹʾÒâͼÊÇ___________¡£

£¨2£©Óõç×Óʽ±íʾE2FµÄÐγɹý³Ì____________¡£

£¨3£©E¡¢F¡¢GÈýÖÖÔªËØËùÐγɵļòµ¥Àë×Ó£¬°ë¾¶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ_________>_________>_________¡£

£¨4£©ÏÂÁÐʵÑé²Ù×÷¶ÔÓ¦µÄʵÑéÏÖÏóÖУ¬²»ÕýÈ·µÄÊÇ_________£¨Ìî×Öĸ£©¡£

Ñ¡Ïî

ʵÑé²Ù×÷

ʵÑéÏÖÏó

a

½«Eµ¥ÖÊͶÈëµ½CuSO4ÈÜÒºÖÐ

Éú³É´óÁ¿ºìÉ«¹ÌÌå

b

ÏòAlCl3ÈÜÒºÖÐͨÈë¹ýÁ¿CµÄÆø̬Ç⻯Îï

ÏÈÉú³É°×É«³Áµí£¬È»ºó³ÁµíÈܽâ

c

½«GµÄµ¥ÖÊͨÈëµ½NaBrÈÜÒºÖгä·Ö·´Ó¦ºó£¬¼ÓÈëËÄÂÈ»¯Ì¼£¬Õñµ´£¬¾²ÖÃ

ϲãÈÜÒº±äΪ³ÈÉ«

d

½«BµÄ×î¸ß¼ÛÑõ»¯ÎïͨÈëµ½Na2SiO3ÈÜÒºÖÐ

Éú³É°×É«³Áµí

£¨5£©Ð´³öAÓëBÐγɵÄ10µç×Ó·Ö×ӵĻ¯Ñ§Ê½_________£¬¸ÃÎïÖÊÓëGµÄµ¥ÖÊÔÚ¹âÕÕÏ·´Ó¦£¬Ò»¶Îʱ¼äºó£¬ÏÂÁÐ×°ÖÃʾÒâͼÖÐÄÜÕýÈ··´Ó³ÊµÑéÏÖÏóµÄÊÇ_________£¨Ìî×Öĸ£©¡£

£¨6£©ÔÚFeºÍCuµÄ»ìºÏÎïÖУ¬¼ÓÈëÒ»¶¨Á¿µÄCµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄÏ¡ÈÜÒº£¬³ä·Ö·´Ó¦ºóÊ£Óà½ðÊôm1 g£¬ÔÙÏòÆäÖмÓÈëÒ»¶¨Á¿µÄÏ¡ÁòËᣬ³ä·Ö·´Ó¦ºóÊ£Óà½ðÊôm2 g¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ_________£¨Ìî×Öĸ£©¡£

a m1´óÓÚm2 b m1µÈÓÚm2

c Ê£ÓàÈÜÒºÖÐÒ»¶¨ÓÐFe3+ d Ê£Óà½ðÊôÖÐÒ»¶¨ÓÐCu

¡¾ÌâÄ¿¡¿ÒÔ¼×´¼ÎªÈ¼ÁϵÄÐÂÐ͵ç³Ø£¬Æä³É±¾´ó´óµÍÓÚÒÔÇâÆøΪȼÁϵĴ«Í³È¼Áϵç³Ø£¬Ä¿Ç°µÃµ½¹ã·ºµÄÑо¿£¬ÈçͼÊÇÄ¿Ç°Ñо¿½Ï¶àµÄÒ»Àà¹ÌÌåÑõ»¯ÎïȼÁϵç³Ø¹¤×÷Ô­ÀíʾÒâͼ¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©B¼«Éϵĵ缫·´Ó¦Ê½Îª___________________________¡£

£¨2£©ÈôÓøÃȼÁϵç³Ø×öµçÔ´£¬ÓÃʯī×öµç¼«µç½âÁòËáÍ­ÈÜÒº£¬Ôòµç½âʱÑô¼«µÄ·´Ó¦Ê½Îª_______________________________________£¬µ±Ñô¼«ÊÕ¼¯µ½11.2L£¨±ê×¼×´¿ö£©ÆøÌåʱ£¬ÏûºÄ¼×´¼µÄÖÊÁ¿Îª__________¿Ë(±£ÁôÁ½Î»ÓÐЧÊý×Ö)£¬ÈôҪʹÈÜÒº¸´Ô­£¬¿ÉÏòµç½âºóµÄÈÜÒºÖмÓÈëµÄÎïÖÊÓÐ ___________¡£

£¨3£©Ä¿Ç°ÒÑ¿ª·¢³öÓõç½â·¨ÖÆÈ¡ClO2µÄй¤ÒÕ¡£

¢ÙÉÏͼʾÒâÓÃʯī×öµç¼«£¬ÔÚÒ»¶¨Ìõ¼þϵç½â±¥ºÍʳÑÎË®ÖÆÈ¡ClO2¡£ÈôÓÃÉÏÊö¼×´¼È¼Áϵç³Ø½øÐеç½â£¬Ôòµç½â³ØµÄµç¼«a½Ó¼×´¼È¼Áϵç³ØµÄ________¼«£¨ÌîA»òB£©£¬Ð´³öÑô¼«²úÉúClO2µÄµç¼«·´Ó¦Ê½£º__________¡£

¢Úµç½âÒ»¶Îʱ¼ä£¬µ±Òõ¼«²úÉúµÄÆøÌåÌå»ýΪ112 mL£¨±ê×¼×´¿ö£©Ê±£¬Í£Ö¹µç½â¡£Í¨¹ýÑôÀë×Ó½»»»Ä¤µÄÑôÀë×ÓµÄÎïÖʵÄÁ¿Îª_________mol¡£

¡¾ÌâÄ¿¡¿Ìú¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓÃ;±È½Ï¹ã·º¡£

£¨1£©¸ßÌúËáÄÆ(Na2FeO4)ÊÇÒ»ÖÖÐÂÐ͵ÄÂÌÉ«Ïû¶¾¼ÁºÍ¸ßÈÝÁ¿µç³Ø²ÄÁÏ¡£½«Fe(NO3)3ÓëNaClO»ìºÏºó£¬ÔÚ¼îÐÔÌõ¼þÏ·¢Éú·´Ó¦¿ÉÖƵøßÌúËáÄÆ£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________________________________¡£

£¨2£©ËÄÑõ»¯ÈýÌú(Fe3O4)³£ÓÃ×÷ÑÕÁÏ¡¢´ÅÁ÷Ìå²ÄÁÏ¡¢´ß»¯¼ÁºÍµç×Ó²ÄÁϵȡ£¹²³Áµí·¨ÊÇÄ¿Ç°ÖƱ¸ÄÉÃ×Fe3O4µÄÖØÒª·½·¨Ö®Ò»£¬ÆäÁ÷³ÌÈçͼËùʾ£º

¢ÙΪµÃµ½½Ï´¿¾»µÄÄÉÃ×Fe3O4£¬FeSO4¡¤7H2OÓëFeCl3¡¤6H2OµÄÎïÖʵÄÁ¿Ö®±È×îºÃΪ________¡£µ«Êµ¼Ê²Ù×÷ʱ£¬È´ºÜÄÑ¿ØÖÆÕâÒ»±ÈÀý£¬Ô­ÒòÊÇ___________________________________________¡£

¢ÚÔÚ×î¼ÑͶÁϱÈÌõ¼þÏ£¬¼ìÑéFe3O4ÊÇ·ñ³ÁµíÍêÈ«µÄʵÑé²Ù×÷ÊÇ_________________________¡£

(3)ÂÌ·¯(FeSO4¡¤7H2O)ÊÇÖÎÁÆȱÌúÐÔƶѪҩƷµÄÖØÒª³É·Ö¡£²â¶¨ÂÌ·¯²úÆ·ÖÐFeSO4¡¤7H2Oº¬Á¿µÄ·½·¨ÈçÏ£º

a£®³ÆÈ¡3.0 gÂÌ·¯²úÆ·£¬ÅäÖƳÉ250.00 mLÈÜÒº£»

b£®Á¿È¡25.00 mL aÖÐÈÜÒºÓÚ׶ÐÎÆ¿ÖУ»

c£®ÓÃ0.01000 mol¡¤L£­1ËáÐÔKMnO4ÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄKMnO4ÈÜÒºµÄƽ¾ùÌå»ýΪ20.00 mL¡£µÎ¶¨Ê±·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ5Fe2£«£«MnO4£­£«8H£«===5Fe3£«£«Mn2£«£«4H2O¡£

¢ÙµÎ¶¨ÖÕµãµÄÏÖÏóÊÇ_______________________________________________________________________¡£

¢Ú²úÆ·ÖÐFeSO4¡¤7H2OµÄÖÊÁ¿·ÖÊýΪ________(СÊýµãºó±£Áô1λÊý×Ö)¡£

¢ÛÈôÓÃÉÏÊö·½·¨²â¶¨µÄÑùÆ·ÖÐFeSO4¡¤7H2OµÄÖÊÁ¿·ÖÊýÆ«µÍ(²â¶¨¹ý³ÌÖвúÉúµÄÎó²î¿ÉºöÂÔ)£¬¿ÉÄܵÄÔ­ÒòÓÐ________________________________________________________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø