ÌâÄ¿ÄÚÈÝ

Na2SµÄË®ÈÜҺϴ»¼´¦¿ÉÒÔÓÃÀ´ÖÎÁÆÓÉÒ»ÖÖС½æ³æÔÚƤ·ôÄÚÉú»îÒýÆðµÄƤ·ô²¡£¬¶øÇÒÓÃÈÈË®ÅäÖƵÄNa2SÈÜÒºÖÎÁÆЧ¹û¸üºÃ£®Çë˵Ã÷Ô­Òò£¬²¢Ð´³öÓйصÄÀë×Ó·½³Ìʽ£®£¨ÒÑÖª£ºH2SÓж¾£¬¿Éɱ³æ£©
£¨1£©¿ÉÖÎÁƵÄÔ­Òò
ÒòΪNa2SË®½âÉú³ÉµÄH2SÓж¾£¬¿Éɱ³æ£»
ÒòΪNa2SË®½âÉú³ÉµÄH2SÓж¾£¬¿Éɱ³æ£»

£¨2£©ÈÈË®ÅäÖƵÄÔ­Òò
Ë®½âÊÇÎüÈÈ·´Ó¦£¬ÈÈË®ÈܽâNa2Sʱ´ÙʹƽºâÓÒÒƶ¯£¬Ôö´óH2SµÄŨ¶È£®
Ë®½âÊÇÎüÈÈ·´Ó¦£¬ÈÈË®ÈܽâNa2Sʱ´ÙʹƽºâÓÒÒƶ¯£¬Ôö´óH2SµÄŨ¶È£®

£¨3£©Àë×Ó·½³Ìʽ
Na2S+H2O?NaHS+NaOH£¬NaHS+H2O?NaOH+H2S
Na2S+H2O?NaHS+NaOH£¬NaHS+H2O?NaOH+H2S
£®
·ÖÎö£ºNa2SΪǿ¼îÈõËáÑΣ¬Ë®½â³Ê¼îÐÔ£¬Ë®½â¹ý³ÌΪÎüÈÈ·´Ó¦£¬¼ÓÈÈ¿É´Ù½øË®½â£¬Ë®½â¿ÉÉú³ÉH2SÓж¾£¬¿Éɱ³æ£®
½â´ð£º½â£º£¨1£©Na2SΪǿ¼îÈõËáÑΣ¬Ë®½âÉú³ÉNaOHºÍH2S£¬H2SÓж¾£¬¿Éɱ³æ£¬
¹Ê´ð°¸Îª£ºÒòΪNa2SË®½âÉú³ÉµÄH2SÓж¾£¬¿Éɱ³æ£»
£¨2£©Ë®½â¹ý³ÌΪÎüÈÈ·´Ó¦£¬¼ÓÈÈ¿É´Ù½øË®½â£¬Ê¹Æ½ºâÏòÉú³ÉH2SµÄ·½ÏòÒƶ¯£¬Ôö´óH2SŨ¶È£¬
¹Ê´ð°¸Îª£ºË®½âÊÇÎüÈÈ·´Ó¦£¬ÈÈË®ÈܽâNa2Sʱ´ÙʹƽºâÓÒÒƶ¯£¬Ôö´óH2SµÄŨ¶È£»
£¨3£©Na2SΪǿ¼îÈõËáÑΣ¬·ÖÁ½²½Ë®½âÆäÖÐÒÔµÚÒ»²½Ë®½âΪÖ÷£¬Àë×Ó·½³ÌʽΪNa2S+H2O?NaHS+NaOH£¬NaHS+H2O?NaOH+H2S£¬
¹Ê´ð°¸Îª£ºNa2S+H2O?NaHS+NaOH£¬NaHS+H2O?NaOH+H2S£®
µãÆÀ£º±¾Ì⿼²éÑÎÀàË®½âµÄÓ¦Óã¬ÌâÄ¿ÄѶȲ»´ó£¬±¾Ìâ×¢Òâ°ÑÎÕÓ°ÏìÑÎÀàË®½âµÄÒòËØ£¬Îª¸ÃÌâµÄÖ÷Òª¿¼²éµã£¬×¢Òâ°ÑÎÕÑÎÀàË®½âµÄÔ­Àí£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø