ÌâÄ¿ÄÚÈÝ

100.0 gÎÞË®ÇâÑõ»¯¼ØÈÜÓÚ100.0 gË®¡£ÔÚT¶Èϵç½â¸ÃÈÜÒº£¬µçÁ÷Ç¿¶ÈI£½6.00 A£¬µç½âʱ¼ä10.00 h¡£µç½â½áÊøζÈÖØе÷ÖÁT£¬·ÖÀëÎö³öµÄKOH•2H2O¾§Ìåºó£¬²âµÃÊ£ÓàÈÜÒºµÄ×ÜÖÊÁ¿Îª164.8 g¡£ÒÑÖª²»Í¬Î¶ÈÏÂÿ100 gÇâÑõ»¯¼Ø±¥ºÍÈÜÒºÖÐÎÞË®ÇâÑõ»¯¼ØµÄÖÊÁ¿Îª£º

ζÈ/¡æ

0

10

20

30

KOH/g

49.2

50.8

52.8

55.8

ÿĦµç×ӵĵçÁ¿Îª9.65¡Á104 C.mol-1¡£

Ç󣺣¨1£©TζÈʱÎö³ö¾§ÌåKOH•2H2OµÄÖÊÁ¿¡£

£¨2£©Îö³ö¾§ÌåʱµÄζȷ¶Î§¡£

 

´ð°¸£º
½âÎö£º

£¨1£©15.1 g      £¨2£©20¡æ¡«30¡æÖ®¼ä

 


Ìáʾ£º

£¨1£©µç½âˮתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª£½2.24 mol£¬

±»µç½âµÄË®µÄÖÊÁ¿Îª£º36 g¡Á£½20.1 g£¬

Îö³öKOH•2H2OµÄÖÊÁ¿Îª£º100 g+100 g-164.8 g-20.1g£½15.1 g

£¨2£©15.1 g KOH•Öк¬KOHÖÊÁ¿Îª£º15.1 g¡Á£½9.2 g

¦Ø(KOH)£½¡Á100%£½55.1%£¬²éÌâÖбíºó¿ÉµÃ52.8%£¼55.1%£¼55.8%£¬¹ÊÎö³ö¾§ÌåµÄζȷ¶Î§ÔÚ20¡æ¡«30¡æÖ®¼ä¡£

 


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø