ÌâÄ¿ÄÚÈÝ

ʵÑéÌ⣺ÏÖÓÐÒ©Æ·£ºW g(W<1)пƬ¡¢Ï¡ÁòËá¡¢ÎÞË®ÁòËáÍ­¡¢Ñõ»¯Í­ºÍË®¡£Çë´ÓͼÖÐÑ¡ÓÃÊʵ±µÄʵÑé×°Öã¬Éè¼ÆÒ»¸ö¼òµ¥µÄʵÑ飬´ÖÂԲⶨпµÄÏà¶ÔÔ­×ÓÖÊÁ¿£¨¼ÙÉè»·¾³Îª±ê×¼×´¿ö£©¡£

£¨1£©Ó¦Ñ¡ÓõÄ×°ÖÃÊÇ£¨Ö»ÒªÇóд³öͼÖÐ×°ÖõıêºÅ£©                                 ¡£
£¨2£©ËùÓÃ×°ÖõÄÁ¬½Ó˳ÐòÊÇ£¨Ìî¸÷½Ó¿ÚµÄ×Öĸ£¬½º¹ÜÊ¡ÂÔ£©                        ¡£
£¨3£©ÎªÁ˱£Ö¤²»Â©³öÇâÆø£¬²Ù×÷ÖмӷÅÊÔ¼ÁµÄ·½·¨ÊÇ                           ¡£
£¨4£©ÓÃʵÑéËù²âµÃµÄÊý¾Ý£¬Ð´³ö¼ÆËãпµÄÏà¶ÔÔ­×ÓÖÊÁ¿µÄÊýѧʽ£ºMr(Zn)=        ¡£
£¨1£©¢Û¢Ü¢Þ
£¨2£©J½Ó F E½Ó I
£¨3£©ÏòÊÔ¹ÜÖмÓÈë×ãÁ¿Ï¡ÁòËáºó£¬½«ÊÔ¹Üб·Å£¬ÔÙ°ÑпƬ·ÅÔÚÊÔ¹ÜÄÚ±ÚÉÏ£¬Èû½ôÈû×Ó£¬ÂýÂýÖ±Á¢£¬Ê¹Ð¿»¬Ï£¬ÓëÏ¡ÁòËá½Ó´¥¡£
£¨4£©22.4W/V(H2)
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨16·Ö£©Îª²â¶¨Ì¼Ëá¸Æ´¿¶È£¨É躬ÔÓÖÊSiO2£©£¬Ñ§ÉúÉè¼ÆÁËÈçϼ¸¸öʵÑé·½°¸¡£Çë»Ø´ðÿ¸ö·½°¸ÖÐÌá³öµÄÎÊÌâ¡£
¡¾·½°¸I¡¿
£¨1£©³Æȡ̼Ëá¸ÆÑùÆ·M g£»
£¨2£©¼ÓÈë¹ýÁ¿ÑÎË᣻
£¨3£©ÊÕ¼¯²¢²â¶¨Éú³ÉµÄÆøÌåÌå»ýV mL¡£
ÎÊÌâ1£º·´Ó¦½áÊøºó£¬Á¿Æø¹ÜÖеÄÏÔʾÈçÓÒͼËùʾ£¬½ÓÏÂÀ´µÄ²Ù×÷ÊÇ£º                                   £¬¶Á³ö¼×¹ÜÖÐÒºÃæµÄ¶ÁÊý¡£

¡¾·½°¸II¡¿
£¨1£©³Æȡ̼Ëá¸ÆÑùÆ·M g£»
£¨2£©ÓÃc mol/L ÑÎËáV mL£¨¹ýÁ¿£©ÈܽâÑùÆ·£»
£¨3£©È¡ÈܽâºóµÄÈÜÒºmL£¬ÒÔ·Ó̪×÷ָʾ¼Á£¬ÓÃc¡ä mol/L NaOHÈÜÒºµÎ¶¨£¬Ç¡ºÃÓÃÈ¥V¡ämL¡£
ÎÊÌâ2£ºÁгö±¾ÊµÑéÖÐËùÓõ½µÄÖ÷ÒªÒÇÆ÷Ãû³Æ(³ýÌú¼Ų̈¼°¸½¼þ¡¢ÉÕ±­Ö®Íâ)                                            ¡£
ÎÊÌâ3£ºÌ¼Ëá¸Æ´¿¶È¼ÆË㹫ʽ                                 ¡£
ÎÊÌâ4£ºµ±Ì¼Ëá¸ÆÈܽâÍêÈ«ºó£¬ÉÙÁ¿Î´ÈܵÄSiO2û¹ýÂËÈ¥£¬½á¹ûµÃµ½Ì¼Ëá¸Æ´¿¶È________   (Æ«´ó¡¢Æ«Ð¡»òÎÞÓ°Ï죩
¡¾·½°¸¢ó¡¿
£¨1£©³Æȡ̼Ëá¸ÆÑùÆ·M g£»
£¨2£©¼ÓÈë×ãÁ¿c mol/LÑÎËáV mLʹ֮ÍêÈ«Èܽ⣻
£¨3£©¹ýÂ˲¢È¡ÂËÒº£»
£¨4£©ÔÚÂËÒºÖмÓÈë¹ýÁ¿c¡ä mol/L Na2CO3ÈÜÒºV¡ämL£»
£¨5£©½«²½Ö裨4£©ÖеijÁµíÂ˳ö¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÖØΪM¡äg¡£
ÎÊÌâ5£º´Ë·½°¸Öв»ÐèÒªµÄÊý¾ÝÊÇ               £¨ÌîÑ¡Ïî±àºÅ£©¡£
A£®c¡¢VB£®c¡ä¡¢ V¡äC£® M¡äD£® M
ÎÊÌâ6£ºÎª¼õÉÙʵÑéÎó²î£¬²½Ö裨3£©¡¢£¨5£©¹ýÂ˺ó¶¼Òª¶Ô³Áµí½øÐÐÏ´µÓ£¬Èç¹û²½Ö裨3£©Î´¾­Ï´µÓ£¬Ôò²â¶¨µÄ̼Ëá¸ÆµÄ´¿¶È½«            £¨Æ«´ó¡¢Æ«Ð¡¡¢ÎÞÓ°Ï죬ÏÂͬ£©£»Èç¹û²½Ö裨5£©Î´¾­Ï´µÓ£¬Ôò²â¶¨µÄ̼Ëá¸Æ´¿¶È½«           ¡£
ÎÊÌâ7£ºÅжϲ½Ö裨4£©ÖÐNa2CO3ÈÜÒºÊÇ·ñ¹ýÁ¿µÄ·½·¨ÊÇ                         ¡£
Ò»°ã²â¶¨ÑùÆ·Öгɷֺ¬Á¿µÄʵÑéÓ¦Öظ´¶þÖÁÈý´Î¡£ÎªÁ˲ⶨijÇâÑõ»¯ÄƹÌÌåÖлìÓеÄ̼ËáÄƵÄÖÊÁ¿·ÖÊý£¬¼×¡¢ÒÒÁ½Î»Í¬Ñ§·Ö±ðÉè¼ÆÁËÈçÏÂʵÑé·½°¸£º
I£®¼×ͬѧµÄ·½°¸ÈçͼËùʾ£º

(1)¸ù¾Ý¼×ͬѧµÄʵÑé×°ÖÃͼ·ÖÎö£¬ÔÚÿ´ÎʵÑé¹ý³ÌÖÐËù½øÐеijÆÁ¿²Ù×÷ÖÁÉÙÒª½øÐР     ´Î¡£
(2)¼×ͬѧÖظ´²â¶¨ÁËÈý´Î£¬µÃµ½Ì¼ËáÄƵÄÖÊÁ¿·Ö
ÊýµÄÊý¾Ý´æÔڽϴóµÄÆ«²î£¬ÄãÈÏΪԭÒò¿ÉÄÜÊÇ            (ÌîÐòºÅ)¡£
A£®×°ÖÃÄÚÔ­ÓпÕÆøÖеĶþÑõ»¯Ì¼ÆøÌåÒ²±»¼îʯ»ÒÎüÊÕ
B£®×°ÖÃÍâ¿ÕÆøÖеÄË®ÕôÆøºÍ¶þÑõ»¯Ì¼±»¼îʯ»ÒÎüÊÕ
C£®·´Ó¦Íê³Éºó£¬×°ÖÃÖеĶþÑõ»¯Ì¼Ã»ÓÐÈ«²¿±»¼îʯ»ÒÎüÊÕ
D£®¼ÓÈëÏ¡ÁòËáµÄÁ¿²»×㣬Ôò¿ÉÄÜÔì³ÉÎó²î
II£®ÒÒͬѧµÄ·½°¸ÊÇ£º³ÆÈ¡ÑùÆ·m g£¬²¢Èܽ⣬¼Ó¹ýÁ¿ÂÈ»¯±µÈÜÒº£¬¹ýÂË¡¢Ï´µÓ¡¢ºæ¸É£¬
³ÆÁ¿µÃ¹ÌÌån g¡£
(1)»ìºÏÎïÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýΪ(ÓÃm¡¢n±íʾ)                  ¡£
(2)Ï´µÓ³ÁµíµÄ²Ù×÷ÒªµãÊÇ                        ¡£
(3)Ca2+¡¢Ba2+¶¼¿ÉÒÔʹCO32-³ÁµíÍêÈ«£¬µ«ÒÒͬѧʹÓÃÂÈ»¯±µÈÜÒº¶ø²»ÓÃÂÈ»¯¸ÆÈÜÒºµÄÔ­ÒòÊÇ              £»²â¶¨CO32-µÄÁ¿£¬ÈôʹÓÃÇâÑõ»¯±µÈÜÒº¶ø²»ÓÃÇâÑõ»¯¸ÆÈÜÒº£¬½á¹û½«¾ßÓиü¸ßµÄ¾«È·¶È£¬Ô­ÒòÊÇ                         ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø